Displaying 20 results from an estimated 10000 matches similar to: "Help in matrix"
2012 Nov 26
3
Help in splitting the records
Hi
I have set of records seperated by a separator say "$$$" i want to get the
values in a dataframe.
eq
qwer$$12$$qwre
ewrtr$7789$ewwe
I want the output as\
V1 V2 V3
qwer 12 qwre
ewrtr 7789 ewwwe
Please help me
-----
Thanks in Advance
Arun
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2012 Feb 22
4
Week number from a date
Hi
My data looks like this
startDate="2008-06-01"
dateRange =c( "2008-10-01","2008-12-01")
Is there any method to find the week number from the startDate range
-----
Thanks in Advance
Arun
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2012 Apr 03
2
Histogram classwise
Hi
I have a data class wise. I want to create a histogram class wise without
using for loop as it takes a long time
my data looks like this
x class
27 1
93 3
65 5
1 2
69 5
2 1
92 4
49 5
55 4
46 1
51 3
100 4
-----
Thanks in Advance
Arun
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2012 Jul 17
2
comparing three vectors
Hi
I 've a data
a=c(10,20,30)
b=c(100,200,300)
c=c(50,60,70)
I want to compare a[1]<=c[1]<b[1],......
How to compare for all the records
-----
Thanks in Advance
Arun
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2012 Oct 24
3
Results not dispalying in R console
Hi
I'm not getting any results in R console when i run commands. I reinstalled
R but the results are same
-----
Thanks in Advance
Arun
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2012 Feb 22
3
inserting a dataframe into the table
Hi,
I have a dataset
X Y
A= 10 15
20 30
40 50
B = X Z
10 30
20 50
I have a table containing X Y Z columns
How to insert a data frame into the table without using for loop ?
now currently i'm using the for loop with using the insert command?
-----
Thanks in Advance
Arun
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2012 Jul 03
2
read the date format
hi
I have a data like thursday, November 20,2012. I'm not able to convert
into data format in R
Can anyone please help
-----
Thanks in Advance
Arun
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2012 Apr 24
2
searchina a pattern in a string
I have a long string. i want to sepearate a 10 digit phone no from it.
eg
"my no is 9876543210 is personal no and my official no is 123-456-8907. you
can use any of these"
i want to seperate the 9876543210 and 123-456-8907 from this. therev may be
many phone nos in the string. how to do it
-----
Thanks in Advance
Arun
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2012 Feb 09
3
calling the function which is stored in a list
Hi
I'm storing two functions in a list
# creating two function
function1 <- function(n) {
return(sum(n))
}
function2 <- function(n) {
return(mean(n))
}
#storing the function
function3 =c(function1,function2)
is it possible to call the stored function and used it ?
x=c(10,29)
funtion3[1](x)
Thanks
-----
Thanks in Advance
Arun
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2012 Aug 03
1
how to get a date variable from a dataset
Hi
I have a find the class of each variable of the data set which is given as
input. I can able to find the string and the numeric variable. Not able to
find if the variable is date or not
Can any one help me.
-----
Thanks in Advance
Arun
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2012 Jan 09
6
runif with condition
Hi
I want to generate 4 random number which sum up to 100 always
Please help
-----
Thanks in Advance
Arun
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2012 Jan 31
1
Help required in using apply instead of for loop
Hi
I have a function
y= x^2
min =10
max=20
increment=0.1
I want to find the value of y for the value of x between min and max by step
increment.
how to get the values using apply function instead of for loop
-----
Thanks in Advance
Arun
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2012 Feb 17
1
Creating XML using apply
Hi
My data looks like this
data is a vector
data= var1 var2 var3
100 120 130
i want to put it in an XML
xmlOutput=NULL
xmlOutput<- newXMLNode("results")
for( i in 1 : length(data))
{
newXMLNode("variable",attrs=c(name =names(data)[i] ), value =
data[i]), parent = xmlOutput)
}
is it possible to use apply here
If there more variables it
2012 Feb 29
1
Error in Aggregate
Hi
My dataframe looks like this
data=
id V1 V2 V3 V4
1 5 6 7 8
1 10 20 30 40
2 23 54 54 6
3 43 54 54 33
4 12 34 54 54
4 34 54 23 52
I have to sum by id
I used command aggregate(data,by =list(data$id),FUN=sum)
Error i face is
Error in Summary.factor(c(1L, 1L, 1L, 1L, 1L), na.rm = FALSE) :
sum not meaningful for factors
Please help me
-----
Thanks in Advance
Arun
--
2012 Mar 27
1
help in replacing for llop
Hi
I have records like like this
X1 X2 State
34 72 state1
9 63 state1
49 31 state1
60 34 state1
80 73 state1
60 20 state2
59 87 state2
88 20 state2
71 66 state2
65 56 state2
59 16 state1
60 100 state2
I want to get the summarize value like mean median histogram for X1 and X2
based on state. I'm using FOR loop for this. Is there any method to remove
for loop and use apply or any
2012 Apr 03
1
help in ddply
Hi
I've records like this
df=
x panel
4 1
93 2
21 3
83 4
75 1
87 2
87 3
78 4
50 1
76 2
86 3
65 4
84 1
40 2
39 3
26 4
i want to create histogram out of it . i want all the mid and count values
for panel wise
my code is
histoutput = ddply(df,.(df[2]),hist)
i'm not able to get the required result.
please help me
using for loop takes a lot of time if there are more records
-----
Thanks
2012 Apr 05
1
help in match.fun
hi
I have a dataframe and a parameter
the parameter can have any one value min max mean sum hist
i'm using the function match.fun
fun=match.fun(input)
fun(dataset)
but if input is hist the plot pops up. is there any method to avoid it. else
should use only if condition for histogram
-----
Thanks in Advance
Arun
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2012 Apr 20
1
what is the maximum number of records that we can load using dbwrite
Hi
I'm using the dbwrite to insert a large dataset. There are about 10 million
rows. But i'm not able to load the records.
Please can anyone tell me the way to load or maximum number of records that
dbwrite does. so that i can load it in batches
-----
Thanks in Advance
Arun
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2012 Aug 01
1
finding correlation for lagged values
Hi
I've to find the correlation of a variable and lag of other variable.
My code currently looks like this
y= 32 1 45 26 33 55 15 24 31 78
x=51 69 96 67 71 89 61 42 78 24
lagTimes=2
i want to find the correlation between y and Lag(x,1) and Y &Lag(x,2)
i'm using loop to find the lag and then finding correlation
If there are more variables and need to find the correlation lag
2013 Mar 08
2
Zoo Data
Hi Jakob,
dat1<-read.table(text="
TIME, Value1, Value2
01.08.2011 02:30:00, 4.4, 4.7
01.09.2011 03:00:00, 4.2, 4.3
01.11.2011 01:00:00, 3.5, 4.3
01.12.2011 01:40:00, 3.4, 4.5
01.01.2012 02:00:00, 4.8, 5.3
01.02.2012 02:30:00, 4.9, 5.2
01.08.2012 02:30:00, 4.1, 4.7
01.12.2012 03:00:00, 4.7, 4.3
01.01.2013 01:00:00, 3, 4.3
01.01.2013 01:30:00, 3.8, 4.1
01.01.2013 02:00:00, 3.8,