similar to: ifelse

Dear list, n00b question, but still can't find any easy answer. Here is a df: > df<-data.frame(cbind(x=c("AA","BB","CC","AA"),y=1:4)) > df x y 1 AA 1 2 BB 2 3 CC 3 4 AA 4 I want to modify this df this way : if df$x=="AA" then df$y=df$y*10 if df$x=="BB" then df$y=df$y*25 and so on with other conditions. TY for any

Dear List, I want to compare and return the rows which are NOT in the two data frames. Classic methods don't work as the df have NOT the same dimensions. Here are one example of my df: reported <- structure(list(Product = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 3L, 4L, 5L, 5L), .Label = c("Cocoa", "Coffee C", "GC", "Sugar No 11", "ZS"),

Hello, I am getting mad at finding a simple way to replace elements of a df. Here is a short df : > names<-c("BO","C","CL") > price<-c("10","25","20") > df<-data.frame(names,price) I want to replace "BO" by "BOB", "C" by "CR", "CL" by "CLO", and the list is

Dear list, I am still struggling with something that should be easy: I compare two data frames with a lot of common rows and want to keep only rows that are NOT in both data frames, unique. Here are an example of these data frame. reported <- structure(list(Product = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 3L, 4L, 5L, 5L), .Label = c("Cocoa", "Coffee C", "GC",

Dear group, Here is my df : df <- structure(list(DESCRIPTION = c("PRM HGH GD ALUMINIUM USD 09/07/10 ", "PRM HGH GD ALUMINIUM USD 09/07/10 ", "PRIMARY NICKEL USD 04/06/10 " ), CREATED.DATE = structure(c(18361, 18361, 18325), class = "Date"), QUANITY = c(-1L, 1L, 1L), CLOSING.PRICE = c("2,415.90", "2,415.90",

Dear group, Here is my data frame: > dput(u) structure(list(DESCRIPTION = structure(c(2L, 5L, 6L, 7L, 9L, 11L, 12L, 15L, 14L, 16L, 1L, 10L, 3L, 4L, 13L, 8L, 17L), .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB

Dear group, Here is my environment: > ls() [1] "DailyPL100419" "DailyPL100420" "DailyPL100421" "dd" "i" "l" "PLglobal" "Pos100416" "Pos100419" "Pos100420" "Pos100421" "position" [13] "result" "sel"

Found this solution. It is maybe not the most elegant way, but it does the job. > a=as.data.frame(substr(lme$DESCRIPTION,1,14)) > colnames(a)=c("DESCRIPTION") > lme=as.data.frame(c(a,lme[,2:3])) > lme DESCRIPTION CLOSING.PRICE POSITION 1 PRIMARY NICKEL 25,755.7100 0 2 PRIMARY NICKEL 25,760.8600 0 3 PRM HGH GD ALU 2,415.9000 0

Dear group, Here is my df : df3 <- structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10", "WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD",

Dear group, Here is my df : trade <- structure(list(Trade.Status = c("DEL", "INS", "INS"), Instrument.Long.Name = c("SUGAR NO.11", "CORN", "CORN"), Delivery.Prompt.Date = c("Jul/10", "Jul/10", "Jul/10"), Buy.Sell..Cleared. = c("Sell", "Buy", "Buy"), Volume = c(1L, 2L,

Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",

Dear list, n00b question, but still can't find any easy answer. Here is a df: > df<-data.frame(cbind(x=c("AA","BB","CC","AA"),y=1:4)) > df x y 1 AA 1 2 BB 2 3 CC 3 4 AA 4 I want to modify this df this way : if df$x=="AA" then df$y=df$y*10 if df$x=="BB" then df$y=df$y*25 and so on with other conditions. TY for any

On Mon, Aug 24, 2015 at 11:29 AM, Bj?rn-Helge Mevik <b.h.mevik at usit.uio.no> wrote: > arnaud gaboury <arnaud.gaboury at gmail.com> writes: > >> - Intel MKL: this is part of Intel Parallel Studio and is a paid >> software. Now, there is the MKL package distributed by >> Revolutionanalytics, but I am not certain how this can be distributed >> for free. Is

Dear group, I have this command line in a function: zz<-merge(transform(merge(value,allcon,all.y=T),SHORTDESCRIPTION=NULL,VALUE= NULL,PL=-VALUE*pl,quantity=NULL),PosB,all.x=T,sort=F) I want to cut it in 2 lines (just for convenient purpose). Here is what I did : zz<-merge(transform(merge(value,allcon,all.y=T),SHORTDESCRIPTION=NULL, +

Dear group, Here is my df: avprix <- structure(list(DESCRIPTION = c("CORN Jul/10", "CORN May/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SPCL HIGH GRADE ZINC USD", "STANDARD LEAD USD"), prix = c(-1.5, -1082, 11084, 1983.5, -2464, -118), quantity = c(0, -3, 8, 2, -1, 0), fees = c(-8.64, -30.24, -26.4, -25.92, -37.5,

Dear group, I have a function, let's call it myfun, wich give me a list of result: R1,R2,R3... There is a loop in this function to get my results. Here is the structure of my function: Myfun<-function() { For (i in X ){ -----------instructions--------- Ri { { All Results (R1,R2...) are Data.frame. As a final result (call it "Final"), I need to rbind all these dataframe. One

Dear group, Here is my df (obtained with a read.csv2()): df <- structure(list(DESCRIPTION = c("COTTON NO.2 Jul/10", "COTTON NO.2 Jul/10", "PALLADIUM Jun/10", "PALLADIUM Jun/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10"), CREATED.DATE = c("13/05/2010", "13/05/2010", "14/05/2010",

Dear group, I am losing my mind with a simple question. Sorry if obvious, but I maybe start to be confused after days and days of reading documentations. Df : df <- structure(list(a = 1:3, b = 4:6, c = structure(c(1L, 1L, 1L), class = "factor", .Label = "w")), .Names = c("a", "b", "c"), row.names = c(NA, -3L), class =

Dear group, Here is my environment : > ls() [1] "l" "PLglobal" "Pos100415" "Pos100416" "Pos100419" "Pos100420" "position" "select" "Trad100415" "Trad100416" "Trad100419" "Trad100420" "trade" "y" With objects : > l [1]

On Sat, Dec 5, 2015, 9:39 PM peter dalgaard <pdalgd at gmail.com> wrote: > On 05 Dec 2015, at 18:07 , arnaud gaboury <arnaud.gaboury at gmail.com> wrote: > > In my shell environment, I have set a path to R_PROFILE_USER. The > file, Rprofile.R, is a collection of small hacks. > > I want to build rstudio-server from source. Best is to $ unset > R_PROFILE_USER