similar to: PLS Error message

Hi, I have a question about understanding PLS. If I use the predict function of R than it seems to me the function only uses the last latent variable to model new Y values. But should the function not use all latent variables to model new Y?s? Thank you very much for your help. /Thomas -- *^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^* Thomas M?ckel, PhD student Department of Earth and

Here I think S3 dispatch is very natural. Try the following: page <- function(x, method = c("dput", "print"), ...) UseMethod("page") page.getAnywhere <- function(x, ..., idx=NULL) { name <- x$name; objects <- x$obj; if (length(objects) == 0) stop("no object named '", name, "' was found"); if (is.null(idx)) {

Hi, forget about the below details. It is not related to the fact that the function is returned from a function. Sorry about that. I've been troubleshooting soo much I've been shoting over the target. Here is a much smaller reproducible example: x <- 1:10 y <- 1:10 + rnorm(length(x)) sp <- smooth.spline(x=x, y=y) ypred <- predict(sp$fit, x) # [1] 2.325181 2.756166 ...

Hi, I'm Pina and I'm a student in geology. I'm working with spectral profile of sand and I have to find the similarity between one spectral profile selected by hyperspectral image anche one that I created to mix different percentage of 4 mineral component. I have to find the best mix of percentage of this 4 mineral in order to have the best likeness with the spectral profile chose by

(moved from R-help) I tried this on Ubuntu with R-2.14.1 built from source, and I do not get the segfault problem. (I don't at the moment have a debian binary R, or I would confirm whether I get the segfault problem.) My sessioninfo() is reporting additional information about namespace imports: > library(ggplot2) Loading required package: reshape Loading required package: plyr

Hi, I've been using "nlregb" routine in splus3.4, but cannot find it here in R. Is it hidden in some library? Or there is a routine equivalent to it but with a different name? I'm planning to move part of my from S to R so that I can work comfortablely at home. Any suggestion is highly appreciated. regards, Tony -- \|||/ Q o o Q ==========================oooQ= ( -

I can't run fix() or edit() anymore. Did I break my system? I'm running Debian Linux with R-2.14.1. As far as I can tell, the R packages came from Debian's testing "wheezy" repository. I would like to know if users on other types of systems see the same problem. If no, then, obviously, it is a Debian-only issue and I can approach it from that point of view. And if no other

I have a function that fits polynomial models for the orders in n: lmn <- function(d,n){ models=list() for(i in n){ models[[i]]=lm(y~poly(x,i),data=d) } return(models) } My data is: > d=data.frame(x=1:10,y=runif(10)) So first just do it for a cubic: > mmn = lmn(d,3) > predict(mmn[[3]]) 1 2 3 4 5 6 7 8

Moi! A student here has been getting a bit irritated with some side effects of scale() (OS is Windows XP, the behaviour occurs in R 2.0.0, but not 1.7.1). The problem is that she scales a variable in a data frame, then does a regression, and tries to get some predictions for some new data. However, at this point she gets an error (see the example below). This seems to be because the

Hallo, I'll need a matrix with n rows of the an identical vector. > h [1] 3 3 3 3 2 2 2 The nmatrix should look like this: > x<-rbind(h,h,h) > x [,1] [,2] [,3] [,4] [,5] [,6] [,7] h 3 3 3 3 2 2 2 h 3 3 3 3 2 2 2 h 3 3 3 3 2 2 2 but I need n rows which must be variable. Can anyone help me? thanks Andreas

Hi all, I recently wrote some code to store a number of polynomial models in a list and return this list. The model is returned fine, but when I make a subsequent call to predict(), I have an error. The code for polyModel selection is listed at the end of the email. Here is an example of the error: > poly.fit <- polyModelSelection(x,y,10,F) > for (d in 1:4) { + lm.model <-

Dear All, I have a question regarding predict.rpart. I use rpart to build classification and regression trees and I deal with data with relatively large number of input variables (predictors). For example, I build an rpart model like this rpartModel <- rpart(Y ~ X, method="class", minsplit =1, minbucket=nMinBucket,cp=nCp); and get predictors used in building the model like

Dear R users, I have a data where I desire to subset according to certain conditions. However, the script is very messy as there are about 30 distinct conditions. (i.e. same script but with different conditions) I would like to make a user defined function so that I can input the desired conditions and just get the results accordingly. Below is an arbitrary data set & sample statements

I recently attempted to read a .txt file using both read.table(" ",header=TRUE) and read.delim(" ",header=TRUE) and received the following message Error in edit.data.frame(get(subx, envir = parent), ...) : symbol print-name too long I am able to also create a variable x<-read.delim (" ",header=TRUE ) , but am unable to fix(x) because

I am fittling a spline to a variable in a regression model, I am then using the predict.glm funtion to make some predictions. When I use bs to fit the spline I don't have any problems using the predict.glm function however when I use ns I get the following error: Error in model.frame(formula, rownames, variables, varnames, extras, extranames, : variable lengths differ (found for

Hey all, I need some help with a cross validation. I'm new with R and as well with statistics. I had a group work to create a tool for remote sensing class that extracts the best bands of hyperspectral satellite images that describe vegetation. Its a regression between a linear function of using a normalized differenced index (i-j)/(i+j) while i and j are the bands (in the data these are the

I'm relatively new to R .I tried converting the datetime column with values like 01apr1985:00:00:00.000 using strptime(datetime,"%d%b%Y).Could anyone help me in this regard .Please reply ASAP i need . -- View this message in context: http://www.nabble.com/Datetime-conversion-tp25503138p25503138.html Sent from the R help mailing list archive at Nabble.com.

Dear List, I have a list of 600+ *.gz files that I would like to extract and read the geotiffs contained within them. I tried using the untar() function to simplify this task but I am stumped by an error. I've combed the Internet for a solution without luck. The details are below, and any help in solving this matter is appreciated. > files = list.files(path = "J:/GIMMS/NDVI",

Hello, Is this a bug or a feature? I am using R 2.7.1 on Apple OS X. > y <- matrix(1:3,nrow=3) # y is a single-column matrix > df <-data.frame(x=1:3,y=y) > sapply(df,data.class) x y "numeric" "numeric" > df$yy <- y > sapply(df,data.class) x y yy "numeric" "numeric" "matrix"

Below is a SIMEX object that was generated with the "simex" function from the "simex" package applied to a logistic regression fit. From this mountain of information I would like to extract all of the values summarized in this line: .. ..$ variance.jackknife: num [1:5, 1:4] 1.684 1.144 0.85 0.624 0.519 ... Can someone suggest how to go about doing this? I can extract the