similar to: Running Total

Displaying 20 results from an estimated 8000 matches similar to: "Running Total"

2011 Aug 22
1
Counting Elements Conditionally
R - I have 3 variables with data below. Variable "Rev" is a vector that changes from 1 to 2, 2 to 3, etc.... Variable "FF" is a binary variable with 1's and 0's. Variable "bin" is a different binary variable with 1's and 0's. I want to calculate the number of elements: 1. Starting with the first element where Rev switches (i.e. 1 to 2) 2. The
2011 Aug 05
1
If find x, then y, else do nothing
I want to write code that says "If you find an element equal to 4 in this vector for each person in the data set tested separately, then put in 1 for 2 and 2 for 4, else leave the variable as is" u.ppl <- (unique(init.dat1$grid)) l.ppl <- length(u.ppl) for (i in 1:l.ppl) { if (grep("4",init.dat1$Slide1_RESP)) {2 == 1, 4 == 2}; else
2011 Jul 27
1
Hidden Markov Models in R
R Community - I am attempting to fit a model as described in Hampton, Bossaerts, and O'doherty (J. Neuroscience) 2006. They use a bayesian hidden markov model to model the Reversal Learning data. I have tried using HMM and depmixS4 with no success. My data is a Reversal Learning Task in which there are 3 sets of patterns over 3 blocks. The participant receives incorrect or correct
2011 Nov 16
1
Cubic Gradient Descent Package
R - Does anyone know of a cubic gradient descent package? I found grad.desc() but that only allows for a 2d function. I have 3 free parameters and thus am looking for a 3d function. Thank you, -- Edward H. Patzelt Research Assistant – TRiCAM Lab University of Minnesota – Psychology/Psychiatry VA Medical Center S355 Elliot Hall: 612-626-0072 www.psych.umn.edu/research/tricam [[alternative
2012 Oct 19
2
Axis Breaks with ggplot2
R-help - I'm trying to create axis breaks similar to this : http://www.r-bloggers.com/wp-content/uploads/2010/08/bar-chart-natural-axis-split1.png . Is there a way to do this in R? Here's my code thus far: structure(list(condition = structure(c(2L, 1L, 3L), .Label = c("con", "exp", "unedit"), class = "factor"), trial.avg = c(4.04583333333333,
2011 Jun 28
2
Loop through each subject
R help - I am attempting to write a script that has multiple subjects in 1 data file. Each subject has multiple rows with columns as variables. Here is my code, I am having problem executing it on each unique subject id (dat$Subject). getwd() setwd("/Users/edwardpatzelt/Desktop/Neuroimaging/MERIT/SRRT/merge") dat <- read.table("test2.txt", header = TRUE, na.strings
2011 Aug 15
0
Indexing Permutation Values
R-help - This code iterates over a function with 2 free parameters to find a list of values (which are the number of incorrect predictions for a computational model). I want to find the values of i,e when there is the minimum number of incorrect predictions. In other words, the value of "i" and "e" when variable "thesum" is at the lowest possible number. The
2016 Apr 22
1
Unique Ordering
Hi R-Help, data at bottom I've been struggling with a problem where I need to order based on 1) the Frequency "Freq" and 2) keeping each group of 3 of the same type together "Var2" but I want across all groups it to go "high to low" based on the earn factor. Thank you! structure(list(Var1 = structure(c(1L, 3L, 2L, 1L, 2L, 3L, 1L, 3L, 2L, 3L, 1L, 2L, 3L, 1L,
2012 Oct 31
2
Aggregate Table Data into Cell Frequencies
R-help - I have this set of aggregated tables (sample data below via dput()). And I would like to have delayValue as the column variables with the "temp" (temp1, temp2, temp3) values as the row variables. However I would like to have the temp variables *aggregated into single rows* so that I have the frequency ("Freq" | counts) of each time each "delayValue" occurs
2009 May 15
1
data summary and some automated t.tests.
I would like to preform a t.test to each of the measured variables (sand.silt etc.) with a mean and sd for each of the treatments (up or down), and out put this as a table.... I am having a hard time starting- maybe it is to close to lunch. Any suggestions would be greatly appreciated. Stephen Sefick x <- (structure(list(sample. = structure(c(1L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 2L, 3L,
2018 Jan 30
2
Could the Odds represent weight in Generalized Linear Model?
Hello all, I'm sorry if my question seems basic. Im studying a responses (Yes,No) in a survey and, thanks to GLM I obtain the following relation with my variables : (Yes,No)~ ?0 + Age We note this this certain type of (Yes,No) response is linked to age (p<0.05 in glm) . After that we calculated : model1=glm(cbind(Yes,No) ~ Age + Times + Type, family=binomial) summary(model1)
2018 Jan 30
1
Could the Odds represent weight in Generalized Linear Model?
Dear Lenny, You can do this by using Age as an offset factor. dataset$wAge <- dataset$Age * 1.02 glm(cbind(Yes,No) ~ offset(wAge) + Times + Type, family=binomial, data = dataset) Best regards, ir. Thierry Onkelinx Statisticus / Statistician Vlaamse Overheid / Government of Flanders INSTITUUT VOOR NATUUR- EN BOSONDERZOEK / RESEARCH INSTITUTE FOR NATURE AND FOREST Team Biometrie &
2018 Jan 30
0
Could the Odds represent weight in Generalized Linear Model?
Dear Thierry, Thanks a lot for this answer, I mean i want to obtain such model *Behavior1 = ?0+?1*Age* , the purpose is to obtain *?1*. I want to be sure that the odds value could be the ?1. Or how to calculate it ? Thanks again for your precious help. Lenny <http://www.avg.com/email-signature?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail>
2017 Nov 07
1
fill histogram in ggplot
Hi all, I have the following data and I have a histogram for mms like ggplot(hist,aes(x=hist$mms))+ geom_histogram(binwidth=1,fill="white",color="black")and then I want to fill the color of histogram by probable=1 and probable=0, could anyone help me in this? My data: structure(list(probable = c(1L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 1L,
2025 May 19
3
Looking for a function or a set of steps
?s 18:40 de 18/05/2025, paul zachos via R-help escreveu: > Dear R Community > > I am an R beginner > > I have a vector of ?1?s and ?0?s > > x > [1] 0 0 1 0 0 1 1 0 1 0 1 1 1 0 1 1 0 0 1 0 1 0 1 0 0 0 0 > [28] 0 1 1 0 1 0 1 1 0 0 0 0 1 0 1 1 0 0 1 0 0 1 0 0 0 1 1 > [55] 0 0 1 0 1 0 0 0 1 1 1 1 0 1 0 0 0 1 0 0 1 1 0 0 0 0 0 > [82] 1 1 1 0 1 0 0 1 0 0 1 1 1 1 1
2024 Oct 17
2
DPLYR Multiple Mutate Statements On Same DataFrame
Hi R Helpers, I have been looking for an example of how to execute different dplyr mutate statements on the same dataframe in a single step. I show how to do what I want to do by going from df0 to df1 to df2 to df3 by applying a mutate statement to each dataframe in sequence, but I would like to know if there is a way to execute this in a single step; so simply go from df0 to df1 while executing
2025 May 28
1
Looking for a function or a set of steps
Paul, Perhaps slightly better and more concise is y <- -x + 1 Why multiply? Of course it may be optimized in some cases. On Tue, May 27, 2025, 3:36?AM Paul Zachos <paz at acase.org> wrote: > Wow! Amazing stuff. > It will take me a while to digest all that you have offered here. > > I came up with a simple solution myself: > y<- (-1*x)+1 > > Thank you >
2018 May 28
3
How to generate a conditional dummy in R?
Hi everyone, I am trying to generate a conditional dummy variable ?X" with the following rules set X=1 if Y is =1, two years prior to the NA. [0,0,NA]. For example, if the pattern for Y is 0,0,NA then the X variable is =0 for all the two years prior to the NA. If the pattern for Y is 0,1,NA or 1,0,NA then the X =1 . To be clear, if 1,1,NA then the X=1 that first specific year, it
2018 May 29
0
How to generate a conditional dummy in R?
Hi Faradj, What a problem! I think I have worked it out, but only because the result is the one you said you wanted. # the sample data frame is named fkdf Y2Xby3<-function(x) { nrows<-dim(x)[1] X<-rep(0,nrows) for(i in 1:(nrows-2)) { if(!is.na(x$Y[i])) { if(x$Y[i] == 1 && any(is.na(x$Y[(i+1):(i+2)]))) X[i]<-1 if(i > 1) { if(X[i-1] == 1) X[i]<-0 } }
2010 Jul 02
2
Problem with aggregating data across time points
Hello- I have a dataset which basically looks like this: Location Sex Date Time Verbal Self harm Violence_objects Violence A 1 1-4-2007 1800 3 0 1 3 A 1 1-4-2007 1230 2 1 2 4 D 2 2-4-2007 1100 0