similar to: Moving average with loess

Dear R-community, maybe someone can help me with this: I've been using the loess() smoother for quite a while now, and for the matter of documentation I'd like to resolve the acronym LOESS. Unfortunately there's no explanation in the help file, and I didn't get anything convincing from google either. I know that the predecessor LOWESS stands for "Locally Weighted

Hi Folks, I'm looking to do Confidence bands around LOESS smoothing curve. If found the older post about using the Standard error to approximate it https://stat.ethz.ch/pipermail/r-help/2008-August/170011.html Also found this one http://www.r-bloggers.com/sab-r-metrics-basics-of-loess-regression/ But they both seem to be approximations of confidence intervals and I was wonder if there was

Hi all, I 've got a question about the usage of loess in the modreg package. The documentation (loess.html) states that the smoothing window is either set by span or enp.target. If span is used, the details section of the docs state... <SNIP> DETAILS Fitting is done locally. That is, for the fit at point x, the fit is made using points in a neighbourhood of x, weighted by their

Hi all, I 've got a question about the usage of loess in the modreg package. The documentation (loess.html) states that the smoothing window is either set by span or enp.target. If span is used, the details section of the docs state... <SNIP> DETAILS Fitting is done locally. That is, for the fit at point x, the fit is made using points in a neighbourhood of x, weighted by their

Hello, I need help with the details of loess prediction algorithm. I would like to get it implemented as a part of a measurement system programmed in LabView. My job is provide a detailed description of the algorithm. This is a simple one-dimensional problem - smoothing an (x, y) data set. I found quite a detailed description of the fitting procedure in the "white book". It is also

Hi, Round(0.55,1)=0.5 Round(2.55,1)=2.6 Can this be right? Thanks, Ed [[alternative HTML version deleted]]

Sorry, maybe it's easy but I haven't found anything useful: how can I obtain a list C that contains all the members in the list B that are not in list A? This are lists of nanes, not numbers! Thank you Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of Genova, Genova, Italy Guest Researcher, LMP, NCI, NIH, Bethesda MD Work: 301-451-8575

Hi how can I find, in a vector of characters, which is the most frequent one? Thanks Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of Genova, Genova, Italy Guest Researcher, LMP, NCI, NIH, Bethesda MD Work: 301-451-8575 Mobile: 301-204-5642 Email: zoppolig at mail.nih.gov

Hello Is there any R package which can do 3-D splines (reconstruct a surface based 3-D data input) ? Thanks, Zhaoming

Dear r-help mailing list, this seems stupid, but I actually don't find the solution: if I have a vector of numbers x of length n, ranging, say, from -3 to 4, if I do barplot (x) all the values below 0 go downwards, and all the positive values go upward. How can I make them all begin from the minimum pointing upwards? Thanks! Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical

Hi, I want to generate a number of vectors and store them with different names, like this: x=1 while (x<100) { vector#x# = rnorm(100) x=x+1 } where each vector has, at its hand, instead of #x# a number which goes from 1 to 99. How can I do this? Thanks Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of Genova, Genova, Italy Guest

Please give me just a reference where I can find something useful. In summary, I need to : - find the median of each row of a matrix - create a new matrix with each value in the first matrix divided by the median of its row - if a value "a" in the second matrix is < 1, I need to substitute it with 1/a I know that for some of you it must be overeasy, but I swear I googled for two

Because functions get called and therefore, the calling sequence matters. It?s just protecting you from yourself, but as someone pointed out, there?s a way to silence such notes. G From: Herv? Pag?s <hpages.on.github at gmail.com> Sent: Tuesday, February 6, 2024 2:40 PM To: Izmirlian, Grant (NIH/NCI) [E] <izmirlig at mail.nih.gov>; Duncan Murdoch <murdoch.duncan at gmail.com>;

Hi all, if I transpose a matrix with t(data), the newly created colums do not appear to have the first row as header. How can I do to have all the newly created columns have their first row as a header? Thanks Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of Genova, Genova, Italy Guest Researcher, LMP, NCI, NIH, Bethesda MD Work: 301-451-8575

Here's a dummy example that I think illustrates the problem: toto <- function() { if (runif(1) < 0.5) function(a) a else function(a,b) a+b } > fcn <- toto() > fcn(1,2) [1] 3 > fcn <- toto() > fcn(1,2) [1] 3 > fcn <- toto() > fcn(1,2) Error in fcn(1, 2) : unused argument (2) How can you use the returned function, if you get different arguments?

Thanks. Workarounds are interesting but... what's the point of the NOTE in the first place? H. On 2/4/24 09:07, Duncan Murdoch wrote: > On 04/02/2024 10:55 a.m., Izmirlian, Grant (NIH/NCI) [E] via R-devel > wrote: >> Well you can see that yeast is exactly weekday you have.? The way out >> is to just not name the result > > I think something happened to your

Hello, In reading the loess description I see: span: the parameter alpha which controls the degree of smoothing. The default seems to be 0.75. Would it be possible to expand on this decription so I can avoid trail and error? Can I increase this pass 'span' > 1? Qualitatively to what degree changing this value affects the smoothing of the data? Thank you. Kevin

I am creating a package, and a rather long usage line for one function becomes truncated in the generated .pdf manual. Is there a way that I can prevent that truncation?

Hello Masters, I run the loess() function to obtain local weighted regressions, given lowess() can't handle NAs, but I don't improve significantly my situation......, actually loess() performance leave me much puzzled.... I attach my easy experiment below #------SCRIPT---------------------------------------------- #I explore the functionalities of lowess() & loess() #because I have

I am trying to upload into R 143 Affymetrix chips onto using R on the NIH Nimbus server. I can load 10 chips without a problem, however, when I try to load 143 I receive a error message: cannot create a vector of 523263 KB. I have expanded the memory of R as follows: R --min-vsize=10M --max-vsize=2500M --min-nsize=10M -max-nsize=50M (as specified in help in R). After running this command the