similar to: Access Denied

My server provider only supports Samba 2.2.8. I need 3.0 to fully appreciate my XP Pro and Microsoft Office 2003 Pro products. I've installed 3.0 but it does not seem to be there. When I run SWAT, it still reports the version to be 2.2.8. Any suggestions? Bill Mann W. D. (Bill) Mann, Sr., LUTCF, RHU The Benefits Office, an RMA Company P. O. Box 1884 Cypress, TX 77410-1884

I've installed 3.0.4. Install show successful. All the parameters are set per Webmin. Still, not path found when calling net use. Also, testparm returns command not found. Any suggestions? Windows XP Pro OS client, FreeBSD Unix Server. Bill Mann W. D. (Bill) Mann, Sr., LUTCF, RHU The Benefits Office, an RMA Company P. O. Box 1884 Cypress, TX 77410-1884 281-374-6071 Ext. 104

Hi, I do want to use the Mann-Whitney test which ranks my data and then uses those ranks rather than the actual data. Here is the R code i am using: group1<- c(1.34,1.47,1.48,1.49,1.62,1.67,1.7,1.7,1.7,1.73,1.81,1.84,1.9,1.96,2, 2,2.19,2.29,2.29,2.41,2.41,2.46,2.5,2.6,2.8,2.8,3.07,3.3) > group2<-

I am new to R and have two scripts written slightly different but should to relatively the same thing but my lack of experience with the program I can not figure out the what I need to do to correct it. The first script gives me a consistent mean fold change values with every run but can generate negative p values for some. For the second version of the script, the fold changes seem to be very

Hello, what I want to do, is, to write every element of a variable into a separate text-file automatically: My Variable: > wull [1] "Hallo Leute, wie gehts denn euch seid ihr noch alle..." [2] "Is their anyone how can help me with..." [3] "mann, mann, mann... das nervt aber.." [4] "how are you littele strange tiger..."

You have quite a few mistakes in your example. The code below works for me - you can wrap it in a function if you like. I think you will need a lot more practice before you can write something like this in R as you are missing close braces and haven't really worked out the difference between the number of calculations you are doing for each replication and the number of replications. It takes

Hi, i think i have figured the purpose of using this index (i-1)*5+j in the previous example that you gave. It is because that i have to consider the outer loop and inner loop also... so the iterative for i need to minus one because it have ran one times simulation already ,then times the number of sizes of inner loop, then plus the iterative of j.... then for the simulation, i think there will

I believe our trademark guidelines say we aren't supposed to use VMware as a noun to mean a product, only to mean the company. So we can say "running on VMware ESXi" or "running in a VMware virtual machine", but "running on VMware" is wrong. There is supposedly some good legal reason for this related to keeping our trademark. On Tue, 25 Oct 2016 22:26:00 -0700,

I believe our trademark guidelines say we aren't supposed to use VMware as a noun to mean a product, only to mean the company. So we can say "running on VMware ESXi" or "running in a VMware virtual machine", but "running on VMware" is wrong. There is supposedly some good legal reason for this related to keeping our trademark. On Tue, 25 Oct 2016 22:26:00 -0700,

Hi all, The Kruskal-Wallis test is a generalization of the two-sample Mann-Whitney test to *k* samples. That being the case, the Kruskal-Wallis test with *k*=2 should give an identical p-value to the Mann-Whitney test, should it not? x1<-c(1:5) x2<-c(6,8,9,11) a<-wilcox.test(x1,x2,paired=FALSE) b<-kruskal.test(list(x1,x2),paired=FALSE) a$p.value [1] 0.01587302 b$p.value [1]

I have been examining the Mann-Whitney test closely. And there are two features of the R implementation that puzzles me. The test statistic is reported as "W" and depends on the order of the arguments to the function. > x <- c(1,3,5,7,9) > y <- x-1 > x [1] 1 3 5 7 9 > y [1] 0 2 4 6 8 > wilcox.test(x, y)$statistic W 15 > wilcox.test(y,x)$statistic W 10

Hello - does anyone know whether there are any packages for Mann-Kendall mutation tests in R available? The only one I could find online is this MK_mut_test: Mann-Kendall mutation test in Sibada/sibadaR: Sibada's accumulated R scripts for next probably use to avoid reinventing the wheel. (rdrr.io) <https://rdrr.io/github/Sibada/sibadaR/man/MK_mut_test.html> but there doesn't seem to

Dear Sir, I am comparing two samples using wilcox.test in R. Literature appears to describe mann whitney u test as the most appropriate test to use on my data. is the wilcox.test function equivalent to mann-whitney u? Is there a way to gain the U-value as apposed to the W-value in R? Thank you

This is my current work.Now i am trying to use a function to do the normal distribution simulation. rm(list=ls()) t <- u<- mann<- rep(0, 45) Nsimulation<-function(S1,S2,Sds,nSims) { set.seed(1) for (sim in 1:nSims) { matrix_t <-matrix(0,nrow=nSims,ncol=3) matrix_u<-matrix(0,nrow=nSims,ncol=3)

Hi there, I'm trying to apply the Mann Kendall test for trend analysis of a time series. I have downloaded and installed the package Kendall and subsequently loaded it into the software. My time series is a .txt file with 2 columns - column 1 is the year (1985 - 2009) and column 2 is the corresponding entry variable. According to the R guidelines, the call should be: MannKendall(x)

Hi All, I have the following dataset (triplicates values of 5 independent measurements and duplicate vaues of a control): 1 2 3 4 5 C 181.8 58.2 288.9 273.2 290.9 53.9 120.3 116.8 108.9 281.3 446 39.6 86.1 148.5 52.9 126 150.3 My aim was to find if mean values of Samples 1 - 5 are

Dear all, I want to compare the efficiency of 2 methods in extracting proteins from algal samples. I collected 6 independant algal samples and I extracted 3 by the method 1 and 3 others by the method 2. So I have 2 groups of 3 samples, that are not paired. I would like to know if the results obtained by these 2 methods are significantly different, I hope method 2 to be more efficient than method

Given this example #start code a<-c(0,70,50,100,70,650,1300,6900,1780,4930,1120,700,190,940, 760,100,300,36270,5610,249680,1760,4040,164890,17230,75140,1870,22380,5890,2430) b<-c(0,0,10,30,50,440,1000,140,70,90,60,60,20,90,180,30,90, 3220,490,20790,290,740,5350,940,3910,0,640,850,260) wilcox.test(a, b, paired=FALSE) #sum of rank for first sample sum.rank.a <-

>Hola colegas, no encuentro como hacer el Mann-Whitney U Test en R. > > Alguna solución????? > > Un abrazo a todos. > > Leonardo > Hola Leonardo: La prueba de Mann-Whitney también se conoce como la prueba de suma de rangos de wilcoxon y puede calcularse mediante la función wilcox.test Un saludo, Nicolás Benítez Parejo Técnico de Evaluación e Investigación Agencia

Hi, Could you please explain what is non-positive fis error? I have been trying to use quantile regression (rq) procedure and I keep ending up with this error. I haven't been able to find an explanation for the same. Best Regards, Arti Arti Mann Ph.D. Student Department of Information Systems W.P. Carey School of Business Arizona State University Email : Arti.Mann at asu.edu