similar to: speed up merge

Hello, Does anyone know of a way I can speed this up? Basically I'm attempting to get the data item on the same row as the report date for each report date available. In reality, I have over 11k of columns, not just A, B, C, D and I have to do that over 100 times. My solution is slow, but it works. The loop is slow because of merge. # create sample data z.dates =

Hello, Thank you for your help/advice! The issue here is speed/efficiency. I can do what I want, but its really slow. The goal is to have the ability to do calculations on my data and have it adjusted for look-ahead. I see two ways to do this: (I'm open to more ideas. My terminology: Unadjusted = values not adjusted for look-ahead bias; adjusted = values adjusted for look-ahead bias.) 1) I

Hello r-help! I have data with two kind of ratings on status of 100 occupations. The first kind of rating is on the percieved "objective" status that these occupations have in society at large, and the second kind or rating is on the status that the respondents think that these occuption *should* have. The ratings were originally integer values in the rage 1-9, but in the current data,

Hello, My direct desire is a good (fast) way to fill values forward until there is another value then fill that value foward in the data xx (at the bottom of this email). For example, from row 1 to row 45 should be NA (no change), but from row 46 row 136 the value should be 12649, and from row 137 to the next value should be 13039.00. The last line of code is all you need for this part. If you

I have Postfix/Dovecot/postfixadmin/MySQL with several virtual mailbox domains one of the domains is like aname.com.au, the user also now has aname.com, and, would like to 'mirror' most of the addresses to be user at aname.com, THOUGH, some are to remain as user2 at aname.com.au so, both user at aname.com as well as user at aname.com.au should be one user the users retrive emails as

Hello, I have a specific problem, I have a large dataframe, and after clustering I want to select certain colums, the elements of a subcluster. My dataframe looks like this : > colnames(data) [1] "101KF4319097339" "102KF4319101170" "103KF4319047549" "104KF4319046389" [5] "105KF4319013260" "106KF4319025582"

While SVCB/HTTPS provides a better solution for the browsing use case, I see other use cases where ALIAS/ANAME would be ideal, notably in apex RRs. So while fostering SVCB/HTTPS deployment is a good thing, I wouldn?t mind name server software implementing ALIAS. Including NSD, but I reckon it?s much more challenging to do due to NSD architecture than it was to implement it in PowerDNS. But if

In a function, say foo.glm for glm objects I want to use the name of the object as a label for some output, but *only* if a glm object was passed as an argument, not a call to glm() producing that object. How can I distinguish these two cases? For example, I can use the following to get the name of the argument: foo.glm <- function(object) { oname <- as.character(sys.call())[2]

Dear prospective reader, I apologize for posting my problem but I've just no idea how to go on by processing this huge (over 70 MB) dataset. Thank you in advance for any help or comment! I do appreciate it! My textfile contains 1 column of interest (numbers/values only). The overall issue is to extract 'events', starting points of which are defined by at least 24 preceding values

Hi, Suppose I've got a matrix, and the first few elements look like "x1 + x3 + x4 + x5 + x1:x3 + x1:x4" "x1 + x2 + x3 + x5 + x1:x2 + x1:x5" "x1 + x3 + x4 + x5 + x1:x3 + x1:x5" and so on (have got terms from x1 ~ x14). If I want to replace all the x1 with i7, all x2 with i14, all x3 with i13, for example. Is there an easy way? I tried to put what I want

Can someone explain why I am getting the following error: in the r code below? Error in solve.default(diag(2) + ((1/currvar) * (XX1 %*% t(XX1)))) : system is computationally singular: reciprocal condition number = 0 In addition: There were 50 or more warnings (use warnings() to see the first 50) The R code is part of a bigger program. ##sample from full conditional

Hi Christof! AFAIK, PowerDNS is the only open source name server that supports ALIAS. There was an idea to standardize ALIAS as "ANAME" (https://datatracker.ietf.org/doc/draft-ietf-dnsop-aname/), but the idea was dropped in favor of SVCB/HTTPS record https://datatracker.ietf.org/doc/rfc9460/. So now we have to wait until all Browser vendors implement SVCB/HTTPS. Regards Klaus PS: If

[Please keep r-help in the cc: list] I don't quite know how to interpret the difference between specifying effort as an offset vs. as weights; I would have to spend more time thinking about it/working through it than I have available at the moment. I don't know that specifying effort as weights is *wrong*, but I don't know that it's right or what it is doing: if I were

smbclient (and smbtar) in version 2.2.7a (and prior) has problems with large files (> 4GB). The following patch (against 2.2.7a) fixes all known problems with this. This code has been checked into the CVS tree in all branches as well. -- ====================================================================== Herb Lewis Silicon Graphics Networking Engineer

If I combine elements into a list b <- c(22.4, 12.2, 10.9, 8.5, 9.2) my.c <- sample.int(round(2*mean(b)), 5) my.list <- list(b, my.c) the names of the elements seems to get lost in the process: > str(my.list) List of 2 $ : num [1:5] 22.4 12.2 10.9 8.5 9.2 $ : int [1:5] 11 8 6 9 20 If I explicitly name the elements at list-creation, I get what I want: my.list <- list(b=b,

Hi, all I can not figure this out, please have a look and help me out. thank you! Note: this is in SPLUS, not R. I have following code *********************************** modfit<-function(yir,yew, ft) { n<-length(yew) yew<-yew[1:(n-1)] yy<-yir-ft xx<-yew-ft n<-length(xx) xx0<-xx[2:n] yy0 <-yy [2:n] xx1<-xx[1:(n-1)] fit <- garch(yy0~xx0 + xx1+var.in.mean,

My data consists of a numeric (yy) variable and a categorical (xx) variable, as shown below. xx = c(rep("C", 5), rep("D",5)) yy = rnorm(10, 0, 4) xx1 = as.integer(as.factor(xx))   plot(xx1, yy, ylim = c(-13.5, 4), col="blue")   I wish to generate a scatter plot of the data such that instead of 1 it prints C, and instead of 2, it prints D on the x- axis.

I have a matrix like this Name 1 2 3 4 5 NM_001039514 1.033557047 0.7469879518 0.9004524887 0.8613861386 0.7952499048 NM_001039723 1.0759493671 1.2315789474 0.8666666667 1.1142857143 0.9428011471 NM_001042605 0.9897435897 0.8870431894

Hi all, I have a very large binary vector, I wish to calculate the number of 1's over sliding windows. this is my very slow function slide<-function(seq,window){ n<-length(seq)-window tot<-c() tot[1]<-sum(seq[1:window]) for (i in 2:n) { tot[i]<- tot[i-1]-seq[i-1]+seq[i] } return(tot) } this works well for for reasonably sized vectors. Does

Dear all, I am stumped at what should be a painfully easy task: predicting from an lm object. A toy example would be this: XX <- matrix(runif(8),ncol=2) yy <- runif(4) model <- lm(yy~XX) XX.pred <- data.frame(matrix(runif(6),ncol=2)) colnames(XX.pred) <- c("XX1","XX2") predict(model,newdata=XX.pred) I would have expected the last line to give me the