similar to: read.zoo problems

I am willing to help the community by creating .deb package files for Wine as soon as the source is released. I will links to the file here. I use Mediafire as my uploading host. Wine 1.4 Stable can be downloaded here http://www.mediafire.com/?7zi68cw59qzkawl (32bit) I'll compile a 64bit version only if people request it. ------------------------------------- Future releases will be listed

Hi, this is related to academic research I am trying to conduct. Please pardon my lack of socialization for this forum. For my project, I had to combine two different datasets, Democracy dataset from Pippa Norris and World Bank Patents dataset. My issue arrises from just loading the file into R. My colleagues proficient in R have been stumped as well. Often times the file would seem to load

I'm doing: > alyL32007z <- zoo(alyL32007,alyL32007$time) > range(time(alyL32007z)) [1] "2007-01-01 00:00:00 UTC" "2007-12-31 23:30:00 UTC" But then, while the original variable is: > summary(alyL32007$NEE_st) Min. 1st Qu. Median Mean 3rd Qu. Max. NA's -15.340 -1.615 -0.054 -0.814 0.750 8.965 11124 the variable within the zoo object

Forgot to add the tcpdump command used: tcpdump -p -s 0 -n -w /root/tcpdump_all.txt Pawel. wt., 5 maj 2020 o 00:01 pavlos <pavlos.audiofreak at gmail.com> napisa?(a): > OK, have repeated the test: > > - samba logs: > http://www.mediafire.com/file/jy4qcyvqg6z39zu/logs.tar.gz/file > - tcpdump log: >

I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe. d <- rep(20110101,24) h <- seq(from = 0, to = 2300, by = 100) df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1)) S <- chron(dates. = as.character(df$LST_DATE), times. = paste(as.character(df$LST_TIME/100), ":0:0", sep = ""), format =

Dear R community, I have the following two zoo objects: MONTHLY CPI > plot(z) > par("usr") [1] 1977.76333 2011.15333 70.39856 227.03744 > z=zooreg(cpius$Value,as.yearmon("1979-11"),frequency=12) > str(z) ?zooreg? series from Nov 1979 to Oct 2010 Data: num [1:372] 76.2 77 77.8 78.5 79.5 80.3 81.1 82 82 82.6 ... Index: Class 'yearmon' num [1:372]

I have the following time series: > class(CCasadesz2) [1] "zoo" > setmanes <- cut(time(CCasadesz2),breaks="weeks") > CCasadeswz <- aggregate(CCasadesz2,sum,by=setmanes) > class(CCasadeswz) [1] "zoo" > summary(CCasadeswz) Index CCasadeswz 2009-01-12 00:00:00: 1 Min. : 4.0 2009-01-19 00:00:00: 1 1st Qu.:

I have a zoo object that contains 2 time series named "A-B" and "V1". When I create a third series "V2", the name of the "A-B" series is changed to "A.B". Although I could recreate the names for the 3 series I am wondering if there is a way of preventing the name change from happening ( ... maybe an equivalent of the keep.names=TRUE statement

Hello all, I'm trying to use zoo.read but can't figure out how to deal with the time format. (example below) would be nice if someone could help. best regards, Immanuel --------------------------- L <- "Date,Time,Open,High,Low,Close,Up,Down 05.02.2001,00:30,421.20,421.20,421.20,421.20,11,0 05.02.2001,01:30,421.20,421.40,421.20,421.40,7,0

#Is there a way to break the below zoo object into non-NA data frames algorithmically #this is a small example of a much larger problem. #It is really no even necessary to have the continuous chunks #end up as zoo objects but it is important to have them end #up with the index column. #thanks for all of your help in advance, and #if you need anything else please let me know library(zoo) ind.

Hello everyone, a problem with the plot.zoo function. In the parameters of the function, cex.lab is ignored. I tried to reduce the size of the yaxis labels by at least 50%. ------------------ Example: sample <- as.zoo(EuStockMarkets) par(las=1) plot.zoo(sample, plot.type="multiple", main="Time Series", xlab="Date", yaxt="n", cex.lab=0.5,

When I try to convert the zoo object to a timeSeries object, which would allow me to utilize Rmetrics packages, I get an error message. > Data<-read.zoo("c:\\DOWUBSPRICING.txt,na.strings="NA",sep="\t",header=T) > is(Data) "zoo" > as.timeSeries.zoo(Data) Error in .local (.Object, . ) Is this happening because I am using daily data?

Just trying to create returns from prices, and do something like: returns.z = tail(prices.z,-1)/head(prices.z,-1) - 1 # should be equivalent to returns = exp(diff(log(prices.z))) - 1 Curiously, I get a zoo object back with zeros everywhere and also with the index having one fewer element than it should. Does anyone know how to pointwise divide zoo objects, and what exactly "/" is

Here's my script: http://pastebin.com/zx3TCtXg I want to draw attention to the code block where the read in of the raw data is located. Is there a function that filters out unwanted data with respect to a ceiling limit. For example, I want to remove any value over 500 kW in the rawCool variable. Any ideas where to go with that? I figure it would be an argument within read.zoo or an external

Dear all, please consider my following workbook: library(zoo) lis1 <- vector('list', length = 2) lis2 <- vector('list', length = 2) lis1[[1]] <- zooreg(rnorm(20), start = as.Date("2010-01-01"), frequency = 1) lis1[[2]] <- zooreg(rnorm(20), start = as.yearmon("2010-01-01"), frequency = 12) lis2[[1]] <- matrix(1:40, 20) lis2[[2]] <-

Is there a easy way to create the time index for a zoo/xts object for every 100 milliseconds. eg. time Index would be: 10:00:00:100 10:00:00:200 10:00:00:300 10:00:00:400 I am looking to build an empty zoo/xts object with time index from 10am to 3pm, index jumps by 100ms each row. Thanks, Chris -- View this message in context:

plot.ts has an argument yax.flip, plot.zoo does not. Is there a way to make the yaxis flip in plot.zoo? I tried using a custom panel function: panel.yaxis<-function(...) { npnl<-parent.frame$panel.number if (npnl %% 2 == 0) { axis(side=3) } else { axis(side=2) } } This leads to a blank window. I am stuck with the intricacies of the plotting and axis

Dear all, I know that it is a silly question, but I have a zoo object like this: valor1 valor2 01/02/08 36.7381 17.0097 01/03/08 36.9296 16.8331 01/04/08 35.6934 16.3539 01/07/08 35.3539 16.3791 01/08/08 36.3811 16.9340 01/09/08 37.9220 17.6655 The name is nuevo.zoo and I need to extract the data for a giving day, for example for 01/03/08 and for the

Why doesn't this work? x = zoo(1:5, as.Date('2001-01-01')+1:5) x[as.Date('2001-01-05')] x[as.Date('2001-01-05')] = 0 x I think this is especially bad because it doesn't cause an error. It lets you do something to x, but then you can't see x again to see what it did. [[alternative HTML version deleted]]

I'm trying to read intraday zoo but running into issues (again) ... what am I missing here? (the date doesn't seem to read in correctly) > head(dat) TrdDate TrdTime impliedVol 1 20090102 09:55:03 0.3610715 2 20090102 09:55:04 0.3637943 3 20090102 09:55:05 0.3752375 4 20090102 09:55:05 0.4190025 5 20090102 09:55:06 0.3696080 6 20090102 09:55:06 0.4944981 > f <-