Displaying 8 results from an estimated 8 matches similar to: "manipulating data of several columns simultaneously"
2012 Jan 11
3
Accomplishing a loop on multiple columns
Hello,
I have a question concerning ?for loops? on multiple columns.
I made 91 columns with results (all made together with a for loop) and I
want to us lm to fit the model.
I want to compare the results of all these calculated columns (91) with one
column with observed values. I use the function lm to fit the model and
calculate r.squared. I manage to do this for each column separately:
For
2012 Jan 17
2
result numeric(0) when using variable1[which(variable2="max(variable2)"]
Dear all,
I have a question about the knowing for which row I have the max value of
one of my variables.
I calculated the Rsquared for different columns and made a list to gather
them. I unlisted this list to create a vector with this values. I want to
know for which column I have the max value of Rsquared.
The columns were always named in the same way. They always start with
results4$depth_
2012 Jun 05
1
nls: how do you know if the model is significant?
Hi all,
I'm struggling with nls. How do you know if your model is significant? For a
lm, you get a p-value, but you don't get it for a nls. Is there a way to
calculate it?
For a lm I use this:
a<-summary(lm(model ~obs))
f.stat<-a$fstatistic
p.value<-1-pf(f.stat["value"],f.stat["numdf"],f.stat["dendf"])
Is there something similar for a nls?
2012 Feb 13
2
different way for a for loop for several columns?
Hi,
I have a question about repeating something for several columns. I
calculated a lot of values for different objects. The values are normally
calculated step-wise for every day for each object. With this obtained data
frame, I make further calculations. Here I have to calculate some things and
I have to take into account the years because I want a number for each year.
I do these first for one
2012 Jun 04
2
Non-linear curve fitting (nls): starting point and quality of fit
Hi all,
Like a lot of people I noticed that I get different results when I use nls
in R compared to the exponential fit in excel. A bit annoying because often
the R^2 is higher in excel but when I'm reading the different topics on this
forum I kind of understand that using R is better than excel?
(I don't really understand how the difference occurs, but I understand that
there is a
2012 Mar 13
1
size of graphs when using multiple figures by row
Hi all,
I have a basic question concerning graphs in R. I?m using the par()
function and I?m working with multiple figures by row (mfrow) but my the
hight of my figures become compressed. I have 4 rows and 2 columns (because
I want to plot 8 histograms (freq = FALSE ) on it. I know I can adapt my
margins with for example ?oma? and ?mai? but I don?t know how to choose the
size of the figure? I
2012 Feb 20
1
apply with as function ifelse with 2 logical conditions
Hi all,
I have a question concerning using several conditions in an ifelse function
used as the function in apply.
I want to create a new value with the function ifelse ? object which can be
coerced to logical mode ?test[n,] >1 & test[n-1,]==0?
With n I mean the row. I don?t know how I could do this without a loop. I
want to avoid the usage of loops and was thinking about apply. This
2012 Feb 15
2
function similar to ddply? + calculations based on previous row
Hi all,
I was wondering if there is a function kind of similar that splits a
dataframe, applies a function to each row and returns in a data frame. I
know ddply but this one isn?t useful in this situation.
I have a dataframe with values for each day (rows) for different objects
(columns). I have values for several years. Now, I want to do calculations
on only the data of that year. With the