similar to: "File size limit exceeded" when running /sbin/mke2fs -j /dev/sdb1

Hi, two days ago my functioning samba/ldap server stopped working. I *think* the problem is somehow related to the fact i transfered everything to a new server, but that was two months ago. Trouble started yesterday morning after a power-outage. Configuration: ubuntu 8.04, with a standard samba, ldap and smbldap-tools installed via apt-get. When users tried to login, they got a message "a

--- configure.ac | 8 +++++--- 1 files changed, 5 insertions(+), 3 deletions(-) diff --git a/configure.ac b/configure.ac index da03c9f..7606bca 100644 --- a/configure.ac +++ b/configure.ac @@ -68,7 +68,8 @@ dnl For ArchLinux handler. AC_CHECK_PROG(PACMAN,[pacman],[pacman],[no]) dnl Required programs, libraries. -AC_PATH_PROG([INSMODSTATIC],[insmod.static],[no])

Hey, I need some help. I want to obtain a cross validation for a regression model (binary response) but I got an error with CVbinary. Well I did this: fit <- lm(resp ~ PC1 + PC2 + PC3 + PC4 + PC5 + PC6 + PC7 + PC8 + PC9+PC10+PC11+PC12+PC13+PC14+PC15+PC16+PC17+PC18+PC19+PC20+PC21+PC22+PC23+PC24+PC25+PC26+PC27+PC28, data = dexp.cp, family=binomial()) CVbinary(fit) Error in sample(nfolds, m,

Hi, I saved as a matrix a summary of a PCA analysis and I've used barplot to plot the PCA variances. I would like to print on the same graphic the values of my matrix m1 - in other words the summary of my PCA analysis. I can do it very painstaking with text for each row and make sure that everything aligns and so on but i wonder if there is a better method than that. My summary follows:

Hello, since a few days the computer in a branch office the computer take five and more minutes to load the user profile. In the user's samba log I found many lines of the type: [2011/08/17 12:36:09, 0] smbd/service.c:1188(make_connection) tonon-pc11 (::ffff:192.168.10.11) couldn't find service odb$ We don't have a service ODB defined on our samba server and never had. Is

Martin, I fully agree. This becomes an issue when you have big matrices. (Note that there are awesome methods for actually only computing a small number of PCs (unlike your code which uses svn which gets all of them); these are available in various CRAN packages). Best, Kasper On Thu, Mar 24, 2016 at 1:09 PM, Martin Maechler <maechler at stat.math.ethz.ch > wrote: > Following from

Following from the R-help thread of March 22 on "Memory usage in prcomp", I've started looking into adding an optional 'rank.' argument to prcomp allowing to more efficiently get only a few PCs instead of the full p PCs, say when p = 1000 and you know you only want 5 PCs. (https://stat.ethz.ch/pipermail/r-help/2016-March/437228.html As it was mentioned, we already

I've got a share where I needed the permissions to be 770 and I think an Apple Mac computer is connecting to a Samba share and changing the permissions each day. At the end of the day, I'll set permissions to: root at backblaze000002:/share1/QuinceCt/.TemporaryItems# ls -la total 12 drwxrwx--- 3 jlehmanjr qcbbwritetoquincectshare 16 Nov 15 14:57 . drwxrwx--- 9 jlehmanjr

As I see it, the display showing the first p << n PCs adding up to 100% of the variance is plainly wrong. I suspect it comes about via a mental short-circuit: If we try to control p using a tolerance, then that amounts to saying that the remaining PCs are effectively zero-variance, but that is (usually) not the intention at all. The common case is that the remainder terms have a roughly

> On 25 Mar 2016, at 10:08 , Jari Oksanen <jari.oksanen at oulu.fi> wrote: > >> >> On 25 Mar 2016, at 10:41 am, peter dalgaard <pdalgd at gmail.com> wrote: >> >> As I see it, the display showing the first p << n PCs adding up to 100% of the variance is plainly wrong. >> >> I suspect it comes about via a mental short-circuit: If we

I agree with Kasper, this is a 'big' issue. Does your method of taking only n PCs reduce the load on memory? The new addition to the summary looks like a good idea, but Proportion of Variance as you describe it may be confusing to new users. Am I correct in saying Proportion of variance describes the amount of variance with respect to the number of components the user chooses to show? So

I have 2 SCSI disks each w/a RH 7.3 ext3 root filesystem: /dev/sdb1, and /dev/sdc1. /dev/sda1 is an old RH4.2 root filesystem. (sdb1 was created as an image of sdc1 using dd.) I have no problem booting from a SYSLINUX 1.52 floppy with SYSLINUX.CFG containing "append initrd=initrd.img root=/dev/sdb1". When I alter SYSLINUX.CFG with: "append initrd=initrd.img root=/dev/sdc1".

> On 25 Mar 2016, at 10:41 am, peter dalgaard <pdalgd at gmail.com> wrote: > > As I see it, the display showing the first p << n PCs adding up to 100% of the variance is plainly wrong. > > I suspect it comes about via a mental short-circuit: If we try to control p using a tolerance, then that amounts to saying that the remaining PCs are effectively zero-variance, but

I currenlty have the setup below, both nodes can see the shared drive ( confirmed with fdisk -l ) However I am unable to mount the shared device from node (2) after I mounted from node(1) I get the follwoign error mount.ocfs2: Transport endpoint is not connected while mounting /dev/sdb1 on /u02/oradata/orcl OS Red Hat uname -r --------------------------------- 2.6.9-22.ELsmp OCFS version

Hi, I'm a newbie to tool 'iostat' and I've read the manual for iostat several times. But it doesn't help. I still get confused with the output of 'iostat', the manual seems too abstract, or high-level, for me. Let's post the output first: avg-cpu: %user %nice %sys %idle 5.70 0.00 3.15 91.15 Device: rrqm/s wrqm/s r/s w/s

Hi, I've created an test enviroment for btrfs 0.11. The aim of the test is to compare speed of btrfs to ext3, reiserfs, jfs, xfs, etc. I've created an 70 GB partition for btrfs, created btrfs filesystem on it, which is currently mounted under /data. I put the kernel source tree of Linux 2.6.24 to the btrfs, make allyesconfig, and i've created the following script: while true; do

How do I go about troubeshooting this? I'm using RHEL 4 update 6. mount: /dev/sdb1 already mounted or /blah busy It's actually an iSCSI LUN (NetApp filer). I successfully configured (ext3) and mounted it, but when I rebooted, the /dev/sdb1 device/partition is seen by the kernel and it shows up with "fdisk -l". Nevertheless I get that error. I've tried

>Yes, if you are creating larger files. By default e2fsck assumes the average >file size is 8kB and allocates a corresponding number of inodes there. If, >for example, you are storing lots of larger files there (digital photos, MP3s, >etc) that are in the MB range you can use "-t largefile" or "-t largefile4" >to specify an average file size of 1MB or 4MB

Hi, is it save to use ext2 / ext3 hashed b-trees feature with linux kernel >= 2.4.25 ? thanx, Gregor -- echo '16i[q]sa[ln0=aln100%Pln100/snlbx]sbA0D3F204445524F42snlbxq'|dc

Hi, Is mke2fs' stride option relevant for a multi-striped LVM volume? Cheers, Stephen