similar to: Median In Survival

Displaying 20 results from an estimated 1100 matches similar to: "Median In Survival"

2012 Jun 25
1
read.spss function
Hi dear all, I am trying to import a dataset from SPSS into R (R x64 2.15.0). I used both   read.spss("D:/Untitled2.sav", use.value.labels = TRUE, to.data.frame = TRUE, max.value.labels = Inf, trim.factor.names = FALSE,trim_values = TRUE, reencode = NA, use.missings = to.data.frame) & read.spss("D:\\Untitled2.sav", to.data.frame = TRUE, stringsAsFactors = FALSE)   but the
2009 Sep 08
1
Obtaining value of median survival for survfit function to use in calculation
Hi, I'm sure this should be simple but I can't figure it out! I want to get the median survival calculated by the survfit function and use the value rather than just be able to print it. Something like this: library(survival) data(lung) lung.byPS = survfit(Surv (time, status) ~ ph.ecog, data=lung) # lung.byPS Call: survfit(formula = Surv(time, status) ~ ph.ecog, data = lung) 1
2012 Mar 16
1
bias sampling
hi i want to analyze Right Censore-Length bias data under cox model with covariate. what is the package ? tank you. [[alternative HTML version deleted]]
2009 May 22
1
survfit, summary, and survmean (was Changelog for survival package)
> Further I appreciate your new function survmean(). At the moment it > seems to be intended as internal, and not documented in the help. The computations done by print.survfit are now a part of the results returned by summary.survfit. See 'table' in the output list of ?summary.survfit. Both call an internal survmean() function to ensure that any future updates stay in
1998 Apr 12
3
R-beta: S Compatibility (again)
While I think total compatibility is not possible or even very important I have become aware recently of some fairly low level incompatibilities that have rather serious consequences for interchange between systems. Some of these are possibly well known, but I put them on on record here just in case. (I do not expect any action on these, of course, but people may want to note them, and correct
1998 Apr 12
3
R-beta: S Compatibility (again)
While I think total compatibility is not possible or even very important I have become aware recently of some fairly low level incompatibilities that have rather serious consequences for interchange between systems. Some of these are possibly well known, but I put them on on record here just in case. (I do not expect any action on these, of course, but people may want to note them, and correct
2009 May 21
1
Changelog for the survival package
> Several changes in print.survfit, plot.survfit and seemingly in the structure > of ratetabels effect some of my syntax files. > Is there somewhere a documentation of these changes, besides the code itself? I agree, the Changelog.09 file is not as comprehensive as one would like. Specific comments: 1. The ratetables were recently changed to accomodate a new option. I thought
2010 Oct 15
1
Downloading file with lapply
I'm still getting familiar with lapply I have this date sequence x <- seq(as.Date("01-Jan-2010",format="%d-%b-%Y"), Sys.Date(), by=1) #to generate series of dates I want to apply the function for all values of x . so I use lapply (Still a newbie!) I wrote this test function pFun <- function (x) { print(paste("This is: ",x,sep="")) } When I
2016 Aug 03
2
polypath winding rule with transparency
Hi, I see different results in png() and pdf() for polypath() on Windows when using the "winding" rule ## overlapping, both clock-wise x <- cbind(c(.1, .1, .6, .6, NA, .4, .4, .9, .9), c(.1, .6, .6, .1, NA, .4, .9, .9, .4)) pfun <- function() { plot(x) polypath(x * 0.8 + 0.2, rule = "winding", col = "#BEBEBE80") polypath(x, rule =
2007 Dec 09
2
Getting estimates from survfit.coxph
Dear all, I'm having difficulty getting access to data generated by survfit and print.survfit when they are using with a Cox model (survfit.coxph). I would like to programmatically access the median survival time for each strata together with the 95% confidence interval. I can get it on screen, but can't get to it algorithmically. I found myself examining the source of print.survfit to
2016 Aug 04
2
[FORGED] Re: polypath winding rule with transparency
Hi Just to clarify, I think this IS a problem with grid.path() as well as polypath(). For the example you give, grid.path() diverts to drawing a polygon (because there is no 'id' specified), and the NAs in 'x' generate two separate polygons, which get drawn one on top of the other. The correct analogy to the polypath() example is ... x2 <- matrix(x[!is.na(x)], ncol=2)
2005 Dec 23
2
convolution of the double exponential distribution
Is there any R function that computes the convolution of the double exponential distribution? If not, is there a good way to integrate ((q+x)^n)*exp(-2x) over x from 0 to Inf for any value of q and for any positive integer n? I need to perform the integration within a function with q and n as arguments. The function integrate() is giving me this message: "evaluation of function gave a
2017 Jun 15
2
"reverse" quantile function
David, thanks for the response. In your response the quantile function (if I see correctly) runs on the columns versus I need to run it on the rows, which is an easy fix, but that is not exactly what I had in mind... essentially we can remove t() from my original code to make "res" look like this: res<-apply(z, 1, quantile, probs=c(0.3)) but after all maybe I did not explain
2017 Apr 24
1
polypath winding rule with transparency
On Thu, 4 Aug 2016 at 17:53 Michael Sumner <mdsumner at gmail.com> wrote: > On Thu, 4 Aug 2016 at 11:17 Paul Murrell <paul at stat.auckland.ac.nz> wrote: > >> Hi >> >> Just to clarify, I think this IS a problem with grid.path() as well as >> polypath(). >> >> > Hi, oh dear - sorry about that > > I appreciate the deeper explanation, I
2012 Jul 04
1
How to use wheneverize gem
Hi all i''m trying to use wheneverize gem to schedule my mails and to run a specific file in controller.i tried but unable to send mails. i am using rails 2.3.8 and ruby 1.8.7 . ive followed the https://github.com/javan/whenever this link Thanks in advance -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To view this
2011 Mar 18
1
median survival time from survfit
Hello, I am trying to compute the mdeian of the survival time from the function survfit: > fit <- survfit(Surv(time, status) ~ 1) > fit Call: survfit(formula = Surv(time, status) ~ 1) records n.max n.start events median 0.95LCL 0.95UCL 111 111 111 20 NA NA NA The results is NA? the fit$surv gives values between 1 and 0.749! Am I doing this correct?
2009 Jul 20
9
rake error
When I run rake test:units I get this error: 292 tests, 350 assertions, 2 failures, 13 errors rake aborted! Command failed with status (1): [/usr/local/bin/ruby -I"lib:test" "/ usr/loc...] This error just showed up yesterday --- I have no idea how I caused it. Here is my gem list in case that helps: actionmailer (2.3.2, 2.2.2) actionpack (2.3.2, 2.2.2) activerecord (2.3.2, 2.2.2)
2012 Aug 30
1
[Whenever gem]What is the reason that linux's cron can't automatic running?
OS : Ubuntu 12.04 Now I use Backup <https://github.com/meskyanichi/backup> and Whenever<https://github.com/javan/whenever> gem to backup my database. When I run backup perform -t my_backup ,I can works. But when I check the task crontab -l ,it as this: 0 22 * * * /bin/bash -l -c ''backup perform -t my_backup'' Run cat /etc/crontab to check my cron configuration
2011 Aug 26
1
methods() not listing some S3 plot methods...?
Dear List, This may be related to this email thread initiated by Ben Bolker last month: https://stat.ethz.ch/pipermail/r-devel/2011-July/061630.html In answering this Question on StackOverflow http://stackoverflow.com/q/7195628/429846 I noticed that `methods()` was not listing some S3 methods for `plot()` provided by the mgcv package. At the time I wanted to check the development version of R as
2017 Jun 16
0
"reverse" quantile function
It would depend on which one of the 9 quantile definitions you are using. The discontinuous ones aren't invertible, and the continuous ones won't be either, if there are ties in the data. This said, it should just be a matter of setting up the inverse of a piecewise linear function. To set ideas, try x <- rnorm(5) curve(quantile(x,p), xname="p") The breakpoints for the