Displaying 20 results from an estimated 30000 matches similar to: "Establishing groups using something other than ifelse()"
2008 Oct 09
2
Bug in ifelse
Hi all, I am quite sure it's not a bug, but I am going nuts about this. I do
not possibly understand why I get different results for b1 and b2 as shown
below.
x=c(183,191,192,193,195,206,207,209,210,211,212,213,214,217,218,221,222,223,
224,225,227,228,229,230)
y=c(221,225,228,241,242)
z=y[y<max(x)] ##all Ys smaller than the maximum of X
a=ifelse(length(z)==0,NA,max(z)) ##assign NA if
2010 Apr 03
2
Using ifelse and grep
Good Morning,
I am trying to create a new column of character strings based on the first
two letters in a string in another column. I believe that I need to use some
combination of ifelse and grep but I am not totally sure how to combine
them. I am not totally sure why the command below isn't working. Obviously
it isn't finding anything that matches my criteria but I am not sure why.
Any
2009 Feb 13
2
extracting parts of words or extraxting letter to use in ifelse-func.
Hello
I want to make some variables with the ifelse-function, but i don't know how
to do it.
I want to make these five variables;
b2$PRRSvac <- ifelse(b2$status=='A' | b2$status=='Aa',1,0)
b2$PRRSdk <- ifelse(b2$status=='B' | b2$status=='Bb',1,0)
b2$sanVac <- ifelse(b2$status=='C' | b2$status=='sanAa',1,0)
b2$sanDk <-
2013 May 29
3
bootstrap
Hi,
You might need to check library(boot).? I have never used that before.? So, I can't comment much.? It is better to post on R-help list.? I had seen your postings on Nabble in the past.? Unfortunately those postings were not accepted in R-help.? You have to directly post at ? r-help at r-project.org after registering at:
https://stat.ethz.ch/mailman/listinfo/r-help
?
2012 Apr 25
1
Create a new Vector based on two columns
Hello,
I am trying to get a new vector 'x1' based on the not NA-values in
column 'a' and 'b'. I found a way but I am sure this is not the best
solution. So any ideas on how to "optimize" this would be great!
m <- factor(c("a1", "a1", "a2", "b1", "b2", "b3", "d1", "d1"), ordered
2004 Jun 12
1
optimize linear function
I am attempting to optimize a regression model's parameters to meet a specific
target for the sum of positive errors over sum of the dependent variable
(minErr below).
I see two courses of action , 1) estimate a linear model then iteratively
reduce the regressors to achieve the desired positive error threshold
(naturally the regressors and predicted values are biased - but this is
2010 Mar 20
2
EM algorithm in R
Please help me in writing the R code for this problem. I've been solving this
for 4 days. It was hard for me to solve it. It's a simulation problem in R.
The problem is
My true model is a normal mixture which is given as
0.5 N(-0.8,1) + 0.5 N(0.8,1). This model has two components.
I will get a random sample of size 100 from this model. I will do this 300
times.
That means, I will have
2009 Feb 19
2
Use of ifelse for indicating specific rownumber
Hello
I have a dataset named "b2" with 1521 rows, in that dataset i have 64 rows
containing specific information.
the rownumbers with specific info are:
+ i
[1] 22 53 104 127 151 196 235 238 249 250 263 335 344 353
362 370 389 422 458 459 473 492 502 530 561 624 647 651 666
671
[31] 715 784 791 807 813 823 830 841 862 865 1036 1051 1062 1068
2011 Jul 26
2
Big data and column correspondence problem
Greetings,
I've been struggling for some time with a problem concerning a big database
that i have to deal with.
I'll try to exemplify my problem since the database is really big.
Suppose I have the following data:
AA = c(4,4,4,2,2,6,8,9)
A1 = c(3,3,5,5,5,7,11,12)
A2 = c(3,3,5,5,5,7,11,12)
A = cbind(A, A1, A2)
BB = c(2,2,4,6,6)
B1 =c(5,11,7,13,NA)
B2 =c(3,12,11,NA,NA)
B3
2012 Apr 25
1
Create new Vector based on two colums
Hello,
I am trying to get a new vector 'x1' based on the not NA-values in
column 'a' and 'b'. I found a way but I am sure this is not the best
solution. So any ideas on how to "optimize" this would be great!
m <- factor(c("a1", "a1", "a2", "b1", "b2", "b3", "d1", "d1"), ordered
2009 Jan 29
4
Text in a character vector to indicate "ifelse" argument
Hello
I have a data set that looks like this;
> b2
dato chr status PRRSvac
PRRSsanVac PRRSsanDk PRRSdk
33 2007-12-03 090432 R?d SPF
34 2007-02-09 090432 R?d SPF+sanDK
35 2002-12-17 090432 R?d SPF+DK
36 2002-11-27 090432 R?d SPF+sanDK
37 2002-07-23
2012 Oct 15
2
fit a "threshold" function with nls
I am trying to model a dependent variable as a threshold function of
my independent variable.
What I mean is that I want to fit different intercepts to y following 2
breakpoints, but with fixed slopes.
I am trying to do this with using ifelse statements in the nls function.
Perhaps, this is not an appropriate approach.
I have created a very simple example to illustrate what I am trying to do.
2013 Jan 24
3
ifelse to speed up loop?
Hello,
I'm not sure how to explain what I'm looking for but essentially I have a
test dataset that looks like this:
test:
V1
1 1
2 1
3 1
4 2
5 2
6 2
7 1
8 1
9 1
10 2
11 2
12 2
And what I want to be able to do is create another column that captures a
"grouping" variable that looks like this:
test
V1 group
1 1 1
2 1 1
3 1 1
4 2 2
5 2
2013 Oct 18
1
crr question in library(cmprsk)
Hi all
I do not understand why I am getting the following error message. Can
anybody help me with this? Thanks in advance.
install.packages("cmprsk")
library(cmprsk)
result1 <-crr(ftime, fstatus, cov1, failcode=1, cencode=0 )
one.pout1 = predict(result1,cov1,X=cbind(1,one.z1,one.z2))
predict.crr(result1,cov1,X=cbind(1,one.z1,one.z2))
Error: could not find function
2013 Apr 13
1
how to add a row vector in a dataframe
Hi,
Using S=1000
and
simdata <- replicate(S, generate(3000))
#If you want both "m1" and "m0" #here the missing values are 0
res1<-sapply(seq_len(ncol(simdata.psm1)),function(i) {x1<-merge(simdata.psm0[,i],simdata.psm1[,i],all=TRUE); x1[is.na(x1)]<-0; x1})
res1[,997:1000]
#????? [,1]???????? [,2]???????? [,3]???????? [,4]???????
#x1??? Numeric,3000 Numeric,3000
2012 Sep 07
6
splitting character vectors into multiple vectors using strsplit
Hi folks,
Suppose I create the character vector charvec by
> charvec<-c("a1.b1","a2.b2")
> charvec
[1] "a1.b1" "a2.b2"
and then I use strsplit on charvec as follows:
> splitlist<-strsplit(charvec,split=".",fixed=TRUE)
> splitlist
[[1]]
[1] "a1" "b1"
[[2]]
[1] "a2" "b2"
I was wondering
2003 Nov 18
1
aov with Error and lme
Hi
I searched in the list and only found questions
without answers e.g.
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/19955.html
: Is there a way to get the same results with lme as
with aov with Error()?
Can anybody reproduce the following results with lme:
id<-c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5,1,1,1,2,2,2,3,3,3,4,4,4,5,5,5,1,1,1,2,2,2,3,3,3,4,4,4,5,5,5)
2009 Nov 29
3
Plotting observed vs. Predicted values, change of symbols
Dear Wiz[R]ds,
I am deeply grateful for the help from Duncan Murdoch, Gray Calhoun, and
others. We are almost there. For whatever reason, I can't change the symbol
from a circle to a triangle in the upright posture plots. Any ideas? I have
included the problem in full.
# tritiated (3H)-Norepinephrine(NE) disappearance from plasma
# concentrations supine and upright
# supine
datasu <-
2013 Sep 26
2
Sums based on values of other matrix
Dear all,
I have a big problem:
- I got two matrices, A and B
- A shows identifies the value of B, however the values of B must be summed
- For instance,
1 1 2 2
2 2 1 1
gives matrix a
3 4 2 1
1 1 2 2
gives matrix b
Now the result for the value 1 would be
7
4
which are the rowsums of the values of matrix B given that matrix A has the value 1.
How can I do this automatically? I
2013 Feb 23
1
how to calculate left kronecker product?
For an application, I have formulas defined in terms of a left Kronecker
product of matrices,
A,B, meaning
A \otimes_L B = {A * B[i,j]} -- matrix on the left multiplies each
element on the right.
The standard kronecker() function is the right Kronecker product,
A \otimes_R B = {A[i,j] * B} -- matrix on the right multiplies each
element on the left.
The example below shows the result of