similar to: Samba 3.24 + LDAP

How do you do !!! Compile samba-2.2.7a with -with-winbind -with-acl-support, has adjusted smb.conf [global] netbios name = server workgroup = sgtp server string = Samba Server max log size = 50 security = domain wins support = yes password server = DOM MULT * encrypt passwords = yes log level = 3 log file =

I am trying, without success, to compile a custom locale for the utf-8 character set. I have issued this command: localedef --no-archive -f UTF-8 -i /usr/share/i18n/locales/en_CA at yyyy-mmm-dd en_CA at yyyy-mmm-dd.utf8 which produces the requisite files without reporting an error but which none-the-less insists on using the iso-8859-1 charset: LC_ALL=en_CA at yyyy-mm-dd locale charmap

We have frequent timeout problems after upgrading our imap servers from dovecot 1.1.16 to dovecot 1.2.11. One server acts as proxy only, and the other one is the "real" imap server". The credentials for the proxy service are stored in a remote MYSQL database. There were no trouble with dovecot 1.1.16. But now, with the most recent version, we get frequent login failures. It

Dear R Helpers, I am trying to isolate a set of characters between two other characters in a long string file. I tried some of the examples on the R help pages and elsewhere, but I am not able to get it. Your help would be much appreciated. require(scrapeR)

Dear List, I'm trying to get diff/removed data and it's offset out. So I write a functions in receive_data. When I run backup, I found there is a weird behavior which I don't understand. i = recv_token(f_in, &data) will receive (i = -1, offset2 = 0) some where in the middle of the transfer procedure. That's to say, it's going to transfer the first data block from sender,

Hello, LLVM guys. I've tried to emit the following simple function to LLVM assmbly. --------------------------------------------------------- void test(long s, double* a) { char h = ttt(s); *a = s; mmm(); } --------------------------------------------------------- It's spat out as follows: --------------------------------------------------------- void %test(int %s, double* %a) {

Hello, is't possible to specify pattern in levels ? > y=c("ff","f","m","mm","fm","mf","ffm","mmf","mmm","fff"); > factor(y) [1] ff f m mm fm mf ffm mmf mmm fff Levels: f ff fff ffm fm m mf mm mmf mmm I want to specify levels using regexp ("f.*","m.*") or use

Hello all, I was wondering if the following behaviour of margin.table in R 1.3.0 is normal. > mm <- data.frame(x=c(0,0,1), y=c(1,1,0), z=c(0,1,0)) > margin.table(mm,1) [1] 1 2 3 <0 rows> (or 0-length row.names) while using 'apply(x,margin,sum)' I get > apply(mm,1,sum) 1 2 3 1 2 1 which appears to be normal. Similar behaviour when margin=2. On the other hand, the

# I have a dataframe in the following form: track <- c(rep('A', 3), rep('B', 4), rep('C', 4)) value <- c(0.15, 0.25, 0.35, 0.05, 0.99, 0.32, 0.13, 0.80, 0.75, 0.60, 0.44) df <- data.frame(track=factor(track), value=value) #> print(df) #track value #1 A 0.15 #2 A 0.25 #3 A 0.35 #4 B 0.05 #5 B 0.99 #6 B 0.32 #7 B 0.13

Please use dput() to post your example matrix. Rambler1 wrote > > I have run into a problem in my code. What I want to accomplish is this: > I have a user input stock symbols into a list and from there I run the > quantmod package to get historical data. I compute the correlation matrix > and then turn that matrix into a simple matrix with 1's or 0's depending > on

Dear R Helpers, I am trying to write a character value to the row of a data frame and am running into a problem that I don't have when I do this for numeric arguments. For example, the following works just fine: > test<-data.frame(number=numeric(1)) > test[1,]<-.5 > test number 1 0.5 But the following bombs out: > hold<-data.frame(symbol=character(1)) >

I would like to ask if there is some simple way for building a hist from the following data. mm <-c(2,3,0,4,5,0,2,9,0) mmm <- matrix(mm,ncol=3, nrow=3) x <- c(0,1.45,2.9) in mmm there are frequencies (each column is separate histogram and each row corresponds to value of x). So that for the first histogram we have 2 times interval [0,1.45] and 3 times [1.45,2.90]. Thanks a lot!

Have timestamp in format HH:MM:SS.MMM.UUU and need to remove the last "." so it is in format HH:MM:SS.MMMUUU. What is the fastest way to do this, since it has to be repeated on millions of rows. Should I use regex ? Currently doing it with a string split, which is slow: >head(ts) [1] 09:30:00.000.245 09:30:00.000.256 09:30:00.000.633 09:30:00.001.309 09:30:00.003.635

Hi everyone, I have a vector of strings, each string made up by different number of words. I want to get a new vector which has only the first word of each string in the first vector. I came up with this: str <- c('aaa bbb', 'cc', 'd eee aa', 'mmm o n') str1 <- rep(1, length(str)) for (i in 1:length(str)) { str1[i] <- strsplit(str, "

Hi all, I have started stubdom, thank all of you. But I still met a problem, that is I found stubdom block when it run 107s. the message in "xm li" : Domain-0 0 1719 2 r----- 171.9 hvmachine 1 256 1 -b---- 110.6 hvmachine-dm

Hi, I am having a problem figuring out how to extract a subset of rows. I have a list with 68 similar data.frames. Each data.frame is 500 rows by 5 columns. I want to take one row from each data.frame based upon the data in a particular column (i.e. it matches a symbol). For example: > str(database) List of 68 $ X2011.01.11:'data.frame': 500 obs. of 5 variables: ..$ Symbol

The input values could be something like this: 01-Dec-2006 01-December-2006 1-June-2006 Is there an easy to way to get the three variables populated dd, mmm and yyyy for any of the above input values? I tried to look at regex but couldn'' anything simple. Thanks -------------- next part -------------- An HTML attachment was scrubbed... URL:

Dear All, I have two data like this : $cat main.csv name,id,memory,storage mohan,1,100.20,1.10 ram,1,200,100 kumar,1,400,50 xxx,1,100,40 aaa,1,800,45 mount,1,200,80 > main <- read.csv(file='main.csv',sep=',' , header=TRUE) > main name id memory storage 1 mohan 1 100.2 10 2 ram 1 200.0 100 3 kumar 1 400.0 50 4 xxx 1

Hi, If I have an R object UUU, where the second element is U2, based on "g" column of my.table my.table of UUU is: mmm ggg gindex map Info aaa123 U1 1 1 1 aaa124 U1 1 2 1 bbb1378 U2 2 1 1 bbb8888 U2 2 2 0 bbb1389 U2 2 3

I have been attempting to do some work using hclust, and have run into a (possibly subtle) problem. The background is that I constructed a dissimilarity matrix ``d1'' (it involved something called the ``Jaccard similarity coefficient''; I won't go into the details unless requested). I then did d2 <- as.dist(d1) try <- hclust(d2,method=ward)