similar to: vlookup type function

I am attempting to emulate the VLOOKUP function from Excel in R. I want to compare one column (coll.minus.release) with another (release.days) to get the number of parasitoid released at that time (TotalParasitoids). for example: coll.minus.release release.days ParasitoidTotal -12 -266 1700 8 -259 1000 8

Hi R-users,   I would like to search for the values of seq that match my rand values.  In excel I will use =VLOOKUP(G2,$E$2:$F$32,2).  For example, for rand=.262 it will give me approximately seq=120 and rand=0.964293344, seq=460 and etc.   E           F     G cdf         seq   rand 0.00E+00    0     0.262123478 1.56E-03    20    0.964293344 1.55E-02    40    0.494827113 5.30E-02    60   

Hi, Is there are function similar to excel vlookup in R. Please let me know. Thanks, Sachin ____________________________________________________________________________________ [[alternative HTML version deleted]]

I have two files with dates and prices in each. The number of rows in each of them will differ. How do I create a new file which contains data from both these files? Cbind and merge are not helpful. For cbind because the rows are not the same replication occurs. Also if I have similar data how do I write a vlookup kind of function? I am giving an example below: Say Price1 file contains the

Hi, A quick beginner's question. I have two time series, A with daily data, and another B with data at varying frequencies, but mostly annual. Both the series are sorted ascending. I need to merge these two series together in the following way: For any entry of A, the lookup should match with B until we find an entry of B that's larger than A's. For all A[i], i = 1,...,N and B[j],

Hi r users,   I would like sort of   cdf         seq   rand 0.00E+00    0     0.262123478 1.56E-03    20    0.964293344 1.55E-02    40    0.494827113 5.30E-02    60    0.733726005 1.16E-01    80    0.800408948 1.97E-01    100   0.925748466 2.88E-01    120   0.047578356 3.80E-01    140   0.266060366 4.68E-01    160   0.125522629 5.48E-01    180   0.701193274 6.18E-01    200   0.915799432

Hi,   Does R has something similar  to vlookup function in excel?   Thank you for the info. [[alternative HTML version deleted]]

Hello! Hope there is a nifty way to speed up my code by avoiding loops. My task is simple - analogous to the vlookup formula in Excel. Here is how I programmed it: # My example data frame: set.seed(1245) my.df<-data.frame(names=rep(letters[1:3],3),value=round(rnorm(9,mean=20,sd=5),0)) my.df<-my.df[order(my.df$names),] my.df$names<-as.character(my.df$names) (my.df) # My example lookup

Hello, I have a matrix and I want to sample 20 rows that are the the percentiles of 0-100 in 0.05 increments. I have a vector of my sequence (0, 0.05, 0.10, 0.15,....1.0) and also a normalised vector of rownumbers. That is, there are 234 rows (for example) so I do perc<-c(1:234/234) which looks like a bunch of numbers from 0 - 1. In Excel (which I try not to use at every possible

Hi everyone, I'd like to be able to apply lda to each 2D matrix slice of a 3D array, and then use the scalings to obtain the corresponding lda scores. I can use 'apply' to get a list of the lda output for each 2D slice, and can create a list of the resulting scalings, but I'm not sure how to multiply them in a vectorized way. Here's how I made a list of 2D matrices

I want to select a subset of an array, but I want to make a function so that it can handle any number of dimensions. This is probably best described with an example > x <- 1:100 > dim(x) <- c(10,10) > x [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,] 1 11 21 31 41 51 61 71 81 91 [2,] 2 12 22 32 42 52 62 72 82 92 [3,]

Hello I have been struggling with this simple looking problem. I have two dataframes. The first one contains ID, date, and revenue information for specific suppliers. id lastdate depvar A 5/10/2017 10 B 8/16/2017 20 C 2/14/2017 30 D 9/5/2017 40 E 8/1/2017 50 F 11/4/2017 60 G 6/22/2017 70 The second dataframe contains timeseries data of each supplier in different columns. For example Column A are

Dear all, I'm aware if y has two separate functions (depending on the conditions of x) you can use the ifelse function to separate y into two separate functions depending on input. How do you do this if there a multiple different conditions for x? for example, y fits the following between t>0 & t<15----->function(t) t^2, y fits the following between t>15 &

Any errors atm in syslog and/or messages and the samba logs.   And the interval of the problem, still 5 days?       Gr.   Louis       Van: Oliver Werner [mailto:oliver.werner at kontrast.de] Verzonden: dinsdag 22 maart 2016 11:00 Aan: L.P.H. van Belle CC: samba at lists.samba.org Onderwerp: Re: [Samba] Problem with Winbind and Windows Clients   Hi,   now i have tested again

Dear R Community, I hope you might be able to assist with a small problem creating a function. I am working with water-quality data sets that contain the concentration of many different elements in water samples. I need to assign quality-control flags to values that fall into various concentration ranges. Rather than a web of nested if statements, I am employing the findInterval function to

What should findInterval(x,vec,all.inside=TRUE) return when length(vec)<=1, so there are no inside intervals? R-3.3.0 gives a decreasing map of x->output when length(vec)==1 and -1's when length(vec)==0. Would '0' in all those cases be better? > findInterval(x=c(10, 11, 12), vec=11, all.inside=TRUE, rightmost.closed=FALSE, left.open=FALSE) [1] 1 0 0 >

Ok, next test. Change : kerberos method = secrets and keytab to kerberos method = secrets and wait again. I'll explain by giving this link. http://changelogs.ubuntu.com/changelogs/pool/main/s/samba/samba_4.3.6+dfsg-1ubuntu1/changelog Look at the last line bugfix in this change log of 4.3.6. Im testing here also, because this looks like its also involves the kerberos changes, now, i

Suppose we have `dat` shown below and we want to find the the `y` value corresponding to the last value in `x` equal to the corresponding component of `seek` and we wish to return an output the same length as `seek` using `findInterval` to perform the search. This returns the correct result: dat <- data.frame(x = c(2, 2, 3, 4, 4, 4), y = c(37, 12, 19, 30, 6, 15), seek = 1:6)

? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile Url: https://stat.ethz.ch/pipermail/r-help/attachments/20070723/2d591177/attachment.pl

>>>>> Gabor Grothendieck >>>>> on Mon, 16 Sep 2024 11:21:55 -0400 writes: > Suppose we have `dat` shown below and we want to find the the `y` value > corresponding to the last value in `x` equal to the corresponding component > of `seek` and we wish to return an output the same length as `seek` using > `findInterval` to perform the