similar to: transforming a data frame to matrix

Hello, How can I make a monte carlo simulation on R? Regards Adel -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel: +216 97 246 706 (+33640302046 jusqu'au 15/6) fax: +216 71 391 166 [[alternative HTML version deleted]]

Hi list I loaded the content of a file dureetasks.txt to variable a. This file contains an interger per line. when I print a vector, it displays correctly. however, when I try to print the histogram, I get this error message > a=read.table("dureetasks.txt") > hist(a) Error in hist.default(a) : 'x' must be numeric Can you help please? regards -- PhD candidate in

Hello list I have this file 0 121289479 25 0 212599129 1 0 285254098 21 0 444889848 45 0 469197123 30 0 640007403 82 0 718215617 8 0 758534043 56 0 799706577 4 0 814441385 93 0 843545059 37 0.2 121289479 6 0.2 285254098 3 0.2 444889848 6 0.2 469197123 13 0.2 640007403 24 0.2 718215617 3 0.2 758534043 2 0.2 799706577 2 0.2

Hello, I have a file with very big values. I want to display the real values with classic ways (without exposant) > summary(a[,1]); Min. 1st Qu. Median Mean 3rd Qu. Max. 1.198e+09 1.199e+09 1.200e+09 1.200e+09 1.201e+09 1.202e+09 Can you help please? Regards Adel -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel:

Hi list I am discovering R, and -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel: +216 97 246 706 (+33640302046 jusqu'au 15/6) fax: +216 71 391 166 [[alternative HTML version deleted]]

Deal list > I want to generate a random number in an interval using exponential low > I know how to make that simply using uniform low > x1 <- runif(1, 5.0, 7.5) > this will generate a number between 5 et 7.5 but with uniform low. > Could you help pease.? > Regards > > -- > PhD candidate in Computer Science > Address > 3 avenue lamine, cité ezzahra, Sousse 4000

Hello, I have a problem with ggplot and colors I used this function to draw somes lines and I want them to be all black (just to test) however, I dont get any black line in the figure. Do you have any experience with ggplot and manual colors?? ggplot(cmax, aes(cmax[,3], cmax[,6],colour=interaction(cmax[,1],cmax[,2]))) + geom_line() + geom_point() +

Hello I am using this command to draw the figure attached to this mail. xyplot(g[,4]~g[,3],type="b",group=interaction(g[,1],g[,2]), auto.key =list( title="Evolution de la stabilit?" , points = FALSE, columns=2, lines = TRUE,space="right") ,data=g,xlab=expression(beta),ylab="stabilit?") I want to change name of the legend that were attributed

dear list I use runif to generate a ramdom number between min and max runif(n, min=0, max=1) however , the syntaxe of rexp does not allow that rexp(n, rate = 1) and it generate a number with the corresponding rate. The question is: how to generate a number between min and max using rexp(). Regards -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000

Hello, I have a question about how R can run automatically. Here is the story: A file called "data.csv" will be generated every couple of minutes in a folder (overwrite itself). What I want R to do is: 1) scan the folder to find the file. 2) if the file is a newly generated file, process the file 3) output some file identifier on the screen, such as the time when the file was

Dear R users, When you do: > x <- rnorm(10) > y <- rnorm(10) > z <- rnorm(10) > a <- data.frame(x,y,z) > a$x [1] 1.37821893 0.21152756 -0.55453182 -2.10426048 -0.08967880 0.03712110 [7] -0.80592149 0.07413450 0.15557671 1.22165341 Why does this not work: > a[a$y>0.5,y] <-1 Error in "[<-.data.frame"(`*tmp*`, a$y > 0.5, y, value = 1) :

Hi list I am a new user of R. I ask for some "beginner" question I am searching if there is any function that computes the variation of some discrete values of a vector (mean() and sd() exists, but i have not find variation). Thanks in advance Adel -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel: +216 97 246 706 (+33640302046

Hi list I need some help for drawing some histograms I have a dataframe , say, X Y Z T I want to draw a histogram Z-T for each value of the couple (X-Y). When I use thus syntax > library(lattice) > histogram(law[,3] ~ law[,66] | law[,1] ) it draws multiple histograms but by selecting distinct values of law[,1] The deal is to make the same thing but for a couple of columns Thanks in

Hello, I want to create 10 dataframe using a for loop. I don t know what to do to create 10 different dataframes whose name is parametrized with variable i. This syntaxe fails. It create a unique fataframe called dfn. Any input will help Thanks > for (i in 1:10){ + filename=paste("avail4",i,sep = "_") + dfn=read.table(filename) + } -- PhD candidate in Computer Science

Hi i'm a french medical student, i have some data that i import from excel. My colomn of the datafram are the localisations of metastasis. If there is a metatsasis there is the symbol "_". i want to exclude the row without metastasis wich represent the NA data. so, i wrote this mela is the data fram mela1=ifelse(mela[,c(11:12,14:21,23,24)]=="_",1,0) # selection of the

I have two objects, one matrix and one vector. I want to use my vector to subset certain values out of my matrix. For example: I want to tell R, to select out all rows in myMatrix into a new myMatrix2 IF that corresponding row is less than a 0.5 in myVector. So: myMatrix = a matrix of 8000 by 20 myVector = vector of 8000 myMatrix2 = a matrix of < 8000 by 20 (based on selection criteria in

Hi everyone, I am having some problems with making a new colomn wit data in it. I have this one column named: Fulfilled Fulfilled 1 1 0 1 1 1 1 0 0 1 And now I would like to add another colum to my .csv file ("Finished") In this "Finished" column I would like to have "Yes" or "No". Where in colomn "Fullfilled" is a 1, "Finished"

Hello, I have some "stupid" problems managing "date" data. I have a colomn "date", which I converted from a character representation: for example: a="26/02/06" date=strptime(a,format="%d/%m/%y") For one part of the analysis, I'm interested only in the month and the year, so I did: m.y=strftime(date,format="%m/%y") This returns me

Hello, If a matrix with 5 columns has been defined and the first two columns need to be sorted in ascending order, how can this be achieved whilst ensuring the other 3 columns data are in relative position to the sorted columns? Glen Jones [[alternative HTML version deleted]]

Hello, is ot possible to draw two ecdf of vectors (say s1 and s2) on the same figire with R. plot function draws a new plot and there is no function like points or lines to draw a second ecdf on the figure. Regards -- *PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel: +216 97 246 706 fax: +216 71 391 166* [[alternative HTML version deleted]]