similar to: iterating through for loop

I need to get the names of the list elements when I iterate over a list. I'm wondering how to do so? alist=list(a=c(1,3),b=c(-1,3),c=c(-2,1)) sapply(alist,function(x){ #need to use the name of x for some subsequent process })

>> Just a quick question: what's the difference between `[.Date` and `[[.Date`? >> Is it supposed to be the method for accessing the value right? > >For Dates and atomic vectors in general they are the same, but ... Even for atomic vectors with names they are not quite the same > c(One=1, Two=2)[[2]] [1] 2 > c(One=1, Two=2)[2] Two 2 (and [[ will

i want to compare two variables (having numbers) serially for matching/dismatching both having equal length > x [1] 2 2 1 2 3 2 2 2 2 3 3 2 2 2 2 2 2 3 2 2 2 2 2 2 2 2 2 2 3 2 3 2 2 2 1 2 2 [38] 2 2 2 3 2 3 2 2 1 2 2 2 2 1 1 1 3 2 2 2 2 1 1 3 1 1 1 2 2 2 3 2 3 3 3 2 2 [75] 2 2 3 2 2 1 1 1 2 3 2 2 2 2 2 2 2 2 2 1 1 3 2 2 2 2 2 2 2 2 2 2 2 1 3 > y [1] 2 2 2 1 3 1 3 2 1 3 3 3 3 2 2 1 2 3

Hi there, I would like to ask something about how to avoid a possible error message within a for loop. I am running a simulation and in some repetitions there may be an error that will cause a crash and stop the whole procedure, what I want is to simply move on to the next iteration automatically and discard the "bad" repetitions from my results. I used the "try" function to

I am not sure if this is a bug or not. Gabor On Wed, Aug 12, 2015 at 11:51 AM, Luca Cerone <luca.cerone at gmail.com> wrote: > Following up on this, should I report a bug? can you drive me through > the process? > > Cheers, > Luca > > On Thu, Aug 6, 2015 at 4:55 PM, William Dunlap <wdunlap at tibco.com> wrote: >>>> Just a quick question: what's

Thanks G?bor, I thought there was some mistake in my logic on how casting works in R and wanted to be sure. Just a quick question: what's the difference between `[.Date` and `[[.Date`? Is it supposed to be the method for accessing the value right? Thanks again for your help, Cheers, Luca On Thu, Aug 6, 2015 at 10:10 AM, G?bor Cs?rdi <csardi.gabor at gmail.com> wrote: > Date has a

Hi all, I have a bunch of int vectors. Each vector holds a bunch of ints that correspond to row numbers of an existing matrix. I use the int vectors to pull out rows of data from a matrix, i.e. data <- my_matrix[int_vector,] I would like to store these int vectors in some sort of data structure that will preserve them as-is and allow iteration. I guess what I'm looking for would be

Hello, I'm an R newbie and was wondering whether there are R commands for iterating over files in a directory. Basically what I want to do is to iterate over many files and apply some R functions to each file seperately. e.g. for (each file in a directory) do { some R calculation with the info in that file } Could someone please give me a pointer to how (or if) this might be done with R

I have a controller that gets a list of employees (which has an "include => [:salaries, :incentives, :billablegoals, :reviews]"). I then need it to iterate through each employee and determine their current active goal based on the "effective date." After playing around with it a bunch, I got the following to work. Only problem is that if I remove the "@employees.each {

I have noticed that when I iterate permutations of short vectors with the same seed, the cycle lengths are much shorter than I would expect by chance. For example: X <- 1:10 Xorig <- X start <- 112358 N <- 10 for (i in 1:N) { seed <- start + i for (j in 1:1000) { # Maximum cycle length to consider set.seed(seed) # Re-seed RNG to same initial state X <- sample(X)

Hi Boris, Do a search on "the order of elements of the symmetric group". (This search will also turn up homework questions and solutions.) You will understand why you are seeing this once you understand how a permutation is decomposed into cycles and how the order relates to a partition of n (n=10 in your case). Enjoy! Eric On Fri, Dec 8, 2017 at 6:39 AM, Boris Steipe <boris.steipe

Greetings! I''m new to Ajax and am trying to get a basic app working as a vehicle for learning it. The app is an extension of the cookbook tutorial. My intent is to be able to add a list of ingredients for a recipe. The page to add ingredients uses Ajax. As ingredients are added to the page they''re displayed in a "green-bar" format like that used in the Depot

On Wed, Aug 12, 2015 at 10:55 AM, G?bor Cs?rdi <csardi.gabor at gmail.com> wrote: > I am not sure if this is a bug or not. > I would argue that this isn't a bug, not even in the documentation of "for" (even though it might be clearer). ?"for" says that `seq` is "[A]n expression evaluating to a vector (including a list and an expression) or to a pairlist or

i know RCurl pakage to retrieve web content,it has limited use, i want interactive package like (in perl--->Mechanize, In java--->Watij,Prowser,HTMLunit,HTTPunit, in Ruby---->Watir ,etc) this modules/packages opens appropriate browser,which can create queries,retrieves output, clicks buttons, fill up form automatically,searches keyword in search engine, Downloads many items from

Perl has Mechanize module which browse web pages through programming(coding),creates queries & retrives data through it which R package support web browsing through programming -- View this message in context: http://r.789695.n4.nabble.com/which-R-package-is-used-for-browsing-web-pages-through-coding-tp4368349p4368349.html Sent from the R help mailing list archive at Nabble.com.

> h<-array() > h [1] NA > append(h,9) [1] NA 9 but what it append......... > h [1] NA -- View this message in context: http://r.789695.n4.nabble.com/how-to-append-element-at-last-position-in-array-dynamically-tp4427893p4427893.html Sent from the R help mailing list archive at Nabble.com.

I want to do the following declare variable: $usernames = [ "chris", "bob", "tim" ] How would I iterate over it to create something like: user { "$username": home => "/home/$username", } Also is it possible to create a more complex structure with $UID and $Shell I''m thinking of something like this: $users

how to avoid writing index of variable in write.table command, e.g. output---> index,character,state "1" "M" "2" "2" "K" "3" "3" "R" "1" "4" "E" "1" "5" "S" "1" "6" "H" "1" "7" "K" "1"

i m searching on net,material related to R, whenever i get ppt presentation of some topic ,i found it in speical format white backgroud & blue bars,having links for further topics see link 1) https://www.rmetrics.org/files/Meielisalp2007/Presentations/Pfaff.pdf 2)http://grapevine.com.au/~yanchang/docs/Time-Series-Mining-slides.pdf If this is format,how can i made it,if i want to give my R

i have following numbers 0.889046409368551 1.22726162946495 1.22726162946495 1.35785109728356 1.35785109728356 1.10704609982913 1.4424189950435 1.2277843378837 1.35785109728356 0.970883941918588 0.822170913920467 1.35785109728356 0.358815782262543 0.774234247460432 0.822170913920467 0.822170913920467 0.72599976881814 0.671583894425946