similar to: Getting Microsoft Word and samba to work together.

Hi Everyone. I am doing some LDAP testing. I have setup a 389 Directory Server on CentOS 5 and using the default schema I have populated it with a couple of users. I then did the configuration on the client that I thought was needed to make it authenticate. To test this I expected to be able to use id <uidNumber> of a user I had defined. But I get id: 1001: No such user id: 5001: No

Now that I have winbind working, life is good. However, I've hit upon a real kick in the pants. As you can see from my email address, we have a convention here of usernames being firstname.lastname. So, when I go to change the owner ship of a file: $ chown chris.palmer myfile Linux thinks I mean user chris, group palmer, and says "invalid group" (there is no palmer group,

Bother! This cold has made me accident-prone. I meant to hit Reply-all. Clarification below. -------- Original Message -------- Subject: Re: [R] Parameterization puzzle Date: Fri, 21 Jul 2006 19:10:03 +1200 From: Murray Jorgensen <maj at waikato.ac.nz> To: Prof Brian Ripley <ripley at stats.ox.ac.uk> References: <44C063E5.3020703 at waikato.ac.nz>

Vacancy number 300014 LECTURER Department of Statistics School of Computing and Mathematical Sciences University of Waikato Hamilton, New Zealand You should have a PhD in Statistics, or equivalent, and will have demonstrated the ability to sustain a successful teaching and research career. You will be expected to contribute towards the Department?s undergraduate and graduate teaching

Hello once again, I've got winbind doing authentication not just for the samba service but also sshd and login. It's great. However, I have to give a fully-qualified username (e.g. "GENEEDINC+chris.palmer") as the username when logging in via these methods. I wondered, Is there any way to get winbindd to insert the domain and the separator for the user, when none is provided? I

How do you stop R from putting up a dialog box when you quit Rgui? (I use Windows and I never save workspaces that way) Murray -- Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html Department of Statistics, University of Waikato, Hamilton, New Zealand Email: maj at waikato.ac.nz Fax 7 838 4155 Phone +64 7 838 4773 wk +64 7 849 6486 home

Consider the following: > A <- 1:10 > A [1] 1 2 3 4 5 6 7 8 9 10 > dim(A) NULL > dim(A) <- c(2,5) > A [,1] [,2] [,3] [,4] [,5] [1,] 1 3 5 7 9 [2,] 2 4 6 8 10 > dim(A) [1] 2 5 > dim(A) <- 10 > A [1] 1 2 3 4 5 6 7 8 9 10 > dim(A) [1] 10 Would it not make sense to have dim(A) = length(A) for all vectors?

I got a shock a few days ago when I accidentally visited www.r-project.com . I thought that the r-project site had been hacked until I realised my mistake. There is also a site www.r-project.net. Both of these sites appear to be Japanese. Does anyone know anything about them? I suppose that it is not unusual for names close to those of popular sites to be used. It is good that they use a

I wanted a sort of matrix product of an array and a matrix. As there does not seem to be any array multiplication apart from outer() I proceeded as follows: lambda <- array(0, c(n,m,d)) # stuff omitted # zed is an n by m matrix # # \lamb.star_{ik} lamb.star <- matrix(0, nrow=n, ncol=d) for (i in 1:n) { for (k in 1:d) { for (j in 1:m) { lamb.star[i,k] = lamb.star[i,k] +

G'day list! I'm thinking about programming likelihood and score intervals for generalized linear models in R based on the paper "On the computation of likelihood ratio and score test based confidence intervals in generalized linear models" by Juha Alho (1992) (Statistics in Medicine, 11, 923-930). Being lazy, I thought that I would ask if anyone else on the list has

I can ask my question using and example from Chapter 1 of Pinheiro & Bates. > # 1.4 An Analysis of Covariance Model > > OrthoFem <- Orthodont[ Orthodont$Sex == "Female", ] > fm1OrthF <- + lme( distance ~ age, data = OrthoFem, random = ~ 1 | Subject ) > summary( fm1OrthF ) Linear mixed-effects model fit by REML Data: OrthoFem AIC BIC

The birth weight example from ?stepAIC in package MASS runs well as indeed it should. However when I change stepAIC() calls to step() calls I get warning messages that I don't understand, although the output is similar. Warning messages: 1: In model.response(m, "numeric") : using type="numeric" with a factor response will be ignored (and three more the same.) Checked

I want to interlace two vectors. This I can do: > x <- 1:4 > z <- x+0.5 > as.vector(t(cbind(x,z))) [1] 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 but this seems rather inelegant. Any suggestions? Murray -- Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html Department of Statistics, University of Waikato, Hamilton, New Zealand Email: maj at waikato.ac.nz

I forgot to mention that I am using Windows XP. -------- Original Message -------- Subject: Pasting data into scan() Date: Tue, 02 May 2006 11:55:03 +1200 From: Murray Jorgensen <maj at stats.waikato.ac.nz> To: r-help at stat.math.ethz.ch The file TENSILE.DAT from the Hand et al "Handbook of Small Data Sets" looks like this: [...] -- Dr Murray Jorgensen

How about: > dim [1] 3 1 4 1 5 > N <- length(dim) > one <- rep(c(3,4),N) > two <- c(rep(1,N),dim) > three <- rep(1:N,rep(2,N))+N*rep(0:1,N) > rep(one,two[three]) [1] 3 4 4 4 3 4 3 4 4 4 4 3 4 3 4 4 4 4 4 ---------------------- Bendix Carstensen Senior Statistician Steno Diabetes Centre Niels Steensens Vej 2 DK-2820 Gentofte Denmark tel: +45 44 43 87 38 mob: +45 28

Suppose you fit a linear model > model.1 ~ lm(v1 ~ ..., data=myframe) and v2 is some other column of myframe typically not in the model. You will often want to try > plot(v2, model.1$residuals) but this will fail if there are NAs in the response v1 as model.1$residuals has length equal to the number of nonmissing values in v1. I suppose > plot(v2[!is.na(v1)],

Having just update to R 2.6.2 on my old Windows laptop I notice that the number of packages is growing exponentially and my usual approach of get-em-all may not be viable much longer. Has any thought been given to dividing "contributed" binaries into a recommended set, perhaps a couple of hundred, and the remained. That way one could install the recommended ones routinely and add in

Does anyone else miss email-friendly character graphics such as the following example, produced using Minitab? Histogram of C6 N = 478 N* = 21 Each * represents 2 observation(s) Midpoint Count -12 16 ******** -11 53 *************************** -10 63 ******************************** -9 83

I have just noticed that quite a few columns of a data frame that I am working on are numeric factors. For summary() purposes I want them to be vectors. I tried, for example > indx <- c(1:18,21:37,40,41) > i <- 0 > i <- i+1 > summary(as.vector(sflows1[indx[i]])) Length Class Mode min.pkt.sz 3000 factor numeric but this does not give the five-number

I'm going to try my hand at converting some Fortran programs to R. Does anyone know of any good articles giving hints at such tasks? I will post a selective summary of my gleanings. Cheers, Murray -- Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html Department of Statistics, University of Waikato, Hamilton, New Zealand Email: maj at waikato.ac.nz