similar to: Contour plot with messy field data.

Displaying 20 results from an estimated 1000 matches similar to: "Contour plot with messy field data."

2005 Dec 13
2
How to make a plot?
Does anyone have an idea of how to make a chart in R like the ones here that use a graphic: http://bigpicture.typepad.com/comments/images/slide1.gif
2013 Jul 18
1
Bland Altman summary stats for all column combinations
Hello, I have the following data.frame structure(list(Study = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L,
2012 Jul 06
4
differences between survival models between STATA and R
Dear Community, I have been using two types of survival programs to analyse a data set. The first one is an R function called aftreg. The second one an STATA function called streg. Both of them include the same analyisis with a weibull distribution. Yet, results are very different. Shouldn't the results be the same? Kind regards, J -- View this message in context:
2012 Aug 02
2
Correlating different sets of variables?
This is a fairly entry level question - so any guidance on this would be appreciated... I have two sets of residuals, one of 100 values (A), and one of 10,000 values (B). There are 50 paired sets of these values. The data is in the form of two matrices (100x50 and 10,000x50). The goal is to correlate the residuals from A and B, to identify a those B values that go up when a single A value goes
2017 Dec 14
2
help with recursive function
Hi, I need some help with running a recursive function. I like to run funlp2 recursively. When I try to run recursive function in another function named "calclp" I get this "Error: any(!dat2$norm_sd) >= 1 is not TRUE". I have never built a recursive function before so having trouble executing it in this case. I would appreciate any help or guidance to resolve this issue.
2017 Dec 14
0
help with recursive function
You seem to have a typo at this expression (and some others like it) Namely, you write any(!dat2$norm_sd) >= 1 when you possibly meant to write !( any(dat2$norm_sd) >= 1 ) i.e. I think your ! seems to be in the wrong place. HTH, Eric On Thu, Dec 14, 2017 at 3:26 PM, DIGHE, NILESH [AG/2362] < nilesh.dighe at monsanto.com> wrote: > Hi, I need some help with running a
2017 Dec 14
2
help with recursive function
My own typo ... whoops ... !( any(dat2$norm_sd >= 1 )) On Thu, Dec 14, 2017 at 3:43 PM, Eric Berger <ericjberger at gmail.com> wrote: > You seem to have a typo at this expression (and some others like it) > > Namely, you write > > any(!dat2$norm_sd) >= 1 > > when you possibly meant to write > > !( any(dat2$norm_sd) >= 1 ) > > i.e. I think your !
2017 Dec 14
2
help with recursive function
Hi, I accidently left out few lines of code from the calclp function. Updated function is pasted below. I am still getting the same error ?Error: !(any(data1$norm_sd >= 1)) is not TRUE? I would appreciate any help. Nilesh dput(calclp) function (dataset) { dat1 <- funlp1(dataset) recursive_funlp <- function(dataset = dat1, func = funlp2) { dat2 <- dataset %>%
2017 Dec 14
0
help with recursive function
Eric: Thanks for taking time to look into my problem. Despite of making the change you suggested, I am still getting the same error. I am wondering if the logic I am using in the stopifnot and if functions is a problem. I like the recursive function to stop whenever the norm_sd column has zero values that are above or equal to 1. Below is the calclp function after the changes you suggested.
2017 Dec 14
0
help with recursive function
The message is coming from your stopifnot() condition being met. On Thu, Dec 14, 2017 at 5:31 PM, DIGHE, NILESH [AG/2362] < nilesh.dighe at monsanto.com> wrote: > Hi, I accidently left out few lines of code from the calclp function. > Updated function is pasted below. > > I am still getting the same error ?Error: !(any(data1$norm_sd >= 1)) is > not TRUE? > > >
2017 Dec 14
3
help with recursive function
If you are trying to understand why the "stopifnot" condition is met you can replace it by something like: if ( any(dat2$norm_sd >= 1) ) browser() This will put you in a debugging session where you can examine your variables, e.g. > dat$norm_sd HTH, Eric On Thu, Dec 14, 2017 at 5:33 PM, Eric Berger <ericjberger at gmail.com> wrote: > The message is coming from
2008 Feb 08
1
Can I index a dataframe with a reference from/to a second dataframe?
Hello, I am unable to figure out how to code a new column in a data frame based on an existing column that matches a column in a reference data frame, in a relational-db fashion. I would like this to maintain a minimum set of reference tables that may be reused over several similar datasets. Specifically, I have two data frames as listed below, 'Bos' and 'tree.' For each case in
2017 Dec 14
0
help with recursive function
Eric: I will try and see if I can figure out the issue by debugging as you suggested. I don?t know why my code after stopifnot is not getting executed where I like the code to run the funlp2 function when the if statement is TRUE but when it is false, I like it to keep running until the stopifnot condition is met. When the stopifnot condition is met, I like to get the output from if statement
2017 Dec 14
1
help with recursive function
Your code contains the lines stopifnot(!(any(data1$norm_sd >= 1))) if (!(any(data1$norm_sd >= 1))) { df1 <- dat1 return(df1) } stop() "throws an error", causing the current function and all functions in the call stack to abort and return nothing. It does not mean to stop now and return a result. Does the function give
2017 Nov 07
1
fill histogram in ggplot
Hi all, I have the following data and I have a histogram for mms like ggplot(hist,aes(x=hist$mms))+ geom_histogram(binwidth=1,fill="white",color="black")and then I want to fill the color of histogram by probable=1 and probable=0, could anyone help me in this? My data: structure(list(probable = c(1L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 1L,
2018 Mar 12
1
Help on Aggregation
Dear All, 1.I have been trying to aggregate my data but I have not been getting it correctly. In the data I want to convert hourly data into daily averages. Here is a sample of the data: Neph_no Date Time Temp_C Pressure_kPa RH 9 2014/03/28 10:00:00 38.4 95.9 29.7 9 2014/03/28 11:00:00 37.8 95.8 29.2 9 2014/03/28 12:00:00 36.7 95.8 35.1 9 2014/03/28 13:00:00 35.4 95.8 38.9 9
2017 Dec 06
2
Odd dates generated in Forecasts
Dear friends, I have a weekly time series which starts on Jan 4th, 2003 and ends on december 31st, 2016. I set up my ts object as follows: MyTseries <- ts(mydataset, start=2003, end=2016, frequency=52) MyModel <- auto.arima(MyTseries, d=1, D=1) MyModelForecast <- forecast (MyModel, h=12) Since my last observation was on december 31st, 2016 I expected my forecast date to start on
2017 Dec 06
0
Odd dates generated in Forecasts
> On Dec 6, 2017, at 5:07 AM, Paul Bernal <paulbernal07 at gmail.com> wrote: > > Dear friends, > > I have a weekly time series which starts on Jan 4th, 2003 and ends on > december 31st, 2016. > > I set up my ts object as follows: > > MyTseries <- ts(mydataset, start=2003, end=2016, frequency=52) > > MyModel <- auto.arima(MyTseries, d=1, D=1)
2017 Dec 06
1
Odd dates generated in Forecasts
Thank you very much David. As a matter of fact, I solved it by doing the following: MyTimeSeriesObj <- ts(MyData, freq=365.25/7, start=decimal_date(mdy("01-04-2003"))) After doing that adjustment, my forecasts dates started from 2017 on. Cheers, Paul 2017-12-06 12:03 GMT-05:00 David Winsemius <dwinsemius at comcast.net>: > > > On Dec 6, 2017, at 5:07 AM, Paul
2008 Jul 06
2
lattice question
I'm creating a lattice barchart based off a pretty complicated data structure. The barchart comes out quite nice ( thanks to lattice ) but the problem is that the horizontal axis comes out all scrunched because the barchart doesn't know that the intervals of Var.1 are really "associated" with the conditioning variable Var.2. Therefore, all the intervals of Var.1 are put on