similar to: Reshape with multiple aggregate functions

Displaying 20 results from an estimated 8000 matches similar to: "Reshape with multiple aggregate functions"

2012 Jan 18
3
Reshape with multiple aggregation functions
I have a data frame and I would like to reshape it to wide format while at the same time applying different aggregate functions to each column AND at times multiple aggregate functions:   test1 = data.frame(         id = c(rep('101',8),rep('102',8)),         phase  = rep(c('D','D','L','L'),4),         day =
2013 Jan 11
2
Merging list of dataframes with reshape merge_all
Hi, I'd like to merge mutliple dataframes from a list of dataframes by some common columns. The approach for simply merging 2 dataframes is working with: merge(df1,df2,by=c("col1","col2","col3"),all=TRUE) For mutliple dataframes in a list I try to use the merge_all command from the package reshape. The documentation states that the command takes a list of
2009 Oct 21
2
How to average subgroups in a dataframe? (not sure how to apply aggregate(..))
Dear all, Lets say I have the following data frame: > set.seed(1) > col1 <- c(rep('happy',9), rep('sad', 9)) > col2 <- rep(c(rep('alpha', 3), rep('beta', 3), rep('gamma', 3)),2) > dates <- as.Date(rep(c('2009-10-13', '2009-10-14', '2009-10-15'),6)) > score=rnorm(18, 10, 3) > df1<-data.frame(col1=col1,
2008 Nov 06
3
Reshape a matrix
Dear R users, I have a matrix like A X 1 B Y 2 C Z 3 I want to reshape this matrix into this format X Y Z A 1 B 2 C 3 Thanks in advance for your help. Dinesh -- Dinesh Kumar Barupal Junior Specialist Metabolomics Fiehn Lab UCD Genome Center 451 East Health Science Drive GBSF Builidng University of California DAVIS 95616
2011 Mar 16
3
making dataframes
Dear all, I have a dataframe which looks like this (dummy): date<-c("jan", "feb", "mar", "apr", "may", "june", "july", "aug","sep","oct","nov","dec") col1<-c(8.2,5.4,4.3,4.1,3.1,2.5,1.1,4.5,3.2,1.9,7.8,6.5) col2<-c(3.1,2.3,4.7,6.9,7.5,1.1,3.6,8.5,7.5,2.5,4.1,2.3)
2013 Jan 11
3
split & rbind (cast) dataframe
Hi, I would like to split dataframe based on one colum and want to connect the two dataframes by rows (like rbind). Here a small example: # The orgininal dataframe df1 <- data.frame(col1 = c("A","A","B","B"),col2 = c(1:4), col3 = c(1:4)) # The datafame how it could look like df2 <- data.frame(A.col2 = c(1,2), A.col3 = c(1,2), B.col2 = c(3,4), B.col3
2010 Jul 16
2
aggregate(...) with multiple functions
hi all - i'm just wondering what sort of code people write to essentially performa an aggregate call, but with different functions being applied to the various columns. for example, if i have a data frame x and would like to marginalize by a factor f for the rows, but apply mean() to col1 and median() to col2. if i wanted to apply mean() to both columns, i would call: aggregate(x, list(f),
2011 Sep 26
1
producing an aggregate table of top 3 by cost
Help-Rs   As someone who is newer to R and trying to make the transition from Access into R, there is a frequetnly used function that I'd like to try and duplicate in the R world.  It involved creating an aggregate table of the top (n)  orders for an item by sum of cost over a select period of time.   So, take the following example :   group <- c(rep(1,10), rep(2,10), rep(3,10)) product
2006 Mar 06
1
Sort problem in merge()
Hello! I am merging two datasets and I have encountered a problem with sort. Can someone please point me to my error. Here is the example. ## I have dataframes, first one with factor and second one with factor ## and integer > tmp1 <- data.frame(col1 = factor(c("A", "A", "C", "C", "0", "0"))) > tmp2 <- data.frame(col1 =
2017 Aug 23
0
Comparing 2 dale columns
Patrick, ## Run the following script an notice the different values of the dataframe "data" in each instance. # I understand you have done something like the following: data <- data.frame(COL1 = c("6/1/14", "7/1/14"), COL2 = c("5/1/15", "5/1/15"), stringsAsFactors = FALSE) data$Date_Flag <- ifelse(data$COL2 >
2020 Sep 13
2
Cambiar datos de un DF
Hola: Si codificas "col1" como un factor, lo puedes cambiar todo de una vez renombrando los niveles correspondientes: > df$col1<-as.factor(df$col1) > df$col1  [1] uno   dos   3     4     cinco 6     siete 8     9     diez Levels: 3 4 6 8 9 cinco diez dos siete uno > levels(df$col1)[1:5] <-
2018 Feb 27
3
Aggregate over multiple and unequal column length data frames
Thank you Pikal and Bert. My apology for posting parts of my previous email in HTML. Bert's suggestion will work but i am wondering if there is an alternative especially in the case where the data frames are big; that is the difference in lengths among them is large. Below is a list of sample date frames and desired result. EK
2005 Oct 07
2
finding missing lines...
Take this as an example: > a=data.frame(col1=c(1,2,3,4,5), col2=c ("my","beloved","daughter","son","wife")) > b=data.frame(col1=c(1,2,4), col2=c("my","beloved","son")) > a col1 col2 1 1 my 2 2 beloved 3 3 daughter 4 4 son 5 5 wife > b col1 col2 1 1 my 2
2018 Feb 25
2
include
HI Jim and all, I want to put one more condition. Include col2 and col3 if they are not in col1. Here is the data mydat <- read.table(textConnection("Col1 Col2 col3 K2 X1 NA Z1 K1 K2 Z2 NA NA Z3 X1 NA Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE) The desired out put would be Col1 Col2 col3 1 X1 0 0 2 K1 0 0 3 Y1 0 0 4 W1 0 0 6 K2 X1
2018 Feb 25
0
include
Jim has been exceedingly patient (and may well continue to be so), but this smells like "failure to launch". At what point will you start showing your (failed) attempts at solving your own problems so we can help you work on your specific weaknesses and become self-sufficient? -- Sent from my phone. Please excuse my brevity. On February 25, 2018 7:55:55 AM PST, Val <valkremk at
2018 Feb 25
0
include
Hi Val, My fault - I assumed that the NA would be first in the result produced by "unique": mydat <- read.table(textConnection("Col1 Col2 col3 Z1 K1 K2 Z2 NA NA Z3 X1 NA Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE) val23<-unique(unlist(mydat[,c("Col2","col3")])) napos<-which(is.na(val23)) preval<-data.frame(Col1=val23[-napos],
2006 Mar 16
3
Did I use "step" function correctly? (Is R's step() function reliable?)
Hi all, I put up an exhaustive model to use R's "step" function: ------------------------ mygam=gam(col1 ~ 1 + col2 + col3 + col4 + col2 ^ 2 + col3 ^ 2 + col4 ^ 2 + col2 ^ 3 + col3 ^ 3 + col4 ^ 3 + s(col2, 1) + s(col3, 1) + s(col4, 1) + s(col2, 2) + s(col3, 2) + s(col4, 2) + s(col2, 3) + s(col3, 3) + s(col4, 3) + s(col2, 4) + s(col3, 4) + s(col4, 4) + s(col2, 5) + s(col3,
2018 Feb 25
3
include
Thank you Jim, I read the data as you suggested but I could not find K1 in col1. rbind(preval,mydat) Col1 Col2 col3 1 <NA> <NA> <NA> 2 X1 <NA> <NA> 3 Y1 <NA> <NA> 4 K2 <NA> <NA> 5 W1 <NA> <NA> 6 Z1 K1 K2 7 Z2 <NA> <NA> 8 Z3 X1 <NA> 9 Z4 Y1 W1 On Sat, Feb 24, 2018 at 6:18 PM, Jim
2018 Feb 25
0
include
hi Val, Your problem seems to be that the data are read in as a factor. The simplest way I can think of to get around this is: mydat <- read.table(textConnection("Col1 Col2 col3 Z1 K1 K2 Z2 NA NA Z3 X1 NA Z4 Y1 W1"),header = TRUE,stringsAsFactors=FALSE) preval<-data.frame(Col1=unique(unlist(mydat[,c("Col2","col3")]))[-1], Col2=NA,col3=NA) rbind(preval,mydat)
2010 May 13
1
merge for data.frame and matrix
Hello, how to merge a data.frame and a matrix by one column in the data.frame and rownames of the matrix? df <- data.frame(col1=c("kk","yy","kk"),col2=c(6,4,3)) > df   col1 col2 1   kk    6 2   yy    4 3   kk    3 m<-matrix(c(3,8,56,9), nrow=2, dimnames = list(c("aa","kk"),c("col1","col2"))) > m    col1 col2 aa