similar to: quantmod getOptionChain Not Work

Package? Quantmod. In the subject line. I agree that they look like dates, I don't know how to determine if they are actually dates. Josh Ulrich usually answers questions along these lines very informatively and quickly. One reasonable course of action is to wait to see if he does the same with this one. --JJS ________________________________ From: Bert Gunter <bgunter.4567 at

Hi Dirk, Thanks for your note. I understand that expiry dates are the dates that the option expires, so I don't think that I am confused about that (although the upper limits of one's confusion is difficult to accurately estimate). My lack of clarity come from treating those "dates" as actual dates as opposed to strings, which one could reasonably interpret them to be from

On 5 March 2018 at 03:13, Sparks, John wrote: | library(quantmod) | #in fairness, I did not include this last time and my example was therefore not reproducible. Apologies to Bert and everyone else #for not following the posting guidelines. | aapl_total<-getOptionChain("AAPL", NULL)> | | How could I then get the subset of the entire list which only has expiry dates in 2019, or

Hi R Helpers, Is it possible to interpret the top level of the list as a date after downloading all the option chain data for a ticker? For example, after I run aapl_total<-getOptionChain("AAPL", NULL) the top descriptor of the lists is a date (Mar.09.2018, Mar.23.2018, etc.). So if want to subset down to those parts of the list that correspond to say, (expiration)

Package? The **names** of the top levels of your lists, "Mar.09.2018", "Mar.23.2018" certainly look like dates and if they are -- I have no idea what package/context is -- they certainly could be formatted as such. See e.g. "date-time" . There are also several package that provide date tools. Cheers, Bert Bert Gunter "The trouble with having an open mind is

On 5 March 2018 at 02:46, Sparks, John wrote: | I agree that they look like dates, I don't know how to determine if they are actually dates. You know options but you are confused about maturity dates, i.e. expiry? In information in that list (ie along the date dimension) is the expiry; at each date you have another list for both puts and calls, and inside each of those a grid given by the

Hi R Helpers, Is it possible to interpret the top level of the list as a date after downloading all the option chain data for a ticker? For example, after I run aapl_total<-getOptionChain("AAPL", NULL) the top descriptor of the lists is a date (Mar.09.2018, Mar.23.2018, etc.). So if want to subset down to those parts of the list that correspond to say, (expiration)

This script below pulls yahoo data via a function in quantmod, then massages the data around to forumalate a 3D graph with RGL library, attached is a ggplot to show the data i'm trying to create a surface with in separate line geoms . the issue is that the 3D graph looks very ugly and cut up because of the limited quantities of points on the front month expirations.. can anyone tell me whats

Hello All, i was trying to simply run the readHTMLTable on the example published in the package. And on a page I was working on. So running: u = "http://en.wikipedia.org/wiki/List_of_countries_by_population" tables = readHTMLTable(u) returns the following error: Error in tb[["thead"]] : subscript out of bounds looking up this error on the web, didnt give me any hint. Is

I realize it's -12C and we're having the next best thing to a blizzard but why can I not melt this data frame. I am missing something terribly obvious but I just don't understand what the error message is saying. John Kane Kingston ON Canada Code and aata below #================================================# library(reshape2) melt(mydata, id.vars = c("date"))

Hi I have a question concerning regexp - I want to select with grep all character strings which contain the numbers 11:20 (code below). At the moment I am using [], but that obviously does not work, as it matches each element in the []. Is there a way to specify that the regexp should match 11, but not 1? Here is the code code: x <- paste("suff", 1:40, "pref",

I have a data.frame named "df". The dput of df is at the bottom of this e-mail. What I'd like to do is replace the "n/a " values with NA. On Mac OSX, it works to do this: df[df == "n/a"] <- NA However, it does not work on Ubuntu. See below. Thanks in advance, Garrett > x <- df[27, 4] # complete data.frame dput is below > dput(x) "n/a?"