similar to: Problem accessing SWAT with Firefox

I have a couple of Samba 2.2 servers, in different locations, configured as NT Domain Controllers, but I'm experiencing some problems with logging on to the domains as Administrator in order to perform some administration tasks, such as configuring antivirus software on workstations. I won't go into the details here; I think the basic problem is my lack of understanding of how the

I ran into a problem today which surprised me, and after two hours of reading and testing I am more confused than ever, so I feel the need for a sanity check. It would be good to have a clear and authoritative article about this somewhere; I thought it would be in either "Using Samba" or in the HOWTO, but I don't see it there. I am using Samba in several installations in homes and

Does CentOS 3.1 come with Swat?

Dear All, would you please provide your thoughts on the following: let us say I have: a <-c(1,5,8,15,32,69) b <-c(8.5,33) and I would like to extract from "a" the two values that are closest to the values in "b", where the length of this vectors may change but b will allways be shorter than "a". So at the end based on this example I should have the result

So, like a lot of people, I am using --link-dest to do backups. My backup target is ext4 so with a hard link limit of 64K. I do end up with trying to create too many links at some point though and get the following sequence of events: rsync: link "/.snapshots/hourly.0/linux/usr/src/openwrt-r18617/build_dir/host/mpfr-2.4.1/tests/.deps/tui_sub.Po" =>

Dear All,   this is probably an easy one but I can not get a handle on it:   x <-c(1,2,3,4,5) y <-c(6,7,8,9,10) z <-15 w <-ifelse(z>14,x,y)   this will give me a value of 1 for w. What I would like to get is the whole string of x, so that w would become a numeric object of 5 characters exactly the same as x.   Apreciate the help,   Sincerely,   Andras [[alternative HTML version

Dear All,   I have a matrix with 33 columns and 5000 rows. I would like to find 2 specific columns in the set: the one that holds the highest values and the one that holds the lowest values. In this case the column's mean would be apropriate to use to try to find those specific columns because each columns mean is different and they all change together based on the same "change of rate

hi! I have a problem with rsync (current CVS version), running on a win2k machine (rsync compiled using Cygwin). c:\rsync>rsync --version rsync version 2.4.6dev protocol version 24 Copyright (C) 1996-2001 by Andrew Tridgell, Paul Mackerras and others Capabilities: 64-bit files, socketpairs, hard links, symlinks It can DOWNload >2gb files from my linux box (with rsync reporting negative

Dear All,   I am working with a Sweave document to be converted into PDF using Rstudio. It seems to me that my R code will also show up after conversion, which I would like not to happen. Is there a way to specify a command that I could place on the beggining and at the end of the R code that would allow R to recognize the area where my R code is and would ignor it when the data is converted?  

Dear All,   I often have to work with certain models in which I try to "reproduce" a distribution the best I can with very little known information avaible. Is there a package or function in R that could best reproduce a probability distribution using only the mean, median and SD values availble without knowing the actual distribution type to begin with and/or the covariance matrix (for

Dear All   I have the following data (somewhat simplyfied):   TINF <-1 a <-c(500,750,1000,1250,1500,1750,2000) b <-c(8,12,18,24,36,48,60,72,96)   following function:   infcprodessa <-function (D, tin, tau, ts)   (D * (1 - exp(-0.048 * tin))/(tin * (0.048*79) * (1 - exp(-0.048 * tau)))) * exp(-0.048 * (ts - tin)) z <-sapply(1:1, function(n) infcprodessa(1000,TINF,12,12-TINF))   is

Dear All,   I was wondering if you could help me with the following: I have the code:   tin <-0.5 tau <-24 output0 <-10 TIMELOW <-tin TIMEHIGH <-1*tau TIME1 <-c(seq(TIMELOW,TIMEHIGH, by = sign(TIMEHIGH-TIMELOW)*(tau-tin)/3))   then I would like to calculate:   cp1 <-output0*exp(-0.3*TIME1[1]) cp2 <-output0*exp(-0.3*TIME1[2]) cp3 <-output0*exp(-0.3*TIME1[3]) cp4

Dear All,   as a follow up to my previous e-mail (I think I am getting closer...):   I am trying to apply the trapezoidal functions to a matric column by column. I have the following code:   a <-matrix(c(1:100),ncol=10) b <-matrix(c(2,4,6,8,10,12,14,16,18,20))   apply(a,2,function(b,a) sum(diff(b)*(a[-1]+a[-length(a)]))/2)   for some reason i get an error message: Error in FUN(newX[[, i],

Hi, I''ve downloaded the latest stabil Hieraki. I have ruby 1.8.2 (2004-12-25) [i686-linux], the latest rails (and gems, too), Apache/1.3.33 (Unix) and mod_fastcgi/mod_fastcgi-SNAP-0404142202. I''m successfully running Typo (from SVN) as a FastCGI application. Hieraki works well with "script/server", and works well as a .cgi (just very slow). My problem is, that

Dear All,   sorry, got stuck again on the following: let us say we have:   a <-c(1:5) b <-c(6:10) d <-cbind(a,b)     from d I would like to remove total number of rows based on the length of f. So if:   f <-c(1)   my result is working great with the following solution:   d[-length(f),]   so I get: a b [1,] 2 7 [2,] 3 8 [3,] 4 9 [4,] 5 10 but if I do: f <-c(1,2) then I get: 

Dear All,   another quick question, this one is on skipping part of my code, so let us say:   a <-5 b <-2 e <-0   d <-a+b f <-a-b   what I would like to do is to have R NOT to calculate the value for d in case the value of e equals to zero (essentially skip that "chunk"), but instead move on to calculate te value for f. In the code I am working with the value of e changes,

dear All   I am trying to plot the following with the x axis on the log scale, but I would like the original x values to show up as labels:   x <-c(0.25,0.5,1,2,4,8,16,32) y <-c(1,1,1,1,0.9,0.8,0.6,0.2)   plot(log(x),y,type="b")   here I would like the labels 0.25,0.5,1,2,4,8,16, and 32 to show on the plot at their respective "log scale" location   apreciate the help,    

Dear List,   I have the following code:   x <-c(0, 13.8333333333333, 38.1666666666667, 62.1666666666667, 85.9166666666667, 108.916666666667) y <-c(1.77, 2.39, 3, 2.65, 2.62, 1.8) Interpolated <- approx(x, y,xout=0:tail(x, n=1),method="linear") plot(Interpolated)   in this code x is time in hours (cumulative), and y is a biological variable. I am using linear interpolation

Dear all,   could you please give me some pointers on how I could make R screen for a value if it falls within a certain range? I looked at the subset function, but is not doing it, perhaps because I only have 1 value to screen?   aptreciate the input   ex: a <-16.5 I would like to screen to see if a is within the range of 15 to 20, (which it is:-)), and I would like the code to return a value

I'll try to make some shorter samples later, but for now here are the ones I have tried with: http://www.surfnonstop.com/~bandit/speex/1.2beta1_AEC_garble/ The original recordings are in mic.raw and spk.raw. Jean-Marc Valin wrote: > You may have triggered an instability problem. Can you upload your files > somewhere so I can have a look at them? > > Jean-Marc > > Andras