similar to: legend

Dear community, I've plotted data and coloured depending on the factor variable v3. In the legend, I'd like to assign properly the same colors than in the factor (the factor has 5 levels). I've been trying this but it doesn't work. plot(var1, var2, xlab = "var1", ylab = "var2", col =var3 , bty='L') legend(locator(1),c("level 1 var3",

Hello everybody, Is it possible to coax legend() into displaying more than one simbol per line in legend? I have a graph like the one attached to this mail; I would like to reorganize the legend in such a way that the duplicate text would be omitted, i.e., the first line would read <square> <triangledown> "increasing frequency" and the second one would read <circle>

Hi there, I draw a multiple figure in one plot, like the following: par(mfcol=c(1,5),mar=c(4,4,0,0)+0.2, oma=c(0,0,3,0)) plot(1:10, type = "b") plot(1:10, type = "b") plot(1:10, type = "b") plot(1:10, type = "b") plot(1:10, type = "b") Now, I hope to plot the legend like the following: legend("top", legend=c("Example"), pch

Dear R Users, I'm able to display a legend using the following code: > legend("topright", c("Simulation", "Observation"), fill=2:3, bty="n") However, this causes the legend to be positioned too close to the bars in my barplot. I'd like to move the legend up slightly. I have been trying to determine the necessary values by trial and error to do

Hi, This is a simple problem, but for the life of me I cannot find the answer. How to determine frequency within given ranges ? I know that table() gives frequency, for example a <- table(numbers) > a numbers 4 5 23 34 43 54 56 65 67 324 435 453 456 567 657 2 1 2 2 1 1 2 1 2 1 3 1 1 1 1 > as.data.frame(table(numbers)) numbers

Hi, I am not sure how to fix the following error. LGD <- c(11.6, 12.3, 15.8, 33.1, 43.5, 51.3, 67.3, 84.9) cor (x=(file [1:47231,3:10]), y= rep (LGD, 47231), method = "pearson") Error in cor(x = (file[1:47231, 3:10]), y = rep(LGD, 47231), method = "pearson") : incompatible dimensions > sessionInfo() R version 2.13.0 (2011-04-13)

Hi, I'll coded your example into R code: Table_A <- c('abc at gmail.com', 'John Chan', '0909') Table_A <- rbind(Table_A, c('bcd at yahoo.com', 'Tim Ma', '89089')) colnames(Table_A) <- c('Email', 'Name', 'Phone') Table_A Table_B <- c('abc at gmail.com', 'John Chan', 'M',

Hi all, I wish to merge 24 .csv files, each having a common identifier-column ("Name") and do two things: 1. Retrieve the common one's. [Analogy: while merging 2-dataframes, similar to using: merge (.... ,by="Name", all=FALSE) ] 2. Retrieve all, i.e., the union of the rows of 24 files. [again, somthing like: merge (.... ,by="Name", all=TRUE) ] On the web,

Hi, I have got two groups of samples; and for every row, I wish to calculate Kruskal-Wallis' p-value. In the example below, and the stars (****) show where I am struggling to design and put things together. Any help would be appreciated. myFile <- data.frame(Sample_1a = 1:10, Sample_1b = 2:11, Sample_1c = 3:12, Sample_2a=4:13, Sample_2b=7:16, row.names=LETTERS[1:10]) groups <- rep

Thanks - Peter, Eivind, Rui Sorry, I perhaps could not explain it properly in the first go. Trying to simplify it here with an example - Say I have two dataframes as below that are NOT equally-sized data frames (i.e., number of columns are different in each table): Table_A: Email Name Phone abc at gmail.com John Chan 0909 bcd at yahoo.com Tim Ma

Hello, I need to change the font for one of the items (C. elegans) in my legend to italic. Can someone suggest how to accomplish this? legend('bottomright', bty='n', c('C. elegans range', 'Study area'), cex=0.8, fill=c('light gray', 'white'), border=c('black','black')) I tried using lab.font=c(1,3) but R ignored and did not write

I could not find a way to specify the border color of the boxes drawn in a legend, so that the legend can match exactly the colors of the actual plot (e.g. in the case of two superimposed histograms which have different shading and different borders). Indeed, the legend function seems to hard code the color "black" for the borders in this call: rect2(left = xt, top = yt +

Hi, I wonder why my attempt to extend an existing loess fit to a new data set is producing error. I was trying the following: dat = read.csv(choose.files()) x = dat[,2]; y = dat[,1] x.sort = sort(x) y.loess = loess(y~x, span=0.75) # For testing the above fit with a new dataset: test = read.csv(choose.files()) # test data new_x = test [,1]; new_y = test[,2] new_x.sort = sort(new_x) predicted

Hi, I have two dataframes (Dataframe_A, Dataframe_B) with the same no. of columns. The first column of both the dataframes contains unique names. I wish to have Dataframe_A with the rows that are NOT common to Dataframe_B. With merge (), it is possible to get the common rows or to merge rows, but I am not quite sure how to do it in a simpler way. Any help would be much appreciated. Thank you.

Hi, I understand that to test the significance of correlation between two PAIRED variables, the function, cor.test () can be used. However, in my case, I have tested the correlation (i.e., Correlation Coefficient, r) between two independent (i.e, different) variables, and now I wish to test for the statistical significance of the correlation. Could you please suggest how I should do that. Thank

Dear all, maybe I have misunderstood something but to me it seems like a minor error in the help for ?legend for the argument 'bg'. There it says: bg: the background color for the legend box. (Note that this is only used if 'bty = "n"'.) I think, however, that it should be changed to: bg: the background color for the legend box. (Note that this

Hi, I have a graph and I would like to write some values inside the legend that were saved in a variable. Please revise the code below in which I've wrote 2 different legends, but I am not happy with either of them. What I want is a legend with tile "Legend" and underneath a line with a name and a value like that: value = 2. #Code begin: # ------------------- a = 2 # result of a

Hi, I seem to be unable to get a mixed legend that has lines *or* polygons (not both). For example: ppi <- seq(0,2*pi,length.out=21)[-21] frame() plot.window(ylim=c(-5,5),xlim=c(-5,5),asp=1) polygon(cos(ppi)*4+rnorm(20,sd=.2),sin(ppi)*4+rnorm(20,sd=.2), col="green",border=FALSE) polygon(cos(ppi)*2+rnorm(20,sd=.1),sin(ppi)*2+rnorm(20,sd=.1), col="blue",border=FALSE)

I have following syntax for putting a legend : legend("bottom", fill=c("red","blue"), legend=expression(p==0.30, p==0.50), bty="n") However what I want is that : the value "0.30" should be a value of a variable instead of a constant, so that I can put the name of this variable and in legend it's value will be displayed. Can anyone tell me how

Hi, I've looked at the parameters available for the legend function and cannot find a way to change the distance between the top of the box surrounding a legend and the legend's title. I have a math expression that raises the height of my title. If you don't mind the non-sensical title I give to the legend for this plot (Figure 3.20 in R Graphics): with(iris,