similar to: How do I stop the guest account printing?

Displaying 20 results from an estimated 1000 matches similar to: "How do I stop the guest account printing?"

2004 Dec 02
2
Printer permissions from W2K
Hey all... I am trying to connect to a Epson FX-85 24-pin printer on my file/print/samba server. I am running SuSE 9.1/Samba 3.0.2a with CUPS as the print spool. When I try to connect to the printer from W2K land, I get this error: "Permission denied" I am at a loss as to where to look (sorry I dont have my smb.conf file posted. I am away from home for a couple of days). ALl else
2005 Jan 08
1
Simple Samba Guest printer setup problem
OK, I have a very simple setup problem. I have a server and three printers which I want to share. These printers should need no password. This does not work However when I login and map a network drive I can print just fin How do I bypass the need for a password or network login on these printers. Thanks I am running Fedora 3 core and samba Thanks Chip Here is the printers section of my
2002 Feb 28
3
access denied on printing from win2k?
Hi, I'm running samba 2.2.1a (RPM install) on RedHat 7.2 I've connected a Canon LBP-8 IV laserprinter to the network via a HP Jetdirect box. I've configured the printer within linux and printing goes fine. Now I'm trying to access the printer via samba from my win2k clients. Now, the problem is: When I'm trying to print to the printer (e.g. a testpage) I get the message
1998 Oct 26
2
IBM 4039 Laserprinter. Weird problem.
I have menaged to setup Samba services to share an IBM 4039 printer and have tested another printer (Epson LX-800) on the PC. It works fine. The weird thing, the IBM4039 will not print anything. All the jpbs will be spooled. For each print job to be printed. I will need to switch off the printer and switch it on again. Have anyone encountered such problems before? I know there is basically
2013 Jun 18
2
find closest value in a vector based on another vector values
Dear All, would you please provide your thoughts on the following: let us say I have: a <-c(1,5,8,15,32,69) b <-c(8.5,33) and I would like to extract from "a" the two values that are closest to the values in "b", where the length of this vectors may change but b will allways be shorter than "a". So at the end based on this example I should have the result
2010 Apr 04
3
Generate Numbers
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2012 Jun 24
7
Hlink node data for 2282618 already has path=...
So, like a lot of people, I am using --link-dest to do backups. My backup target is ext4 so with a hard link limit of 64K. I do end up with trying to create too many links at some point though and get the following sequence of events: rsync: link "/.snapshots/hourly.0/linux/usr/src/openwrt-r18617/build_dir/host/mpfr-2.4.1/tests/.deps/tui_sub.Po" =>
2012 Aug 31
3
Help on numerical object and ifelse function
Dear All,   this is probably an easy one but I can not get a handle on it:   x <-c(1,2,3,4,5) y <-c(6,7,8,9,10) z <-15 w <-ifelse(z>14,x,y)   this will give me a value of 1 for w. What I would like to get is the whole string of x, so that w would become a numeric object of 5 characters exactly the same as x.   Apreciate the help,   Sincerely,   Andras [[alternative HTML version
2012 Sep 02
3
Help on finding specific columns in matrix
Dear All,   I have a matrix with 33 columns and 5000 rows. I would like to find 2 specific columns in the set: the one that holds the highest values and the one that holds the lowest values. In this case the column's mean would be apropriate to use to try to find those specific columns because each columns mean is different and they all change together based on the same "change of rate
2001 Nov 08
4
win2k + >2GB files problem
hi! I have a problem with rsync (current CVS version), running on a win2k machine (rsync compiled using Cygwin). c:\rsync>rsync --version rsync version 2.4.6dev protocol version 24 Copyright (C) 1996-2001 by Andrew Tridgell, Paul Mackerras and others Capabilities: 64-bit files, socketpairs, hard links, symlinks It can DOWNload >2gb files from my linux box (with rsync reporting negative
2012 Sep 12
2
Help on converting a Sweave document to PDF
Dear All,   I am working with a Sweave document to be converted into PDF using Rstudio. It seems to me that my R code will also show up after conversion, which I would like not to happen. Is there a way to specify a command that I could place on the beggining and at the end of the R code that would allow R to recognize the area where my R code is and would ignor it when the data is converted?  
2012 Jun 07
4
"Re-creating" distributions
Dear All,   I often have to work with certain models in which I try to "reproduce" a distribution the best I can with very little known information avaible. Is there a package or function in R that could best reproduce a probability distribution using only the mean, median and SD values availble without knowing the actual distribution type to begin with and/or the covariance matrix (for
2013 Jan 25
5
Loop question?
Dear All   I have the following data (somewhat simplyfied):   TINF <-1 a <-c(500,750,1000,1250,1500,1750,2000) b <-c(8,12,18,24,36,48,60,72,96)   following function:   infcprodessa <-function (D, tin, tau, ts)   (D * (1 - exp(-0.048 * tin))/(tin * (0.048*79) * (1 - exp(-0.048 * tau)))) * exp(-0.048 * (ts - tin)) z <-sapply(1:1, function(n) infcprodessa(1000,TINF,12,12-TINF))   is
2012 Dec 17
3
simplifying code
Dear All,   I was wondering if you could help me with the following: I have the code:   tin <-0.5 tau <-24 output0 <-10 TIMELOW <-tin TIMEHIGH <-1*tau TIME1 <-c(seq(TIMELOW,TIMEHIGH, by = sign(TIMEHIGH-TIMELOW)*(tau-tin)/3))   then I would like to calculate:   cp1 <-output0*exp(-0.3*TIME1[1]) cp2 <-output0*exp(-0.3*TIME1[2]) cp3 <-output0*exp(-0.3*TIME1[3]) cp4
2017 Oct 23
3
Linear regression with tranformed dependant variable
Dear all,?I am trying to fit a multiple linear regression model with a transformed dependant variable (the normality assumption was not verified...).?I have realised a sqrt(variable) transformation...?The results are great, but I don't know how to interprete the beta coefficients... Is it possible to do another transformation to get interpretable beta coefficients to express the variations in
2012 Sep 08
3
Apply a function to columns of a matrix
Dear All,   as a follow up to my previous e-mail (I think I am getting closer...):   I am trying to apply the trapezoidal functions to a matric column by column. I have the following code:   a <-matrix(c(1:100),ncol=10) b <-matrix(c(2,4,6,8,10,12,14,16,18,20))   apply(a,2,function(b,a) sum(diff(b)*(a[-1]+a[-length(a)]))/2)   for some reason i get an error message: Error in FUN(newX[[, i],
2005 Aug 10
6
Hieraki + FCGI + Problem
Hi, I''ve downloaded the latest stabil Hieraki. I have ruby 1.8.2 (2004-12-25) [i686-linux], the latest rails (and gems, too), Apache/1.3.33 (Unix) and mod_fastcgi/mod_fastcgi-SNAP-0404142202. I''m successfully running Typo (from SVN) as a FastCGI application. Hieraki works well with "script/server", and works well as a .cgi (just very slow). My problem is, that
2013 Mar 20
2
remove specific number of rows from a matrix
Dear All,   sorry, got stuck again on the following: let us say we have:   a <-c(1:5) b <-c(6:10) d <-cbind(a,b)     from d I would like to remove total number of rows based on the length of f. So if:   f <-c(1)   my result is working great with the following solution:   d[-length(f),]   so I get: a b [1,] 2 7 [2,] 3 8 [3,] 4 9 [4,] 5 10 but if I do: f <-c(1,2) then I get: 
2013 Mar 20
3
how to skip part of the code
Dear All,   another quick question, this one is on skipping part of my code, so let us say:   a <-5 b <-2 e <-0   d <-a+b f <-a-b   what I would like to do is to have R NOT to calculate the value for d in case the value of e equals to zero (essentially skip that "chunk"), but instead move on to calculate te value for f. In the code I am working with the value of e changes,
2012 Aug 30
2
help on plot on the log scale but showing original values on axis
dear All   I am trying to plot the following with the x axis on the log scale, but I would like the original x values to show up as labels:   x <-c(0.25,0.5,1,2,4,8,16,32) y <-c(1,1,1,1,0.9,0.8,0.6,0.2)   plot(log(x),y,type="b")   here I would like the labels 0.25,0.5,1,2,4,8,16, and 32 to show on the plot at their respective "log scale" location   apreciate the help,