Displaying 20 results from an estimated 700 matches similar to: "Time series questions"
2001 May 06
1
legend/text in time series plot
hi,
i need help on placing legend/text in a time series plot. here is what
i am doing (i am using rw1022 on windoze 2000):
#read data file
gdpn <- scan("jngdpsa.dat", list(year=0, qtr=0, gdp=0));
gdpr <- scan("jrgdpsa.dat", list(year=0, qtr=0, gdp=0));
#convert to time series object
gdpn <- ts(gdpn$gdp, frequency=4, start=c(1955,2));
gdpr <- ts(gdpr$gdp,
2008 Nov 22
1
declaring constants in an Sweave / LaTeX document
List,
I would like to set a variable to hold, say, the size of my plots in a
Sweave document. i.e. something like the following in my '.Rnw' file:
==============================================================================
smallPlotSize = 4
<<fig1, echo=false, results=hide, height=smallPlotSize, width=smallPlotSize,
fig=true>>=
dat <- read.table("
2011 Jun 03
4
Problem using read.xls - Everything converted to factors
Hallo,
I would like to use to read.xls function from the gdata package to read
data from Microsoft Excel files but I experienced a problem: For example
I used the following code:
testfile<-read.xls("/home/.../wsjecon0603.xls", #file path
header=F,
dec=",",
na.strings="n.a.",
skip=5,
sheet=2,
2004 Apr 14
3
A bug report?
Folks,
I have a strange situation, which I may have isolated as a bug
report. Or, it could just be that there's something about R that I
don't know. :-) I have attached the data file and the program file but
don't know whether these attachments will make it into the list. Here
is my bugreport.R program --
---------------------------------------------------------------------------
2001 Sep 24
3
x axis point labels
I am attempting to manually specify x axis value labels (NOT x axis label as
in xlab) on a density plot. Generally speaking, I would like to erase the
default x axis point labels and replace them with arbitrary x axis point
labels relating to specific CDF points.
I am sure this can be done, but it isn't obvious to me how. Has anyone done
this before?
My R code follows if it helps (new
2011 Dec 07
1
removing specified length of text after a period in dataframe of char's
Dear all,
I'm trying to remove some text after the period (a decimal point) in
the data frame 'hi', below. This is one step in formatting a table. So
I would like e.g.
"2.0" to become "2"
and "5.3" to be "5.3",
where the variable digordered contains the number of digits after the
decimal that I would like to display, in the same order in which
2012 Oct 22
0
"Vars" package: impulse response function
Hello,
I'm using VAR models in R in order to obtain impulse responses of stock
market shock on US economy.
I have series of quarterly changes in real gdp, S&P 500 and quarterly level
of unemployment for 1985 - 2012 period.
My series are stationary. So I did all the steps below. However I don't
understand what do irf function results mean. These are the cumulative
orthogonal responses
2007 Apr 25
0
sorting data help
I am trying to create a 2x2xk contingency table. The variables are GDP and
an income inequality statistic with year being the k levels. I want to
eventually run a loglinear model with the data. Currently the data is
organized by either year or country. example
Country Year log(GDP) sqrt(INEQ)
1 1980 24 5.3
1 1981 25 5.45
1
2008 Jan 30
2
numeric coercion when one or more elements is non numerice
I don't understand this behavior. Why does the every data point get trashed by data.matrix when there is one non-numeric element in the array? Thanks.
> temp
GDP CPIYOY
19540 2098.1 garbage
19632 2085.4 0.9
19724 2052.5 0.8
19814 2042.4 1.1
> data.matrix(temp)
GDP CPIYOY
19540 4 4
19632 3 2
19724 2 1
19814 1
2011 Nov 16
1
geom_bar with missing data in package ggplot
Dear all,
I was hoping someone could help with a ggplot question. I would like
to generate a faceted bar chart, but missing data are causing
problems.
g<-structure(list(Date = structure(c(11322, 11687, 12052, 11322,
11687, 12052, 11322, 11687, 12052, 11322, 11687, 12052), class = "Date"),
variable = c("Govt Revenues to GDP", "Govt Revenues to GDP",
2012 Jun 24
2
Defining multiple variables in a loop
Good day,
For lack of a better solution (or perhaps I am ignorant to something
more elegant), I have been bootstrapping panel data by hand so to
speak and I would like to know if there is a way to define multiple
variables in a loop using the loop variable. I found a post (here:
https://stat.ethz.ch/pipermail/r-help/2002-October/026305.html ) that
discussed naming multiple variables but it
2002 Jun 14
1
data.frame - transform
Hi there,
I have a data.frame (pwt6) which I would like to transform:
country year gdp
MEX 1950 2
MEX 1951 5
BOL 1950 4
BOL 1951 12
ITA 1950 45
ITA 1951 2
This should be the result:
year MEX.gdp BOL.gdp ITA.gdp
1950 2 4 45
1951 5 12 2
Right now I have this code (better - no code):
country.label<-names(table(pwt6$country))
result<-data.frame(year=NULL)
for(i in country.label)
?
2012 Apr 30
5
Different varable lengths
Hi!
I'm trying to do a lm() test on three objects. My problem is that R protests
and says that the variable lengths differ for one of the objects
(Sweden.GDP.gap). But I have double checked that the number of observations
are the same. All three objects should contain 9 observations but R only
accepts 9 observations in two of the objects. The third must have 10! Very
confusing because there
2003 Oct 04
2
(no subject)
Dear all,
I have the following question. I have to fit the hierarchical model for the
hypothesis concern the individual-level effects by controlling for the
individual -level attributes and national-level contextual effects on
individuals by using R.
O have to obtain the estimates of the impact of the second-level (national:
GDP per capita) effects on individuals ( in this instance the impact
2017 May 20
2
[PATCH] drm: remove NULL pointer check for clk_disable_unprepare
After long term efforts of fixing non-common clock implementations,
clk_disable() is a no-op for a NULL pointer input, and this is now
tree-wide consistent.
All clock consumers can safely call clk_disable(_unprepare) without
NULL pointer check.
Signed-off-by: Masahiro Yamada <yamada.masahiro at socionext.com>
---
drivers/gpu/drm/etnaviv/etnaviv_gpu.c | 15 +++++----------
2011 Aug 04
1
Running a column loop through the Moran.I function.
Dear R users,
I have two data frames that consist of statistical information for most
countries around the world. One dataframe consists of the latitude and
longitude ("coord.csv") of each country, while the other consists of 100's
of different attributes ("countryattri.csv") for each country (like, GDP,
Population, etc.). The data is organized with a header and then
2011 Jun 26
2
Accessing variables in a data frame
Hello
My data.frame (dat) contains many variables named var.names and others
named var.names_var.id
For example
var.name <- c("gdp","inf","unp")
var.id <- c("w","i")
x <- paste(var.name, rep(var.id, each=length(var.name)), sep="_")
How can I access variables in the dama.frame by names listed in x, for
example to compute
2013 May 03
1
Likelihood
Hi all,
I have run a regression and want to calculate the likelihood of obtaining
the sample.
Is there a way in which I can use R to get this likelihood value?
Appreciate your help on this.
The following are the details:
raw_ols1=lm(data$LOSS~data$GDP+data$HPI+data$UE)
summary(raw_ols1)
Call:
lm(formula = data$LOSS ~ data$GDP + data$HPI + data$UE)
Residuals:
Min 1Q
2013 May 04
2
Lasso Regression error
Hi all,
I have a data set containing variables LOSS, GDP, HPI and UE.
(I have attached it in case it is required).
Having renamed the variables as l,g,h and u, I wish to run a Lasso
Regression with l as the dependent variable and all the other 3 as the
independent variables.
data=read.table("data.txt", header=T)
l=data$LOSS
h=data$HPI
u=data$UE
g=data$GDP
matrix=data.frame(l,g,h,u)
2011 Sep 21
1
Strucchange gbreakpoints
Hi,
I am a new user to R.
I am using strucchange to generate breakpoints:
--------------------------------------------------------------------------------------
> res <- gbreakpoints(GDP.new ~ 1,data=a,h=2,breaks=5)
> print(res)
Optimal 6-segment partition for `lm' fit:
Call:
gbreakpoints(formula = GDP.new ~ 1, data = a, h = 2, breaks = 5)
Breakpoints at observation number: