similar to: generate a random number with rexp ?

Hello, How can I make a monte carlo simulation on R? Regards Adel -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel: +216 97 246 706 (+33640302046 jusqu'au 15/6) fax: +216 71 391 166 [[alternative HTML version deleted]]

Hi list I loaded the content of a file dureetasks.txt to variable a. This file contains an interger per line. when I print a vector, it displays correctly. however, when I try to print the histogram, I get this error message > a=read.table("dureetasks.txt") > hist(a) Error in hist.default(a) : 'x' must be numeric Can you help please? regards -- PhD candidate in

Hello > orderulcount Group.1 Group.2 Group.3 x V5 7 C L 0.0 30 C / L 19 C L 0.2 27 C / L 31 C L 0.4 15 C / L 43 C L 0.6 7 C / L 54 C L 0.8 2 C / L 10 C S 0.0 27 C / S 22 C S 0.2 10 C / S 34 C S 0.4 6 C / S 46 C S 0.6 1 C / S 1 D

Hello, I have a file with very big values. I want to display the real values with classic ways (without exposant) > summary(a[,1]); Min. 1st Qu. Median Mean 3rd Qu. Max. 1.198e+09 1.199e+09 1.200e+09 1.200e+09 1.201e+09 1.202e+09 Can you help please? Regards Adel -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel:

Hello, I want to create 10 dataframe using a for loop. I don t know what to do to create 10 different dataframes whose name is parametrized with variable i. This syntaxe fails. It create a unique fataframe called dfn. Any input will help Thanks > for (i in 1:10){ + filename=paste("avail4",i,sep = "_") + dfn=read.table(filename) + } -- PhD candidate in Computer Science

Deal list > I want to generate a random number in an interval using exponential low > I know how to make that simply using uniform low > x1 <- runif(1, 5.0, 7.5) > this will generate a number between 5 et 7.5 but with uniform low. > Could you help pease.? > Regards > > -- > PhD candidate in Computer Science > Address > 3 avenue lamine, cité ezzahra, Sousse 4000

Hello, I have a problem with ggplot and colors I used this function to draw somes lines and I want them to be all black (just to test) however, I dont get any black line in the figure. Do you have any experience with ggplot and manual colors?? ggplot(cmax, aes(cmax[,3], cmax[,6],colour=interaction(cmax[,1],cmax[,2]))) + geom_line() + geom_point() +

Hi list I am a new user of R. I ask for some "beginner" question I am searching if there is any function that computes the variation of some discrete values of a vector (mean() and sd() exists, but i have not find variation). Thanks in advance Adel -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel: +216 97 246 706 (+33640302046

Hi list I need some help for drawing some histograms I have a dataframe , say, X Y Z T I want to draw a histogram Z-T for each value of the couple (X-Y). When I use thus syntax > library(lattice) > histogram(law[,3] ~ law[,66] | law[,1] ) it draws multiple histograms but by selecting distinct values of law[,1] The deal is to make the same thing but for a couple of columns Thanks in

Hello, is ot possible to draw two ecdf of vectors (say s1 and s2) on the same figire with R. plot function draws a new plot and there is no function like points or lines to draw a second ecdf on the figure. Regards -- *PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel: +216 97 246 706 fax: +216 71 391 166* [[alternative HTML version deleted]]

Hello, I have a question about how R can run automatically. Here is the story: A file called "data.csv" will be generated every couple of minutes in a folder (overwrite itself). What I want R to do is: 1) scan the folder to find the file. 2) if the file is a newly generated file, process the file 3) output some file identifier on the screen, such as the time when the file was

Hello list I have this file 0 121289479 25 0 212599129 1 0 285254098 21 0 444889848 45 0 469197123 30 0 640007403 82 0 718215617 8 0 758534043 56 0 799706577 4 0 814441385 93 0 843545059 37 0.2 121289479 6 0.2 285254098 3 0.2 444889848 6 0.2 469197123 13 0.2 640007403 24 0.2 718215617 3 0.2 758534043 2 0.2 799706577 2 0.2

Hello I am using this command to draw the figure attached to this mail. xyplot(g[,4]~g[,3],type="b",group=interaction(g[,1],g[,2]), auto.key =list( title="Evolution de la stabilit?" , points = FALSE, columns=2, lines = TRUE,space="right") ,data=g,xlab=expression(beta),ylab="stabilit?") I want to change name of the legend that were attributed

Does anyone know if R have any problems with the exponential random number generation (function rexp)? I comment it because I executed data<-sort(rexp(100)) plot(data,dexp(data)/(1-pexp(data)),type="l") and the graphic isn't constant. (Note: exponential distribution have a constant hazard failure rate). Thank you, Juan

Hi list I am discovering R, and -- PhD candidate in Computer Science Address 3 avenue lamine, cité ezzahra, Sousse 4000 Tunisia tel: +216 97 246 706 (+33640302046 jusqu'au 15/6) fax: +216 71 391 166 [[alternative HTML version deleted]]

Hi everybody, while performing ks.test for a standard exponential distribution on samples of dimension 2500, generated everytime as new, i had this strange behaviour: >data<-rexp(2500,0.4) >ks.test(data,"pexp",0.4) One-sample Kolmogorov-Smirnov test data: data D = 0.0147, p-value = 0.6549 alternative hypothesis: two.sided >data<-rexp(2500,0.4)

I am using rexp to generate several exponential distributions. I am passing rexp a vector of rates , r. I am wanting to simulate a sample of size 200 for each rate so the code looks like: rexp(n=200*length(r),rate=r) this gives me a vector of the random exponential variables, but they are all disjointed b/c rexp goes through and simulates an exponential variable for each rate and it does that 200

In splus rexp() and rweibull() are related: > set.seed(153) > rexp(1) [1] 0.0493267 > set.seed(153) > rweibull(1, shape=1) [1] 0.0493267 (you can also try shape =2, then rweibull = sqrt(rexp) ) However, in rw0.64.1 (on Win NT) they are different > .Random.seed <- 1:4 > rexp(1) [1] 1.412030 > .Random.seed <- 1:4 > rweibull(1, shape=1) [1] 2.054032 May be rweibull

Dear userRs, "playing around" with combinations of replicate() and random number generating functions inside a self-defined "wrapper" function I encounterd a puzzling behaviour. The following are intentionally simple (and rather nonsense-) examples to isolate the relevant aspects. Please, note the seemingly "inconsistent" behaviour for the second call of

Hi all, I just run into this today. Apparently rexp() sometimes gives different slightly results for the same seed on 32 bit and 64 bit machines. runif() is the same for both, so the problem seems to be in rexp(). 64 bit Linux is the same as 64 bit OSX, and R-devel gives the same results as R-3.0.2. Best, Gabor # --------------------------------------------- > options(digits=22) ;