Displaying 20 results from an estimated 8000 matches similar to: "Vectorizing a loop"
2007 Dec 04
2
Multiple stacked barplots on the same graph?
Dear R-Users,
I would like to know whether it is possible to draw several
stacked barplots (i.e. side by side on the same sheet)...
my data look like :
Cond1 Cond1' Cond2 Cond2'
Compartment 1 11,81 2,05 12,49 0,70
Compartment 2 10,51 1,98 13,56 0,85
Compartment 3 1,95 0,63 2,81 0,22
Compartment 4 2,08 0,17
2010 Nov 29
1
cross tabulate variables by subject id
Dear list,
I have data like this:
dat1 <- data.frame(subject=rep(1:10,2),
cond1=rep(c("A","B"),each=5),
cond2=rep(c("C","D"),each=10),
choice=sample(0:1,10,replace=TRUE))
I would like to compare subjects' "choice" for (cond1=="A" &
cond2=="C") vs
2016 Nov 02
3
(RFC) Encoding code duplication factor in discriminator
----- Original Message -----
> From: "Dehao Chen" <dehao at google.com>
> To: "Hal Finkel" <hfinkel at anl.gov>
> Cc: "llvm-dev" <llvm-dev at lists.llvm.org>, "Xinliang David Li"
> <davidxl at google.com>
> Sent: Tuesday, November 1, 2016 6:41:29 PM
> Subject: Re: [llvm-dev] (RFC) Encoding code duplication factor in
2017 Jul 24
5
Ifelse statements and combining columns
Hi everyone,
I'm having some trouble with my ifelse statements.
I'm trying to put 12 conditions within 3 groups. Here is the code I have so
far:
dat$cond <- ifelse(test = dat$cond == "cond1" | dat$cond == "cond2" |
dat$cond == "cond3" dat$cond == "cond4"
yes = "Uniform"
no = ifelse(test =
2017 May 22
5
[poison] is select-of-select to logic+select allowed?
Some InstCombine transforms for select-of-select were added here:
https://reviews.llvm.org/rL228409
But Alive says this is more poisonous:
Name: selsel
%s1 = select i1 %cond1, i8 C1, i8 C2
%s2 = select i1 %cond2, i8 %s1, i8 C2
=>
%andcond = and i1 %cond1, %cond2
%s2 = select i1 %andcond, i8 C1, i8 C2
http://rise4fun.com/Alive/JT6
Are those transforms legal?
-------------- next part
2015 Jul 16
3
[LLVMdev] why LoopUnswitch pass does not constant fold conditional branch and merge blocks
Hi,
I have a general question on LoopUnswtich pass.
Consider the following IR snippet:
define i32 @test(i1 %cond) {
br label %loop_begin
loop_begin:
br i1 %cond, label %loop_body, label %loop_exit
loop_body:
br label %do_something
do_something:
call void @some_func() noreturn nounwind
br label %loop_begin
loop_exit:
ret i32 0
}
declare void @some_func() noreturn
After running
2012 Sep 27
2
equivalent of Stata "by construct"
I am evaluating a switch from Stata to R. I don't need to extensive Statistical methods, but the main reason I am exploring the switch is the coding flexibility in R (e.g. Stata does not support linear/quadratic programming). I have been going over the R syntax and I had a quick question:
In Stata, one has a very useful construction called "by", e.g.
by month signal: gen xxx =
2011 May 22
2
Convert dataframe with two factors from wide to long format
I know how to convert a simple dataframe from wide to long format with one
varying factor. However, for a dataset with two factors like the following,
Subj T1_Cond1 T1_Cond2 T2_Cond1 T2_Cond2
1 0.125869 4.108232 1.099392 5.556614
2 1.427940 2.170026 0.120748 1.176353
How to elegantly convert to a long form as
Subj Time Cond Value
1 1 1 0.125869
1
2012 Mar 19
3
Issue with asin()
Hello everyone,
I am working for a few days already on a basic algorithm, very common in
applied agronomy, that aims to determine the degree-days necessary for a
given individual to reach a given growth stade. The algorithm (and context)
is explained here: http://www.oardc.ohio-state.edu/gdd/glossary.htm , and
so I implemented my function in R as follows:
DD <- function(Tmin, Tmax, Tseuil,
2002 Mar 04
2
Plotting a x axis from a vector with rownames
Hi all,
suppose there is a vector y with rownames:
> y
cond1 cond2 cond3 cond4
78.952 87.308 86.490 74.040
how can I easily plot this vector using the rownames? plot(y) gives me a
plot with a x-axis from 1 to 4 in 0.5 steps, also plot(rownames(y), y)
and plot(y ~ rownames(y) don't work. I know I can build a x-axis with
axis(1, ...), but in this case I need a character string like
2007 Oct 10
1
Deleting for() loop in function
Dear UseRs,
I wrote following function in order to solve Data Envelopment Analysis.
Reason for posting is that the function is slow when nrow(dat) is large.
I wonder if other functions could substitute the for() loop in the
code, such as mapply().
Can anybody help to rewrite the dea() function as efficiently as
possible?
The code is as follows:
2016 Nov 02
2
(RFC) Encoding code duplication factor in discriminator
----- Original Message -----
> From: "Dehao Chen" <dehao at google.com>
> To: "Hal Finkel" <hfinkel at anl.gov>
> Cc: "llvm-dev" <llvm-dev at lists.llvm.org>, "Xinliang David Li"
> <davidxl at google.com>
> Sent: Tuesday, November 1, 2016 8:24:30 PM
> Subject: Re: [llvm-dev] (RFC) Encoding code duplication factor in
2016 Nov 01
2
(RFC) Encoding code duplication factor in discriminator
----- Original Message -----
> From: "Hal Finkel via llvm-dev" <llvm-dev at lists.llvm.org>
> To: "Dehao Chen" <dehao at google.com>
> Cc: "llvm-dev" <llvm-dev at lists.llvm.org>, "Xinliang David Li"
> <davidxl at google.com>
> Sent: Tuesday, November 1, 2016 4:26:17 PM
> Subject: Re: [llvm-dev] (RFC) Encoding code
2013 Apr 23
2
Problemas con NA y el calculo de un promedio ponderado
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1
Estimada comunidad, tengo el siguiente problema:
1. tengo un data.frame con varias columnas, algunas numericas, otras son
variables categoricas
2. necesito hacer un calculo simple sobre este data.frame (un promedio
ponderado de los valores de la columna 7), pero solo para las filas que
cumplan ciertos criterios
3. en ocasiones ninguna de las filas
2005 Jul 13
2
Proportion test in three-chices experiment
Hi,
I wish to analyze with R the results of a perception experiment in which
subjects had to recognize each stimulus among three choices (this was a
forced-choice design). The experiment runs under two different
conditions and the data is like the following:
N1 : count of trials in condition 1
p11, p12, p13: proportions of choices 1, 2, and 3 in condition 1
N2 : count of trials in
2009 Sep 04
1
User defined function's argument as Subset function's input
Dear R users,
I have a data where I desire to subset according to certain conditions.
However, the script is very messy as there are about 30 distinct conditions.
(i.e. same script but with different conditions)
I would like to make a user defined function so that I can input the desired
conditions and just get the results accordingly.
Below is an arbitrary data set & sample statements
2016 Nov 04
2
(RFC) Encoding code duplication factor in discriminator
Discussed with Hal, Adrain and Paul offline at the llvm dev meeting today.
* trip count is not enough for vectorization, there is runtime check that
might go false, which can be reflected in profile that we may want to
preserve.
* simply recording these context-profile may cause problems to
iterative-sample-pgo. i.e. when you find a loop's vectorized version no
executed (due to runtime
2012 Nov 07
3
extract indep vars from formula
Hello,
I'm trying to extract the independent variables from a formula. The
closest I've been able to come, aside from rolling my own, is the following:
> a = y ~ b * x
> attr(terms(formula(a)),"variables")
The reason I'm doing this is that I'm building a grid of points that I
use to construct a 3-d model prediction surface in rgl. If there are
more than two
2006 Apr 11
5
multiple select_tag
Hello again,
I have a table called line_items, with the following fields:
id int
item_name varchar()
qty int
conditions text
I''ve made my LineItem model, and everything works as such (with simple
text_fields)..
Now I''d like for the conditions field to be a select_tag() with multiple
choice possibility.
I''m guessing I need some code to expand/restract the array for
2012 Nov 02
2
backreferences in gregexpr
Hi Folks,
I'm trying to extract just the backreferences from a regex.
> temp = "abcd1234abcd1234"
> regmatches(temp, gregexpr("(?:abcd)(1234)", temp))
[[1]]
[1] "abcd1234" "abcd1234"
What I would like is:
[1] "1234" "1234"
Note: I know I can just match 1234 here, but the actual example is
complicated enough that I have to