similar to: Failure to Change Machine Account Password

Is there an specific function to eliminate blank space within strings? Thanks -- Dr. Agustin Lobo Institut de Ciencies de la Terra "Jaume Almera" (CSIC) LLuis Sole Sabaris s/n 08028 Barcelona Spain Tel. 34 934095410 Fax. 34 934110012 email: Agustin.Lobo at ija.csic.es http://www.ija.csic.es/gt/obster

I'm doing: > alyL32007z <- zoo(alyL32007,alyL32007$time) > range(time(alyL32007z)) [1] "2007-01-01 00:00:00 UTC" "2007-12-31 23:30:00 UTC" But then, while the original variable is: > summary(alyL32007$NEE_st) Min. 1st Qu. Median Mean 3rd Qu. Max. NA's -15.340 -1.615 -0.054 -0.814 0.750 8.965 11124 the variable within the zoo object

Hi! Is there any way of having a greyed ("ghosted") text (i.e, 2006) in the background of a plot? I'm making a dynamic plot and would like to show the year of each time step as a big greyed text in the background. (the idea comes from Hans Rosling video: http://video.google.com/videoplay?docid=4237353244338529080&sourceid=searchfeed ) Thanks Agus -- Dr. Agustin Lobo Institut

Hi! Is not there an standard R function to retrieve the day of the year (since 1st Jan of the same year)? I know I can make my own using julian, but find it weird that having days(), months() etc doy() does not exist as an standard function. Also, is the following not a bit inconsistent? > a <- chron("20100506",format="ymd") > a [1] 100506 > years(a) [1] 2010

Hi! Is it possible to set a file to which both commands and output would get automatically saved? I've tried with sink(), but only get the output. I mean something like a combined history and sink, as you get with File/Save to File.. in the windows GUI. Tis is done with diary filename in Matlab, and you can state diary on and diary off to control what is being saved to the file. Thanks Agus

Hi! I'm confused by this: > as.numeric(as.POSIXct(518400,origin="2001-01-01")) [1] 978822000 I guess the problem is that as.numeric() assumes a different origin, but cannot find any default origin. How can I get back the seconds from the POSIXct format? In other words, which the inverse function of as.POSIXct()? I've tried as.numeric and unclass() using a origin=

Which is the proper way to rename a factor? If I do: test$Parc[test$Parc=="Ol?rdola"]<-"Ol?rdola" R complains that Warning message: invalid factor level, NAs generated in: `[<-.factor`(`*tmp*`, test$Parc == "Ol?rdola", value = "Ol?rdola") Thanks Agus -- Dr. Agustin Lobo Institut de Ciencies de la Terra "Jaume Almera" (CSIC) LLuis Sole

I've set layout(matrix(c(1,3,2,4),ncol=2)) and par(mar=c(0, 4, 4, 0) + 0.0) and par(mar=c(0, 0, 4, 3) + 0.0) for the upper-left and upper-right plots, but still get an space between both plots, is there any way to completely eliminate that space? Thanks Agus -- Dr. Agustin Lobo Institut de Ciencies de la Terra "Jaume Almera" (CSIC) LLuis Sole Sabaris s/n 08028 Barcelona Spain

I've found that while cutree() and rect.hclust() make the same classes for a given height in the dendrogram, the actual labeling of the classes is different. For example, both produce the same 4 classes but class 1 according to cutree() is class 4 according to rect.hclust(). Would it be possible that future versions provide the same labeling? rect.hclust() is useful to display the classes

By Ctr-moving the cursor over a point in an iplot() scatterplot (package iplots) it is possible to check the exact x,y coordinates of a given point. Is it possible to check a text label for that point as well? (i.e., the same info that would get printed on the graphic using text(x,y, labels=v) or with identify(x,y,labels), but I do not want to get the labels permanently plotted on the graphic)

Hi! Given a vector (or a factor within a df),i.e. v1 <- c(1,1,1,2,3,4,1,10,3) and a dictionary cbind(c(1,2,3),c(1001,1002,1003)) is there a function (on the same line than recode() in car) to get v2 as c(1001,1001,1001,1002,1003,4,1001,10,1003) ? I'm using myself a function based on match() since long ago (I think that thanks to advice by Prof. B. Ripley), but would like to know if there

Hi! If I'm plotting 2 variables with the same units (i.e. wing length of 2 species), how can I force that X and Y axes have the same size for length unit? For example, if X ranges from 0 to 10 and Y ranges from 10 to 30, I want Y axis to be twice as long as X axis. I know I can just put xlim and ylim from 0 to 30, i.e., plot(runif(10,0,10),runif(10,10,30),xlim=c(0,30),ylim=c(0,30)) but this

Subject: Re: [R-sig-Debian] ubuntu problem with 'r-cran-robustbase' [FWD Agustin Lobo] Date: Tue, 12 May 2009 13:30:49 +0200 From: Agustin Lobo <aloboaleu at gmail.com> Reply-To: aloboaleu at gmail.com To: Dirk Eddelbuettel <edd at debian.org> CC: Martin Maechler <maechler at stat.math.ethz.ch>, R-SIG-Debian at stat.math.ethz.ch References: <18953.17704.527898.355877

I have the following time series: > class(CCasadesz2) [1] "zoo" > setmanes <- cut(time(CCasadesz2),breaks="weeks") > CCasadeswz <- aggregate(CCasadesz2,sum,by=setmanes) > class(CCasadeswz) [1] "zoo" > summary(CCasadeswz) Index CCasadeswz 2009-01-12 00:00:00: 1 Min. : 4.0 2009-01-19 00:00:00: 1 1st Qu.:

Given: > mitest <- matrix(1:16,ncol=4) > dimnames(mitest)[[1]] <- c("a","b","c","d") > dimnames(mitest)[[2]] <- c("a","b","c","d") > mitest a b c d a 1 5 9 13 b 2 6 10 14 c 3 7 11 15 d 4 8 12 16 I can do: > mitest[cbind(c(1,2,3),c(2,3,2))] [1] 5 10 7 but using the names does not

Given char vector delme2: > str(delme2) chr [1:1065] "30-1-08 8:48:21" "30-1-08 8:55:17" "30-1-08 9:00:22" ... I do: > delme3 <- strptime(delme2,format="%d-%m-%y %H:%M:%S") But then: > str(delme3) POSIXlt[1:9], format: "2008-01-30 08:48:21" "2008-01-30 08:55:17" ... > length(delme3) [1] 9 whie >

Agustin, posted on R-help. I think the problem is one of the debian/ubuntu package 'r-cran-robustbase' and its setup or (missing?) dependencies. I can confirm Agustin's problem, working on Ubuntu 8.04.2 (8.04 is a "LTS" = long time support version). apt-get install r-cran-robustbase works fine, but when trying to load the package, there's a DLL - dependency on

Dear list: Given > str(b3) 'data.frame': 159 obs. of 6 variables: $ index_pollution : num 8.228 10.513 0.549 0.915 10.416 ... $ position_descrip: chr "2" "2" "2" NA ... $ position_geo : chr "3" "0" "3" "3" ... $ institution : Factor w/ 3 levels "digesa","mem",..: 3 3 3 3 3 3

Hi; I'm having some trouble to comunicate with my just bought (08/17/15) Ups. According to SOLIS(8): SUPPORTED HARDWARE This driver has been tested with : Solis 1000 VA Solis 1500 VA Solis 2000 VA Solis 3000 VA Back-UPS BZ1200-BR Back-UPS BZ2200BI-BR So solis is the one to go for. Here is my scenario: SW: nut-2.7.3 (compiled from ports) OS: FreeBSD

Hi! I have a 3d array: > dim(ib5km15.dbc) [1] 190 241 19 and a set of positions to extract: > ib5km.lincol.random[1:3,] [,1] [,2] [1,] 78 70 [2,] 29 213 [3,] 180 22 Geting the values of a 2D array for that set of positions would be: > ima <- ib5km15.dbc[,,1] > ima[ib5km.lincol.random[1:10,]] but don't find the way for the case of the 3D array: >