similar to: list factoring

Hello can anyone help please? i read two words "cell1", "cell2" into a list. I want to turn this list into a factor. > cell_data <-list(c('cell1','cell2')) > cell_data [[1]] [1] "cell1" "cell2" > factor_list <- factor(cell_data) Error in sort.list(y) : 'x' must be atomic for 'sort.list' Have you called

Hi all, I attached a driver for MiniBox openUPS device ( http://www.mini-box.com/OpenUPS) and a dump of the hid usages. I had the possibility to make a few adjustments to the device firmware for HID usages, and although I haven't managed to produce a good structure many issues from previous firmware were at least fixed and new information added. ATM the driver only shows pertaining

This is an example from chapter 11 of the 6th edition of Devore's engineering statistics text. It happens to be a balanced data set in two factors but the calculations will also work for unbalanced data. I create a factor called 'cell' from the text representation of the Variety level and the Density level using '/' as the separator character. The coefficients for the linear

Hello R-users, I apologize for my question but I'm a newbie. I want to read a file which columns separator is "\t". At the end of each row there is a "\n" to go to the following line. The three first lines are remarks lines and the fourth contains columns titles ( variables names, ids, dates, calculated values, observed values...) . I do: read.table("myFile",

I wrote a procedure to create a spreadsheet using rdcomclient. It uses a function to do the writing and runs "correctly" in isolation. It gives errors, but it continues to completion. The error I receive is "Error: Member not found". If I place it inside a for loop the loop fails after the first iteration, once it reaches the error. Has anyone had experience with this

I have a data frame containing the results of time measurements taken from several cells. Each cell was measured in conditions A and B, and there are an arbitrary number of measurements in each condition. I am trying to calculate the difference of each measurement from the mean of a given cell in a given condition without relying on loops. >my.df id cond time 1

Okay I got ther error below in figure-1, so I added an end then I got figure-2 figure-1 expecting tCOLON2 or ''['' or ''.'' figure-2 unexpected '';'', expecting tCOLON2 or ''['' or ''.'' end ; _erbout -- Posted via http://www.ruby-forum.com/.

Hello dear R people, for my MSc thesis I need to program some functions, and some of them simply do not work. In the following example, I made sure both vectors have the same length (10), but R gives me the following error: Error in if (vector1[i] == vector2[j]) { : missing value where TRUE/FALSE needed I googled for possible solutions, but I did not find a good explanation for this...

Hi We are using postgresql with rails, we find out that when we read array from postresql (postgresql support array type in table) the rails (or postgresql_adapter) converts the arrays into Strings, example: we have a data type array in a table which has two cells: [cell1,cell2], rails will convert them into string like this {cell1,cell2}. So after received the result from a SQL request we have

Hi, I have a question about heatmap. I have a data with row as microRNA and two columns are two cell expression values for these microRNA. So, like: cell1 cell2 miRNA1 1.5 3.4 miRNA2 1.3 2.4 ................... miRNA50 5 2.1 miRNA51 7.3 0.5 I want to see some miRNA are high in cell1 and low in cell2 but others are low in cell1 and high in cell2. I

Dear all, I was encountering with a typical Matching problem and was wondering whether R can help me to solve it directly. Let say, I have 2 vectors of equal length: vector1 <- LETTERS[1:6] vector2 <- letters[1:6] Now I need to match these 2 vectors with all possible ways like: (A,B,C,D,E) & (a,b,c,d,e) is 1 match. Another match can be (A,B,C,D,E) & (b,a,c,d,e), however there

Hi All, I am counting the number of occurrences of the terms listed in one vector in another vector. My code runs: for( i in 1:length(vector3)){ vector3[i] = sum(1*is.element(vector2, vector1[i])) } where vector1 = vector containing the terms whose occurrences I want to count vector2 = made up of a number of repetitions of all the elements of vector1 vector3 = a vector of NAs that is

Dear all. I wanted to read in a 20,000 row X 60 column matrix (called "table") into R. i did this: >R >table <- read.table("table", header=TRUE) >table it prints out the start of my table (~10000 rows by 7 columns) and then this error: [ reached getOption("max.print") -- omitted 5465 rows ]] There were 50 or more warnings (use warnings() to see the

Looking for help with the following problem. Given a sample of zeros and ones, for example: > VECTOR1<-rep(c(1,0),c(15,10)) > VECTOR1 [1] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 How would I create a new sample (VECTOR2) also containing zeros and ones, in which the phi-coefficient between the two sample vectors was drawn from a population with a known

Hi I'm trying to Passthrough a GPU to a VM and have it still share its free memory with the host (just like it would with virtio-balloon). Is this something virtio-mem is capable of? I've tried to run it, but it immediately took over 9GB of memory: virt-install --name test --cpu cell0.cpus=0,cell0.memory=4194304,cell1.cpus=1,cell1.memory=4194304 --memory

hi is there a faster way to do this? i <- 1 for(x in vector1) for(y in vector2) { m[[i]] <- (x - y) i <- i + 1 } regards soren -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in

Hi, I have many files containing one column of data. I like to use the scan function to parse the data. Next I like to bind to a large vector. I try this like: count<-1 files <- list.files() # all files in the working directory for(i in files) { tmp <- scan(i) assign(files[count], tmp) count<-count+1 } This part works! Now I like to plot the data in a boxplot.

Here are another three problems with logarithmic scales: 1) segments() does not work with logarithmic scales. I suggest to change lines 962-973 in "plot.c": for (i = 0; i < n; i++) { if (FINITE(xt(x0[i%nx0])) && FINITE(yt(y0[i%ny0])) && FINITE(xt(x1[i%nx1])) && FINITE(yt(y1[i%ny1]))) { GP->col = INTEGER(col)[i % ncol];

Hi All, I am trying to match two character arrays (email lists) using either pmatch(), match() or charmatch() functions. However the function is "missing" some matches due to differences in the cases of some letters between the two arrays. Is there any way to disable case sensitivity or is there an entirely better way to match two character arrays that have identical entries but written

Dear Statisticians--- This is not even an R question, so please forgive me. I have so much ignorance in this matter that I do not know where to begin. I hope someone can point me to documentation and/or a sample. I want to compute a covariance as quickly as non-humanly possible on an Intel core processor (up to SSE4) under linux. Alas, I have no idea how to engage CPU vectorization. Do I need