similar to: Add number series to data frame

Hello, consider the following data.frame df and vector v df <- data.frame(group = c("A","B","C","D"), value = c(1,2,3,4)) v <- c(2,3) How can I return a sub data.frame which has only the rows left where value matches v df: group value B 2 C 3 Cheers -- View this message in context:

Hello! I have a data.frame which looks like: Name - Value A - 400 A - 300 B - 200 B - 350 C - 500 C - 350 D - 450 D - 600 E - 700 E - 750 F - 630 F - 650 I want to add another column where all A,B should get an index 1, all C,D an index of 2 and all E,F an index of 3 so that the data.frame looks like: ID - Name - Value 1 - A - 400 1 - A - 300 1 - B - 200 1 - B - 350 2 - C - 500 2 - C - 350 2

Hello, I am struggling with detecting successive digits in a numerical series vector. Here is an example: vec <- c(1, 15, 26, 29, 30, 31, 37, 40, 41) I want to be able to detect 29, 30, 31 and 40, 41. Then, I would like to delete the successive digits from the vector. 1, 15, 26, 29, 37, 40 Cheers -- View this message in context:

Hello! If I have a vector vec <- c(FALSE, FALSE, TRUE, FALSE, TRUE, TRUE, FALSE FALSE) I can I create the following order of numbers based on vector vec: 1, 2, 2, 3, 3, 3, 4, 5 Whenever there is a FALSE I increase the number (starting with 1). Whenever there is a TRUE I set the same number as the previous FALSE has been assigned to. I would be happy for any input Cheers, Syrvn -- View

Hi, I created the following example of a xyplot. The plot actually looks ok apart from that the x-axis is pretty squeezed/clinched. I tried aspect="fill" already but I want to have all 3 sub plots next to each other. I tried loads of different scaling varieties but with no significant result... library(lattice) N <- 6 d <-

Hi, let's assume I have the following vector a: 1 5 23 How can I use R to duplicate the elements so that my new vector looks like: 1 1 5 5 23 23 Many thanks, Syrvn -- View this message in context: http://r.789695.n4.nabble.com/Duplicate-elements-of-a-vector-tp3879561p3879561.html Sent from the R help mailing list archive at Nabble.com.

Hello, can anybody tell me how to produce a plot like the one in http://cran.r-project.org/web/packages/lme4/vignettes/Implementation.pdf on page 13, Figure 6? The data is stored in: library(nlme) data(Oats) Cheers -- View this message in context: http://r.789695.n4.nabble.com/Help-needed-in-reproducing-a-plot-tp4119603p4119603.html Sent from the R help mailing list archive at

Hi, imagine the following matrix/data.frame Letter Number a 1 a 1 b 1 b 0 c 0 c 1 d 0 d 0 If the numbers for two identical letters are also identical then I want to remove either the first or the second row of that letter. If for a letter the numbers are 1 and 0 I want to remove the row with the 0. That means if the code works I would and up with the following matrix/data.frame Letter

Hello! with the R system command I would like to call a perl script which needs an input directory and an output directory in form of a path. When I put in the path directly it works. The script line looks as follows: system("perl '../path1' '../path2' '../path3'") If I store the path in a variable/object and call the perl script again it does not run and I

Hello, with Sys.time() you get the following string: "2011-11-15 16:25:55 GMT" How can I extract the following substrings: year <- 2011 month <- 11 day_time <- 15_16_25_55 Cheers, Syrvn -- View this message in context: http://r.789695.n4.nabble.com/Extract-pattern-from-string-tp4073432p4073432.html Sent from the R help mailing list archive at Nabble.com.

Hi, the R code: a <- matrix(c(1,5,4,3,7,10,34,4,3,8,6,5,12,17,45,3,2,45,46,47,3,4,22,12,21), nrow=5) rownames(a) <- c("a","b","c","d","e") a a[which(a[,3] < 8), ] a[which(a[,3] < 6), ] produces the following output: > a [,1] [,2] [,3] [,4] [,5] a 1 10 6 3 3 b 5 34 5 2 4 c 4 4 12 45 22 d

Hello, I am working on a big R project using Eclipse/StatET/Texlipse. I'd like to write a Latex document within that project but DO NOT want to Sweave it. It's pure Latex. Via the external tools configurations I set up 2 different versions to ensure that my latex document is processed correctly. Version 1 (System Call): library(tools) setwd("${container_loc}") file =

Hi All, I have a data frame dat1: dat1 <-data.frame(N=seq(1, 12,1), B=c("29_log","29_log", "29_log", "27_cat", "27_cat", "1_log", "1_log", "1_log", "1_log", "1_log",

Hello, I am running Windows 7 and R-2.13 in StatET. When I try to create a directory it does not print any errors but if I check outside eclipse if it exists or do a refresh in Eclipse the directory is not been created. The strange thing is that it happens only to some sub-folders... On the other hand when I use the normal windows explorer in one of these sub-folders and create a folder it

Hi Sarah, Thank you so much!! I got your good ideas. Ding -----Original Message----- From: Sarah Goslee [mailto:sarah.goslee at gmail.com] Sent: Friday, May 11, 2018 11:40 AM To: Ding, Yuan Chun Cc: r-help mailing list Subject: Re: [R] add one variable to a data frame [Attention: This email came from an external source. Do not open attachments or click on links from unknown senders or

Hello, since 3 days now I try to get pgfSweave running using Eclipse + StatET. I created a super simple .Rnw file which can be viewed here: http://www.text-upload.com/read.php?id=147992&c=6441045 test.Rnw When I use sweave it works perfectly fine but when I use pgfSweave I get an error. The R output can be viewed here: http://www.text-upload.com/read.php?id=147995&c=3804886 R output

Hi, Here's one way to approach it, using the coercion of factor to numeric. Note that I changed your data.frame() statement to avoid coercing strings to factors, just to make it simpler to set the levels. dat1 <-data.frame(N=seq(1, 12,1), B=c("29_log","29_log", "29_log", "27_cat", "27_cat", "1_log", "1_log",

Hello, when I use list.files with recursive = TRUE and all.files = TRUE, R returns a list of strings/paths. >From all those strings I want to keep only the ones starting with a . I tried using grep to achieve that. However, the problem is that because of the recursive list.files parameter, for some files beginning with a . there is a path attached. I think it is not as simple as it looks

Hi, how can I produce random data which lies around a straight line with angle 45 degree. Similar to this image: http://zoonek2.free.fr/UNIX/48_R/g134.png Cheers -- View this message in context: http://old.nabble.com/Random-data-tp26513822p26513822.html Sent from the R help mailing list archive at Nabble.com.

Sarah's solutions are good, and here's another, even more basic: tmp1 <- unique(dat1$B) tmp2 <- seq_along(tmp1) dat1$C <- tmp2[ match( dat1$B, tmp1) ] > dat1 N B C 1 1 29_log 1 2 2 29_log 1 3 3 29_log 1 4 4 27_cat 2 5 5 27_cat 2 6 6 1_log 3 7 7 1_log 3 8 8 1_log 3 9 9 1_log 3 10 10 1_log 3 11 11 3_cat 4 12 12 3_cat 4 As a single line