similar to: Weighted mad

BaselR - The new R meeting We are pleased to announce the new R meeting to be held in Basel, Switzerland. BaselR will be held from 6:30-9:30pm on Tues, Apr 27 at TransBARent: http://transbarent.business.sv-group.ch Doors open at 6:30,pm with the presentations starting at 7:00pm Introduction: What is Basel R? Andreas Krause:... Graphing Pharma Data Yann Abraham: Graphics Charles Roosen: Web

I am pleased to announce to agenda for next weeks LondonR meeting: LondonR meeting - 13th July 2010 Date:?? ???????? Tuesday 13th July 2010 Time:??????????? 6pm - 9pm Venue:????????? The Shooting Star ??????????????????? 125 - 129 Middlesex Street ??????????????????? E1 7JF ??????????????????? (Nearest Tubes- Liverpool Street, Moorgate or Bank)? Agenda 6.00pm???????? Mango

Hi, Anybody can tell me why I don't have colors in my picture? library(lattice) my.pch<-c(17,16,15,18,20,9,10,12) my.fill<-c('yellow','black','green','red','blue','cyan','magenta','pink') wzorzec1<- c(1,3,2,4,6,4,2,3) wzorzec2<- c(5,3,6,6,2,3,4,1) a<-factor(wzorzec1) b<-factor(wzorzec2)

## Not run: from <- sprintf("<sendmailR@ to <- "<olafm at datensplitter.net>" subject <- "Hello from R" msg <- "It works!" sendmail(from, to, subject, msg, control=list(smtpServer="ASPMX.L.GOOGLE.COM")) ## End(Not run) the above commands are provided in this document ie http://cran.r-project.org/web/packages/sendmailR/sendmailR.pdf

Greetings to all, and my apologies for a question that is mostly about statistics and secondarily about R. I have just started a new job that (this week, apparently) requires statistical knowledge beyond my training (as an epidemiologist). The problem: - We have 57 food production facilities in three categories - Samples of 4-6 different foods were tested for listeria at each facility - I need

There are still places available on the following courses. For more detailed information and a registration form please contact training@mango-solutions.com, or visit our website at www.mango-solutions.com <http://www.mango-solutions.com/> . R for Finance **************************************************** Dates: 21st to 23rd October 2008. Duration: 3 days. Location: London.

Dear all, Lattice provides automatic coloring for subgroups on each panel by the simple use of a groups statement. For an application I want to change these colors to a predifined set. This works well using a panel function in stead of the default as long as there are only points in the graphs. When I set type="b" things get messed up. Any idea why? I include sample code for

Dear R-users, I am trying to make a plot with ggplot-geom_tile(), but cannot remove some unwanted (white) lines through my plot. Below a reproducible example: ##### library(ggplot2) tot=as.data.frame(rep(seq(-50,50,5),each=21)) names(tot)="precip" temp=rep(seq(-5,5,0.5),21) tot$temp=temp disc=array(dim=c(21,21)) for(i in 1:21){ for(y in 1:21){ temp<-

Hello R-Experts, I've got a question, concerning the automation of a number of regressions (lm) with the help of a loop (for i in ....). The situation is as follows (the code follows after that): I have my data in an access database. I have historical data for 2000 parts, for each of this parts I want to do a regression analysis, so I need to do 2000 regressions (just for one country, there

Dear All wonder if you could provide some insights on the following: currently I have this code which produces the expected results: require(deSolve) pars <- list(k = 0.08,v=15) intimes <- c(0,0.5,12) input <- c(800,0,0) forc <- approxfun(intimes, input, method="constant", rule=2) derivs <- function(t, state, pars) { inp <- forc(t) dy1 <- - pars$k * state[1]

Following problem: Say you have a bunch of parameters and want to produce results for all combinations of those: height<-c("high","low") width<-c("slim","wide") then what i used to do was something like this: l<-list() for(h in height){ l[[h]]<-list() for(w in width){ l[[h]][[w]] <- doSomething() } } Now those parameters aren't

Hi, i am working on bar plot but i need to generate y axis for horizontal bar plot. In the attached diagram x-axis is there with scale 0 to 12 but i need y axis. How can i implement it? http://r.789695.n4.nabble.com/file/n4630478/barplot2.jpg Thanks -- View this message in context: http://r.789695.n4.nabble.com/How-to-create-axis-y-axis-for-horizontal-bar-plot-tp4630478.html Sent from the

Dear All, I would wish to make multiple plots and give title/ headings same time, is there a simpler/ tidier way compared to below(, especially the headings as they are missing)? See output attached. #####################################Making multiple Plots start######################## plot(mybrick9, y = 2, col = terrain.colors( length(seq(0,1, by = .2))-1),breaks= seq(0, 1, by = 0.2), axes =

Hello all, i'm a newbie to R and now I get stuck by the question, would anybody help me please? Suppose, I got the following > test <- data.frame(test1=c(c(0.00, 0.005, 0.01, 0.015, 0.02))) > test test1 1 0.000 2 0.005 3 0.010 4 0.015 5 0.020 Now I want another column inside test, named test2 for i=c(1:5), If test$test1[i] is 0, then the value of test$test2[i] is 1/test1[i] or

Hello. Is it possible to find the Jordan Form of a matrix with R? Arnau. ------------------------------------------------------------ Arnau Mir Torres Edifici A. Turmeda Campus UIB Ctra. Valldemossa, km. 7,5 07122 Palma de Mca. tel: (+34) 971172987 fax: (+34) 971173003 email: arnau.mir at uib.es URL: http://dmi.uib.es/~arnau

On Thursday 21 April 2016 15:12:52 Juergen Gross wrote: > On 21/04/16 12:57, Pali Roh?r wrote: > > On Tuesday 05 April 2016 21:31:52 Pali Roh?r wrote: > >> On Tuesday 05 April 2016 16:54:14 Guenter Roeck wrote: > >>> On Tue, Apr 05, 2016 at 07:10:07AM +0200, Juergen Gross wrote: > >>>> Use the smp_call_on_cpu() function to call system management >

On Thursday 21 April 2016 15:12:52 Juergen Gross wrote: > On 21/04/16 12:57, Pali Roh?r wrote: > > On Tuesday 05 April 2016 21:31:52 Pali Roh?r wrote: > >> On Tuesday 05 April 2016 16:54:14 Guenter Roeck wrote: > >>> On Tue, Apr 05, 2016 at 07:10:07AM +0200, Juergen Gross wrote: > >>>> Use the smp_call_on_cpu() function to call system management >

It might be a bit faster to do matrix indexing: R> tbm <- as.matrix(tb) # turn it into a character matrix R> tmat[cbind(match(tbm[,2], rownames(tmat)), match(tbm[,1], colnames(tmat)))] <- 1 > tmat Apple Orange Mango Grape Star A 1 1 1 0 0 O 1 1 0 0 0 M 0 0 1 0 0 G 0 0 0 0 0 S 1 1 1 0

Dear R users, Could somebody please help me to find a way of comparing nonlinear, non-nested models in R, where the number of parameters is not necessarily different? Here is a sample (growth rates, y, as a function of internal substrate concentration, x): x <- c(0.52, 1.21, 1.45, 1.64, 1.89, 2.14, 2.47, 3.20, 4.47, 5.31, 6.48) y <- c(0.00, 0.35, 0.41, 0.49, 0.58, 0.61, 0.71, 0.83, 0.98,

hi: I have matrix with dimensions(200 X 20,000). I have another file, a tab-delim file where first column variables are row names and second column variables are column names. For instance: > tmat Apple Orange Mango Grape Star A 0 0 0 0 0 O 0 0 0 0 0 M 0 0 0 0 0 G 0 0 0 0 0 S 0 0 0 0 0