similar to: Table into a list

Hi, Can someone please give me a pointer as to how I can set values of an array? Why does the code below not work? my_array <- array(dim=c(2,2)) my_array[][] = 0 my_array [,1] [,2] [1,] 0 0 [2,] 0 0 for(i in seq(1,2,by=1)){ for(j in seq(1,2,by=1)){ my_array[i][j] = 5 } } Warning messages: 1: In my_array[i][j] = 5 : number of items to replace is not a multiple of

Dear R-users, suppose I have three dataframes like these df1: mydate min_temp 31032013 12 01042013 8 02042013 -999 df2: mydate min_temp 31032013 10 01042013 11 02042013 14 df3: mydate min_temp 31032013 4 01042013 3 02042013 5 where -999 means that the temperature data is not available (at the moment I cannot change it to NA because I am not the db administrator); suppose also that oggi is

Hello, I would like to compress some data, stored in a Numpy Array (Python) with something like (*): flac.compress(my_array) without having to put data in a .wav file, without having to deal with containers, etc., i.e. : *raw data in / raw data out* Do you have an idea on how to do that with FLAC? This could be useful for audio data of course (stored in simple arrays), but also for other kind

Hello I've been looking at a debuginfo issue on an out-of-tree target which uses DWARF aranges. The problem is that aranges are generated for both data and code objects, and the debugger gets confused when program addresses overlap data addresses. The target is a Harvard Architecture CPU, so the appearance of overlapping address ranges is not in itself a bug as they reside in different

I am going nuts here.. I have a form where users can write a city name (used with auto_complete) - and once they click on the desired city in the dropdown menu - I would like to have the Country field filled automatically as well... Is this possible at all ? If so, can somebody please tell me where I can find some documentation on the subject, or preferrably an example ? Many thanks in

Hi everyone, I am trying to simulate the ''grep -v'' behavior in an array: Ex: vgrep([''aaa'',''bbb'',''ccc'',''aaaddd''], ''aaa'') Would return: [''bbb'', ''ccc''] So I tried to use ruby to do it: normally the ''-'' operation should be

Can anyone help me ??? I want to export some data into MS excel and create a pie or line chart. How can I export the data? Does it gives any tutorial websites ? thanks for your help! -- Posted via http://www.ruby-forum.com/.

I am trying to reshape a data set. Could someone please help me with the reshape, cast, and melt functions? I am new to R and I have tried reading up on how to use the reshape package, but I am very confused. Here is an example of what I am trying to do: subject coder score time [1,] 1 1 20 5 [2,] 1 2 30 4 [3,] 2 3 10 10 [4,] 2 2

Hi guys, bought the ROR book. I understand most of it and really like it. There is just on thing I just dont get. Lets take this code for example. def list @products = paginate :product, :per_page => 10 end As far as I understand @products should be some kinda hash or array, with the data of the Database inside. How can I display this array ? One solution is to do it like this (like in

I'm in the middle of my own little intellectual exercise comparing dcast() and reshape() and have successfully stumped myself. I want to melt() a data frame, then dcast() it into a new form. After doing so, I want to duplicate the process using reshape(). So far, I can do the melt and cast require(reshape2) Raw <- data.frame(site = c(1, 1, 1, 1, 2, 2, 2, 2), id =

## Can someone suggest a simpler expression than either of these, with the goal ## of taking a long matrix into a wide one with exactly one of the factors converted to ## columns and all the rest retained as factors. I want something that generalizes beyond ## the three factors illustrated here. ## Rich meltTest <- data.frame(A=rep(c("B","C"), each=12),

Hi all, I have played a bit with the "reshape" package and function along with "melt" and "cast", but I feel I still don't have a good handle on how to use them efficiently. Below I have included a application of "reshape" that is rather clunky and I'm hoping someone can offer advice on how to use reshape (or melt/cast) more efficiently. #For this

Hello, I need to convert dataframe from: ID T0 T1 T2 A 1 2 3 B 4 5 6 C 7 8 9 to: ID Variable Value A T0 1 A T1 2 A T2 3 B T0 4 B T1 5 B T2 6 C T0 7 C T1 8 C T2 9 i tried to use melt cast but it gives me all the time not exactly what I need. Thank

List, I want to reshape my data, but I'm not sure how to do it... it might be a simple task, but don't know which package does this. "occ.data" (see below) is how my original data are arranged, and I know that with melt() I can reshape it like "y" (see below). However, I just want to build a matrix like the "y" matrix, but with only 2 dimensions. Something

Dear all, I'm having a few problems trying to reshape a data frame. I tried with reshape{stats} and melt{reshape} but I was missing something. Any help is very welcome. Please find details below: ################################# # data in its original shape: indiv <- rep(c("A","B"),c(10,10)) level.1 <- rpois(20, lambda=3) covar.1 <- rlnorm(20, 3, 1) level.2

Hi, I used to use reshape and moved to reshape2 (R 2.15.1). Now I tried some of my older scripts and was surprised that my cast function wasn't working like before. What I did/want to do: 1) Melt a dataframe based on a vector specifying column names as measure.vars. Thats working so far: dfm <- melt(df, measure.vars=n, variable_name = "species", na.rm = FALSE) 2) Recast the

I am trying to use the "cast" function from the reshape package, where the formula is not passed in directly, but as the result of the as.formula() function. Using reshape v. 0.7.2 I am able to properly melt() by data with: > molten <- melt(x, id=1:2) then I can properly cast with this: > cast(molten, days ~ variable) but if I try > cast(molten,

I have an array with 44800 columns and 24 rows I would like to compute the row average for the array 100 columns at a time, so I would like to end up with an array of 24 rows x 448 columns. I have tried using apply(dataset, 1, function(x) mean(x[])), but I am not sure how to get it to take the average 100 columns at a time. Any ideas would be welcomed. thanks, Spencer [[alternative HTML

Dear All, I have some data in the following shape: ID begin_t1 end_t1 begin_t2 end_t2 Thomas 11/03/04 13/05/06 04/02/07 16/05/08 ... ... ... ... ... Jens 24/01/02 23/05/03 07/06/03 14/11/05 I would like to reshape this data to have the following form: ID Begin_Time End_Time Thomas 11/03/04 13/05/06 Thomas 04/02/07 16/05/08 ... ... ... Jens 24/01/02 23/05/03 Jens

Hi list, I run R on Linux and OSX. On both systems I use R version 2.9.2 (2009-08-24) and reshape version: 0.8.2 (2008-11-04). When I do a melt with na.rm=T on a data frame I get different results on these systems: library(reshape) x <- read.table(textConnection("char trial wn p E10I13D0 4 r E10I13D0 4 a E10I13D0 4 c E10I13D0 4 t E10I13D0 4 i E10I13D0 4 c E10I13D0 4 e E10I13D0