similar to: readLines vs scan

Please, I am receiving lot of e-mails that I do not want. Please could you delete my e-mail. Thank, Judit -----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Thomas Adams Sent: Monday, December 12, 2011 3:22 PM To: Bert Gunter Cc: r-help at r-project.org Subject: Re: [R] Boxplot of multiple vectors with different lengths Bert,

WARNING: COMPLETELY OFF TOPIC -- Nothing to do with R. I thought readers of this list might enjoy the following. The link to the full article is at the bottom. I hope this is not "too" inappropriate. ------- Overconfidence in crime statistics doesn?t pay. In a new study, a team of criminologists makes the case that reported crime rates should acknowledge uncertainty in the data. The

This is a followup to a recent post on using atop() to obtain multiline expressions. My reading of the plotmath docs makes it clear that issuing (in base graphics) the specification par(cex = 2) doubles symbols and regular text in subsequent plotmath expressions. However, it is unclear to me what specifying cex _within_ the annotation function using plotmath should do, and the following seems

Folks: I thought John Nash's comment below was profound and a possible Fortunes candidate: (Aside: I believe it applies to a great deal of what is discussed on this list, not just stochastic optimization.) Cheers, Bert ... (in the context of stochastic optimization) >... As with many tools in this domain, for effective use they > require more knowledge than many of their users

On Thu, Sep 20, 2012 at 9:01 AM, David Winsemius <dwinsemius at comcast.net> wrote: (In response to an OP's aplogy for an "awkwardly worded question"): > Awkwardly worded questions will get much better answers if they are accompanied by some test data. Fortune nomination! Cheers, Bert > -- > David Winsemius, MD > Alameda, CA, USA > >

AdvisoRs: Is the following a bug, feature, hinky error message, or dumb Bert? > mtest <- matrix(1:12,nr=4) > dftest <- data.frame(mtest) > ix <- cbind(1:2,2:3) > mtest[ix] <- NA > mtest [,1] [,2] [,3] [1,] 1 NA 9 [2,] 2 6 NA [3,] 3 7 11 [4,] 4 8 12 ## But ... > dftest[ix] <- NA Error in `[<-.data.frame`(`*tmp*`, ix, value

I will repost on R-devel. -- Bert On Tue, Jul 17, 2012 at 10:32 AM, Prof Brian Ripley <ripley@stats.ox.ac.uk>wrote: > On 17/07/2012 18:20, Bert Gunter wrote: > >> Folks: >> >> sessionInfo() >> R version 2.15.0 (2012-03-30) >> Platform: i386-pc-mingw32/i386 (32-bit) >> >> locale: >> [1] LC_COLLATE=English_United States.1252 >> [2]

Note the edited subject line! I don't know why I typed it as it was before. This says that as.numeric(as.character(f)) will work regardless of the implementation, and I agree. It's the recommendation to use as.numeric(levels(f))[f] that has me wondering about section 2.3.1 of the language definition. I expect that this idiom is in widespread use, and perhaps the language definition

Hi Folks: I'm writing a little package that may not ever hit CRAN or even be distributed beyond a relatively narrow audience at my company. Nevertheless, I have tried to adhere to practices that would work if it were. With that in mind, I have read the Writing R Extensions Manual (and my humble kudos to its writers, as it has successfully guided even an ignoramus like myself ) and Luke

Folks: sessionInfo() R version 2.15.0 (2012-03-30) Platform: i386-pc-mingw32/i386 (32-bit) locale: [1] LC_COLLATE=English_United States.1252 [2] LC_CTYPE=English_United States.1252 [3] LC_MONETARY=English_United States.1252 [4] LC_NUMERIC=C [5] LC_TIME=English_United States.1252 attached base packages: [1] datasets splines grid tcltk stats graphics grDevices [8] utils

Folks: Herein is a suggestion for a little R convenience function mainly to obtain unevaluated ... function arguments. It arose from a query on R-help on how to get these arguments. The standard (I think) idiom to do this is via match.call(expand.dots=FALSE)$... However, Bill Dunlap pointed out that this repeats the argument matching of the function call and suggested a couple of alternatives

Below. -- Bert On Tue, Apr 3, 2012 at 1:47 PM, Danielle Duncan <dlduncan2 at alaska.edu> wrote: > Thanks for the response, I should have clarified that the NOEL is the > smallest dose above which there is a statistically significant effect. > This is not a scientifically meaningful nor defensible definition as it is stochastic, depends on the test used, design, level chosen, etc.

Hi Bert, I won't post any more messages on this thread as problem has shifted from Optimization in R to Graph Algorithms. Rest fine Khris. On Aug 2, 2012, at 9:13 PM, Bert Gunter [via R] wrote: > This discussion needs to be taken off (this) list, as it appears to > have nothing to do with R. > > -- Bert > > On Thu, Aug 2, 2012 at 2:27 AM, khris <[hidden email]>

Folks: Over the years, many people -- including some who I would consider real expeRts -- have criticized factors and advocated the use (sometimes exclusively) of character vectors instead. I would just like to point out that, for me, factors provide one feature that I find to be very convenient: ordering of levels. ** As an example, suppose one has a character vector of labels

... Well, this works in this simple case, but is too clumsy for a general formulation of this problem: given a "dictionary" consisting of two character vectors of unique "names" (or two columns in a data frame), x and y, how does one convert a factor z with levels in x into the corresponding equivalent with levels in y? There are likely a zillion ways to do this with various

Hi Folks: Here's the situation: > m <- cbind(x=letters[1:3], y = letters[4:6]) > m x y [1,] "a" "d" [2,] "b" "e" [3,] "c" "f" ## m is a 2 column character matrix > d <- data.frame(a=1:3,b=4:6) > d$c <- m > d a b c.x c.y 1 1 4 a d 2 2 5 b e 3 3 6 c f ## But please note (as was remarked

Folks: I thought the following excerpt from Bruce McCullough's post would be a good candidate for the R fortunes package -- except that it's about Excel, not R! So I nominate it... but leave it to others to say whether it's really "qualified" to be nominated. ---- "The idea that the Excel solver "has a good reputation for being fast and accurate" does not

Hi, how can I create an array of lists of three components? This approach does not work: n1 <- 2 n2 <- 4 n3 <- 5 res <- array(rep(vector("list",3), n1*n2*n3), dim = c(n1,n2,n3)) res[1,1,1] # is not a list with three components... The goal is that res[1,1,1] is a list with three components. Also, appending the components didn't work. For example, I tried: component

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Hi all, Does anybody know the easiest way to import excel data into R? I copied and pasted the excel data into a txt file, and tried read.table, but R reported that Error in read.table("data_support.txt", sep = " ", header = T) : more columns than column names Thanks! Ling