similar to: vlookup type function

I am attempting to emulate the VLOOKUP function from Excel in R. I want to compare one column (coll.minus.release) with another (release.days) to get the number of parasitoid released at that time (TotalParasitoids). for example: coll.minus.release release.days ParasitoidTotal -12 -266 1700 8 -259 1000 8

Hi R-users,   I would like to search for the values of seq that match my rand values.  In excel I will use =VLOOKUP(G2,$E$2:$F$32,2).  For example, for rand=.262 it will give me approximately seq=120 and rand=0.964293344, seq=460 and etc.   E           F     G cdf         seq   rand 0.00E+00    0     0.262123478 1.56E-03    20    0.964293344 1.55E-02    40    0.494827113 5.30E-02    60   

Hi, Is there are function similar to excel vlookup in R. Please let me know. Thanks, Sachin ____________________________________________________________________________________ [[alternative HTML version deleted]]

I have two files with dates and prices in each. The number of rows in each of them will differ. How do I create a new file which contains data from both these files? Cbind and merge are not helpful. For cbind because the rows are not the same replication occurs. Also if I have similar data how do I write a vlookup kind of function? I am giving an example below: Say Price1 file contains the

Hi, A quick beginner's question. I have two time series, A with daily data, and another B with data at varying frequencies, but mostly annual. Both the series are sorted ascending. I need to merge these two series together in the following way: For any entry of A, the lookup should match with B until we find an entry of B that's larger than A's. For all A[i], i = 1,...,N and B[j],

Hi r users,   I would like sort of   cdf         seq   rand 0.00E+00    0     0.262123478 1.56E-03    20    0.964293344 1.55E-02    40    0.494827113 5.30E-02    60    0.733726005 1.16E-01    80    0.800408948 1.97E-01    100   0.925748466 2.88E-01    120   0.047578356 3.80E-01    140   0.266060366 4.68E-01    160   0.125522629 5.48E-01    180   0.701193274 6.18E-01    200   0.915799432

Hi,   Does R has something similar  to vlookup function in excel?   Thank you for the info. [[alternative HTML version deleted]]

Hello! Hope there is a nifty way to speed up my code by avoiding loops. My task is simple - analogous to the vlookup formula in Excel. Here is how I programmed it: # My example data frame: set.seed(1245) my.df<-data.frame(names=rep(letters[1:3],3),value=round(rnorm(9,mean=20,sd=5),0)) my.df<-my.df[order(my.df$names),] my.df$names<-as.character(my.df$names) (my.df) # My example lookup

Hello, I have a matrix and I want to sample 20 rows that are the the percentiles of 0-100 in 0.05 increments. I have a vector of my sequence (0, 0.05, 0.10, 0.15,....1.0) and also a normalised vector of rownumbers. That is, there are 234 rows (for example) so I do perc<-c(1:234/234) which looks like a bunch of numbers from 0 - 1. In Excel (which I try not to use at every possible

Hi everyone, I'd like to be able to apply lda to each 2D matrix slice of a 3D array, and then use the scalings to obtain the corresponding lda scores. I can use 'apply' to get a list of the lda output for each 2D slice, and can create a list of the resulting scalings, but I'm not sure how to multiply them in a vectorized way. Here's how I made a list of 2D matrices

I want to select a subset of an array, but I want to make a function so that it can handle any number of dimensions. This is probably best described with an example > x <- 1:100 > dim(x) <- c(10,10) > x [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,] 1 11 21 31 41 51 61 71 81 91 [2,] 2 12 22 32 42 52 62 72 82 92 [3,]

Hello I have been struggling with this simple looking problem. I have two dataframes. The first one contains ID, date, and revenue information for specific suppliers. id lastdate depvar A 5/10/2017 10 B 8/16/2017 20 C 2/14/2017 30 D 9/5/2017 40 E 8/1/2017 50 F 11/4/2017 60 G 6/22/2017 70 The second dataframe contains timeseries data of each supplier in different columns. For example Column A are

Dear all, I'm aware if y has two separate functions (depending on the conditions of x) you can use the ifelse function to separate y into two separate functions depending on input. How do you do this if there a multiple different conditions for x? for example, y fits the following between t>0 & t<15----->function(t) t^2, y fits the following between t>15 &

Any errors atm in syslog and/or messages and the samba logs.   And the interval of the problem, still 5 days?       Gr.   Louis       Van: Oliver Werner [mailto:oliver.werner at kontrast.de] Verzonden: dinsdag 22 maart 2016 11:00 Aan: L.P.H. van Belle CC: samba at lists.samba.org Onderwerp: Re: [Samba] Problem with Winbind and Windows Clients   Hi,   now i have tested again

Dear R Community, I hope you might be able to assist with a small problem creating a function. I am working with water-quality data sets that contain the concentration of many different elements in water samples. I need to assign quality-control flags to values that fall into various concentration ranges. Rather than a web of nested if statements, I am employing the findInterval function to

What should findInterval(x,vec,all.inside=TRUE) return when length(vec)<=1, so there are no inside intervals? R-3.3.0 gives a decreasing map of x->output when length(vec)==1 and -1's when length(vec)==0. Would '0' in all those cases be better? > findInterval(x=c(10, 11, 12), vec=11, all.inside=TRUE, rightmost.closed=FALSE, left.open=FALSE) [1] 1 0 0 >

Ok, next test. Change : kerberos method = secrets and keytab to kerberos method = secrets and wait again. I'll explain by giving this link. http://changelogs.ubuntu.com/changelogs/pool/main/s/samba/samba_4.3.6+dfsg-1ubuntu1/changelog Look at the last line bugfix in this change log of 4.3.6. Im testing here also, because this looks like its also involves the kerberos changes, now, i

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Hi, we have upgrade an Samba Member (DCs already upgraded) from Samba 4.1.17 to Samba 4.2.10. On DCs work fine after install winbind. But our member extremely slow. Connect to the Share takes 2-3 minutes and directory listing need 2-5 minutes. wbinfo -u takes around 20 seconds and will not return output wbinfo -g takes 3 seconds and show my groups id user.name takes 20 seconds and shows

I've found over time that R documentation that comes off as terse at first blush is usually revealed to be precise, concise, and complete on close reading.? I'm sure this is also true of `?findInterval`, but for whatever reason my brain simply refuses to extract meaning from it. Part of the problem may be that we interact with the function via a compressed form of the bounds of the