similar to: samba resolves wrong wins ip address

Heya All I'm having a Samba PDC on Centos machine from past 4-5 months everything went one coolly untill I installed vmware on this same machine to put a new server, as the hardware of the computer was very good to support it. No worried with the vmware even both the servers are running properly. My Samba was set to use Interface eth0 with ip 192.168.50.56 . Upon installation the Vmware

On 2014?03?07? 23:05, Ady wrote: > I understand that these remarks might seem not the main issue, but I > tend to think that once you are successful while using only "default" > > values and in a minimalistic case, you could add complexity > (different paths, multiple firmwares, additional kernels, multiple > cfg files...). Ady, Thanks. I will follow your advice to

Hello! I want to start rsync on w2k as service. If I try to start rsync from command line it simply do nothig: $ rsync --daemon Administrator@dm-w2ks /usr/bin $ ps PID PPID PGID WINPID TTY UID STIME COMMAND 480 1 480 480 con 500 04:15:03 /usr/bin/bash 1428 480 1428 1420 con 500 05:26:46 /usr/bin/ps Administrator@dm-w2ks

In /etc/shorewall/masq I have: eth0 eth1 eth0 vmnet1 eth0 vmnet8 ------------- eth0 is my default route to the Linksys router connected to the cable modem. eth1 is my connection to 192.168.1 subnet and it is the gateway for all other machines on this subnet. My routing table is: # netstat -nr Kernel IP routing table Destination

Hi! I'm running Samba 2.2.7a as Domain Controller, and when I try to add a workstation to the domain, I get always the following logentry (and the operation fails): [2002/12/20 14:30:21, 0] passdb/pdb_ldap.c:pdb_getsampwnam(859) LDAP search "(&(uid=vmware-w2ks_)(objectclass=sambaAccount))" returned 0 entries. [2002/12/20 14:30:22, 0]

Hi, I cannot seem to find a good answer for what I am doing wrong; I am simply trying to rsync a directory from one large disk partition to another disk, both ext2, on the same physical system by using the command: rsync --archive -v /etc /mnt/hdf/ I systematically get the following errors: # rsync --archive -v /etc /mnt/hdf/ building file list ... done etc/ etc/mtab etc/ntp/drift

yes, thanks, and I was getting close to that. One thing I found is the manual says the height is the distance above the y-line, which should be, but doesn't have to be positive. In fact, the time series are estimates of a cycle, and has negative values, which unfortunately are not included in my sub-sample. And the negative values are not handled properly (the series disappears for

Hi All: I am using httr to download files form a service, in this case a .csv file. When I use httr::content on the result, I get a message. Since this will be in a package. I want to suppress the message, but haven't figured out how to do so. The following should reproduce the result: myURL <-

> On 1 Jun 2017, at 22:42, Roy Mendelssohn - NOAA Federal <roy.mendelssohn at noaa.gov> wrote: > > Thanks to all for responses/. There was a question of exactly what was wanted. It is the generalization of the obvious example I gave, > >>>> junk1 <- junk[, rev(seq_len(10), ] > > > so that > > junk[1,1,1 ] = junk1[1,10,1] > junk[1,2,1] =

Hi All: In creating a R Notebook I know that in the text I can link to a (sub) section by using the command: [Header 1](#anchor) and putting the appropriate anchor name at the appropriate header. But can the same be done for code chunks, if the code chunk is named? What I want to do is say that such and such code chunk is an example of how to do something, and have that link to the

Hi All: I have been looking for an elegant way to do the following, but haven't found it, I have never had a good understanding of any of the "apply" functions. A simplified idea is I have an array, say: junk(5, 10, 3) where (5, 10, 3) give the dimension sizes, and I want to reverse the second dimension, so I could do: junk1 <- junk[, rev(seq_len(10), ] but what I am

I have tried: ggplot(plotFrame, aes(x = time, y = cycle, height = cycle, group = depth)) + geom_ridgeline() ggplot(plotFrame, aes(x = time, y = depth, height = cycle, group = depth)) + geom_ridgeline() ggplot(plotFrame, aes(x = time, y = depth, group = depth)) + geom_density_ridges() none are producing a plot that was a ridgeline for each depth showing the time series at that depth. The plot

My error. Clearly I did not do enough testing. z <- array(1:24,dim=2:4) > all.equal(f(z,1),f2(z,1)) [1] TRUE > all.equal(f(z,2),f2(z,2)) [1] TRUE > all.equal(f(z,3),f2(z,3)) [1] "Attributes: < Component ?dim?: Mean relative difference: 0.4444444 >" [2] "Mean relative difference: 0.6109091" # Your earlier example > z <- array(1:120, dim=2:5) >

The min_height = -0.25 is there to make it show cycle values down to -1/4. You may want to change it to -1 so it shows more of the cycle values. Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, Oct 17, 2017 at 1:26 PM, Roy Mendelssohn - NOAA Federal < roy.mendelssohn at noaa.gov> wrote: > yes, thanks, and I was getting close to that. One thing I found is the > manual says the

Here is an alternative approach using apply(). Note that with apply() you are reversing rows or columns not indices of rows or columns so apply(junk, 2, rev) reverses the values in each column not the column indices. We actually need to use rev() on everything but the index we are interested in reversing: f2 <- function(a, wh) { dims <- seq_len(length(dim(a))) dims <-

How about this: f <- function(a,wh){ ## a is the array; wh is the index to be reversed l<- lapply(dim(a),seq_len) l[[wh]]<- rev(l[[wh]]) do.call(`[`,c(list(a),l)) } ## test z <- array(1:120,dim=2:5) ## I omit the printouts f(z,2) f(z,3) Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into

Thanks again. I am going to try the different versions. But I probably won't be able to get to it till next week. This is probably at the point where anything further should be sent to me privately. -Roy > On Jun 1, 2017, at 1:56 PM, David L Carlson <dcarlson at tamu.edu> wrote: > > On the off chance that anyone is still interested, here is the corrected function using

On the off chance that anyone is still interested, here is the corrected function using aperm(): z <- array(1:120,dim=2:5) f2 <- function(a, wh) { idx <- seq_len(length(dim(a))) dims <- setdiff(idx, wh) idx <- append(idx[-1], idx[1], wh-1) aperm(apply(a, dims, rev), idx) } all.equal(f(z, 1), f2(z, 1)) # [1] TRUE all.equal(f(z, 2), f2(z, 2)) # [1] TRUE

Does the following work for you? ggplot2::ggplot(plotFrame, aes(x = time, y = depth, height = cycle, group = depth)) + ggridges::geom_ridgeline(fill="red", min_height=-0.25) Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, Oct 17, 2017 at 12:43 PM, Roy Mendelssohn - NOAA Federal < roy.mendelssohn at noaa.gov> wrote: > I have tried: > > ggplot(plotFrame, aes(x =

I apologize for the off-topic post, but my Google search did not turn up much and I thought people on this list my have knowledge of this. I am looking for examples of data brushing (i.e. dynmaic linked plots) either on a web site, or in a web-based application, such as an AJAX app. Even better if there is a way to do this in R. Thanks for any help. -Roy M. **********************