similar to: Plot Many Data to same plot

Dear all, I have a code that looks like the following (I am sorry that this is not a reproducible example)     indexSkipped<-NULL  ....code Skipped that might alter indexSkipped     if (length(indexSkipped)==0)         spatial_structure<-spatial_structures_from_measurements(DataList[[i]]$Lon,DataList[[i]]$Lat,meanVector)     else        

Dear all, I am having a for loop that iterates a given number of measurements that I would like to split over 16 available cores. The code is in the following format inputForFunction<-expand.grid(caseList,filterList) for (i in c(1:length(inputForFunction$Var1))){#           FileList<-GetFileList(flag=as.vector(inputForFunction$Var1[i]));        print(sprintf("Calling the plotsCreate

I want to generate a list (called "dataList" below) where each of its levels is named. These names are assigned to nameList, which contains all possible permutations of size two taking letters from a larger alphabet, e.g., "aa",...,"Fd",..,"Z1",... One of these permutations is the character string "NA". It seems that when I try to name one

Hello, i only got a small problem. i try to create automatic new dataframes, or png?s. the main problem i got is: how can i create automatic a new name for a file (read out by simply "for") - i tried to use "(paste...) but theres an errormessage, about a wrong declination. R told it is as.character, but need as.Real. Should i use another method than "paste"? i tried as

I am trying to learn how to format Ascii data files for scan or read into R. Precisely for a quickie project, I found some code (at end of this email) to do exactly what I need: To cluster and graph a dendrogram from package (stats). I am stuck on how to format a text file to run the script. I looked at the dataset USArrests (which would be replaced by my data and labels) using UltraEdit. That

First, here's the problem I'm working on so you understand the context. I have a data frame of travel activity characteristics with 70,000+ records. These activities are identified by unique chain numbers. (Activities are part of trip chains.) There are 17,500 chains. I use the chain numbers as factors to split various data fields into lists of chain characteristics with each element of

Hello R-helpers, I have a vector x<-c(1,2,3) and a list that contains vectors datalist<-list(c(1,2,3),c(2,3,4),c(3,4,5),c(4,5,6)) and I would like to identify those list elements that are identical to x. I tried > datalist %in% x [1] FALSE FALSE FALSE FALSE but I am obviously using %in% incorrectly. I also tried messing around with lapply but I can't figure out how to specify

Hi, The following is a cut/paste from http://developer.r-project.org/200update.txt: ... 3) When a package is installed, all the data sets are loaded to see what they produce. If this is undesirable (because they are enormous, or depend on other packages that need to be installed later, ...), add a `datalist' file to the data subdirectory as described in `Writing R

Hello, I am trying to write a script with the end goal of graphing power (y) as a result of sample size (x) at a variety of effects sizes. I am new to loops, and I think my problem is there. Here's the script, which is modified from the script found at the bootom of http://www.statmethods.net/stats/power.html. ANy help would be much appreciated!mtesche at ualberta.ca library(pwr)

Hi all,I would like to draw a simple circle where the color gradient follows the rule color = 1/(r^2) where r is the distance from the circle. I would also like to add a color bar with values going from -40 to -110 (and associate those with the color gradient that fills the circle). So far I experiemented with draw circle

Dear developeRs, my package FrF2.catlg128 holds large catalogues and is supposed to gain additional ones. All the catalogues are intended for the user. So far, the catalogues were stored in the data directory, and LazyData was "no". I understand that this is not considered wise any more (if it ever was), so that I want to change to LazyData "yes" with the next release

I have a question about antialiasing when R generates bitmaps. (This follows a thread on the ggplot2 mailing list.) I mostly use R on Linux, although I sometimes use it in Mac and Windows as well. On Linux, I've found that plotting shapes 15-18 via cairo results in bad-looking output. The points are not antialiased, and they are jagged and misshapen. Plots generated in Windows also aren't

I have written a function to emulate minitab's QQ plotting output (with SW test and AD test results on the graph): mtab.norm<-function(x) { library(nortest) library(lattice) x<-as.numeric(x) x<-as.vector(x) plot.ht<-4.6 plot.wd<-4.6 pt.ht=plot.ht/5 txt.sz<-(plot.ht/7.5) X11(width=plot.wd, height=plot.ht, bg='gray96') qqplot(x, pch=16, cex=pt.ht,

Here are another three problems with logarithmic scales: 1) segments() does not work with logarithmic scales. I suggest to change lines 962-973 in "plot.c": for (i = 0; i < n; i++) { if (FINITE(xt(x0[i%nx0])) && FINITE(yt(y0[i%ny0])) && FINITE(xt(x1[i%nx1])) && FINITE(yt(y1[i%ny1]))) { GP->col = INTEGER(col)[i % ncol];

hi all, I have a simple problem that i am not able to solve. I've a list called datalist with the following structure: [...] [[10]] [[10]]$a -1 0 1 -1 31 5 2 0 6 7 5 1 1 7 36 [[10]]$b -1 0 1 -1 31 5 2 0 6 7 5 1 1 7 36 [[10]]$c [1] 0.855 [[10]]$d [1] 0.855 [...] with [[1]] ... [[100]]. How can i get the mean value of datalist[[x]]$d, where x

The generic rule is that R is not a macro language, so looping of names of things gets awkward. It is usually easier to use compound objects like lists and iterate over them. E.g. datanames <- paste0("aa_", 2000:2007) datalist <- lapply(datanames, get) names(datalist) <- datanames col1 <- lapply(datalist, "[[", 1) colnum <- lapply(col1, as.numeric) (The 2nd

great!! thanks very much, mean(unlist(lapply(listdata, function(z) z$c))) works well. and what about getting the average table $a (displaying the average elements across all 1000 matrix)? could you please help me? I am struggling with this... thanks in advance Roberto mean(unlist(lapply(x, function(z) z$d))) should do the trick On Sun, 12 Feb 2006 20:06:12 +0000, statistical.model at

This may not actually be an R/Splus problem, but it started off that way ..... ===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+===+=== Executive summary: ================== Simulations involving extreme value distributions seem to ``work'' when the underlying distribution is exponential(1) or exponential(2) == chi-squared_2, but NOT when the underlying distribution is

Dear All, I was trying to call a self-defined function that performs nonlinear regression and gets the corresponding prediction upper limit using nls2 package. However, weird thing happened. When I called the function in the main program, an error message "fitted(nlsmodel): object 'nlsmodel' not found" came up. But when I directly ran the codes inside the function, no error came

Dear Mailinglist, I just set up an R 2.9.1 environment with Rcmdr 1.4-6 on Ubuntu Jaunty 9.04. As I'm from Germany my $LANG variable is set to "de_DE.UTF-8". Now, when I open up Rcmdr and try to edit a new datamatrix there is no edit window appearing: Datenmatrix <- edit(as.data.frame(NULL)) ERROR: invalid device In addition, there are plenty of warning messages in the