Displaying 20 results from an estimated 5000 matches similar to: "question about groups"
2023 Mar 20
1
Cleanup permission settings / traverse folder
Hello,
I have problems removing the permission settings on a directory/folder after configuration of a share.
My folders look like:
/var/folder1/folder2/
I created share1 on folder1 and share2 on folder2.
Afterwards, I activated ACLs and set permission on folder1 to domain/group1 and on folder2 to domain/group2.
I couldn't access share2 with a user from group2 and I figured out that Samba
2023 Mar 20
1
Cleanup permission settings / traverse folder
On 20/03/2023 16:58, Rowland Penny via samba wrote:
>
>
> On 20/03/2023 16:22, Thomas Hoffmann (Speed4Trade GmbH) via samba wrote:
>> Hello,
>> I have problems removing the permission settings on a directory/folder
>> after configuration of a share.
>>
>> My folders look like:
>> /var/folder1/folder2/
>>
>> I created share1 on folder1 and
2011 Mar 11
2
insertion of a row between individuals
Can someone help with a fairly simple task?
I have a data set where I would like to insert a 0 time event between
individuals:
what I have:
VAR DATE TIME CONC COVAR
1 NOV2 0.25 10 group1
1 NOV2 0.5 20 group1
1 NOV2 1 5 group1
1 NOV2 2 1 group1
1 NOV2 3 0.1 group1
2 NOV2 0.25 10
2011 Nov 03
1
Reclassify string values
Hi All,
Is there a simple way to convert a string such as c("A", "B" ,"C", "D")
to a string of c("Group1", "Group1", "Group2", "Group2"). Naturally I
could use the factor function as below but I don't like seeing that
warning message (and I don't want to turn off warning messages). Perhaps
a function
2005 Apr 20
1
negative p-values from fisher's test (PR#7801)
Full_Name: Martha Nason
Version: 2.0.1
OS: Windows XP
Submission from: (NULL) (137.187.154.154)
I am running simulations using fisher's test on 2 x c tables and a very small
p.value from fisher's test (<2.2e-16) is returned as a negative number. Code
follows.
> set.seed(0)
> nreps.outer <-7
> pvalue.fisher <- rep(NA,nreps.outer)
>
> population1 <- c(
2009 Sep 20
2
missing level of a nested factor results in an NA in lm output
Hello All,
I have posted to this list before regarding the same issue so I
apologize for the multiple e-mails. I am still struggling with this
issue so I thought I'd give it another try. This time I have included
reproducible code and a subset of the data I am analyzing.
I am running an ANOVA with three factors: GROUP (5 levels), FEATURE
(2 levels), and PATIENT (2 levels), where
2008 Mar 12
1
[smb.conf] "browseable = no EXCEPT valid users" possible ?
Hello,
I'm looking for a solution to my problem :
i have a samba server with ldap auth on Debian ETCH.
I need to configure this samba for multi-group and multi-users.
Example :
user 1 (from group1) have to see his own directory (for writing), his
group' directory (for writing and sharing) but also the "homes" of
others users from this group...
user2 (from group2)
2011 Apr 30
1
More flexible aggregate / eval
Dear list,
I would like to do some calculation using different grouping variables.
My 'df' looks like this:
# Some data
set.seed(345)
id <- seq(200,400, by=10)
ids <- sample(substr(id,1,1))
group1 <- rep(1:3, each=7)
group2 <- rep(1:2, c(10,11))
group3 <- rep(1:4, c(5,5,5,6))
df <- data.frame(id, ids, group1, group2, group3)
df <- rbind(df, df, df)
df$time <-
2011 Feb 09
1
Questions about dovecot-shared in 1.2 and inherit group membership from parent mailbox
Hi,
I read the Wiki about dovecot-shared a few times but it is not 100%
clear to me (at least for 1.2).
First, if I want shared keywords I *must* have a dovecot-shared. In this
case, the permissions are not taken any longer from the parent folder
(what is exactly this parent folder?) but from the dovecot-shared file.
So in some sense dovecot-shared is always required (since everyone would
2005 Feb 23
1
How to conctruct an inner grouping for nlme random statement?
Hello. Im hoping someone can help with a grouping
question related to the "random=" statement within the
nlme function. How do you specify that some grouping
levels are inner to others? I tried several things,
given below.
Lets say I have a data frame with five variables,
resp, cov1, ran1, ran2, group1, and group 2. The
formula is resp~cov1 + ran1 + ran2, where the ran are
random
2011 Jun 01
2
Samba + ACL + Linux Client
Hello,
I'm Oliver and I need help for a experiment.
I have a sharing with Samba version 3.2.5, my distribution Linux is
Debian(Lenny) and the acl version is 2.2.47.
Below my configurations files:
#/etc/fstab
/dev/sda3 /shared reiserfs defaults,acl 0 1
#smb.conf
[data]
comment = files
path = /shared
inherit acls = yes
inherit permissions = yes
map acl inherit = Yes
#
2009 Mar 03
2
Reshape
Hi all,
I would like to transform to long format a matrix which has only
information about individuals and a value for each individual. I would like
to have it in ling format with more information related to groups, so ell
values and individuals are repeated for each group. Let me show the example:
matrix in wide format:
Individuals Value
A 3
B 4
C 5
D 2
And long format would
2010 Jul 27
1
Multiple Workgroups and Subnets
Hi,
I am configuring a network with two subnets with a different workgroup
in each subnet. My aim is to have users being able to view and access
shares on both workgroups. I have a Samba server in each
subnet/workgroup, configured as both the domain and local master for
each workgroup. Each server is also the WINS server for its subnet. The
setup is like this:
Subnet1:
network -
2010 Jul 15
1
Auto directory creation not working
Hello,
I am experiencing problems with auto directory creation for user shares.
I have samba instance that is authenticated against samba PDC, on PDC i have 2 groups, group1 and group2.
What i want to do now is to have separate folders for user shares for each group.
so /mnt/share/group1/user1 would be for user1 in group 1 and /mnt/share/group2/user2 would be folder for user2 in group 2
root
2005 Jun 24
1
lme4 extracting individual variance components
Hi,
For further calculations I need to extract indivdual Variances of
different random effects from a fitted model.
I found out how to extract the correlations
(VarCorr(m1)@reSumry$group1) but I was not able to find a way to
extract the other components individually.
To extract the Residuals I tried: (ranef(m1)@ stdErr) which
unfortunately did not work.
Thank you very much for your help!
2008 Oct 02
2
aggregate empty row for pretty appearance also subtotal if possible
Hi,
To pretty print aggregates by various dimensions I needed to add a
empty row in output of aggregate.
For example.
d<-(aggregate(data[,cbind("x")], by=list(data$group1,data$group2),
sum))
Group.1 Group.2 x
1 A N 3
2 A Y 2
3 B N 420164905
Is there a way to add an empty
2011 Apr 04
2
merging 2 frames while keeping all the entries from the "reference" frame
Hello!
I have my data frame "mydata" (below) and data frame "reference" -
that contains all the dates I would like to be present in the final
data frame.
I am trying to merge them so that the the result data frame contains
all 8 dates in both subgroups (i.e., Group1 should have 8 rows and
Group2 too). But when I merge it it's not coming out this way. Any
hint would be
2011 Jul 14
2
cbind in aggregate formula - based on an existing object (vector)
Hello!
I am aggregating using a formula in aggregate - of the type:
aggregate(cbind(var1,var2,var3)~factor1+factor2,sum,data=mydata)
However, I actually have an object (vector of my variables to be aggregated):
myvars<-c("var1","var2","var3")
I'd like my aggregate formula (its "cbind" part) to be able to use my
"myvars" object. Is it
2012 Nov 09
2
Passing an array of user groups to a define
As I try to get some flexibility in the creation of users, I switched to a
define.
problem is, I can''t pass an array of user groups anymore. This either
results in
- wrong group creation: group1,group1group2,group2 (see that group1 and
group2 are concatenated in the middle, undefined group)
- error: Group names must be provided as an array, not a comma-separated
list.
I use the
2010 May 27
1
median test
Hi all,
I have found the following function online
median.test<-function(y1,y2){
z<-c(y1,y2)
g <- rep(1:2, c(length(y1),length(y2)))
m<-median(z)
fisher.test(z<m,g)$p.value
}
in
http://www.mail-archive.com/r-help@r-project.org/msg95278.html
I have the following data
> group1 <- c(2, 2, 2, 1, 4, 3, 1, 1)
> group2 <- c(3, 1, 3, 1, 4, 1, 1, 1, 7, 1, 1, 1, 1,