similar to: Remove Please

Hey Y'all, I've been trying for months to get samba to share my printer with my wife's Win XP machine. I've RTFM, and spent hours on google to no avail. I can't see the printer from Windows so I can't mount it up. Nothing appears in the logs. The file shares work just fine. It looks like I've got Samba 3.6.9 on this machine: [mlapier at mushroom samba]$ rpm -qa

Hello, The openssh client terminates with the following error message when unable to resolve a username: "You don't exist, go away!" Leaving aside style and tone, the message is not informative. Please consider changing it to something more appropriate and helpful, such as "Unable to resolve username". (The message appears in the files ssh-keygen.c and ssh.c, as of

Hi, does anybody manage to get music-on-hold with inaccess oh323 driver? Statement like : exten => 10,1,Dial(OH323/xx,mt) works (dials the xx number) but no music is heared. Also, if I put 'r' (ringback) it doesn't work either. With chan_h323 I got this functionality but this driver had some other problems (call transfer don't work).... Thanx in advance, Victor...

Hi Ashta, There are many ways to do it. Here is one: vars <- sapply(split(DM$x, DM$GR), var) DM[DM$GR %in% names(vars[vars > 0]), ] Best Ista On Wed, Dec 6, 2017 at 6:58 PM, Ashta <sewashm at gmail.com> wrote: > Thank you Jeff, > > subset( DM, "B" != x ), this works if I know the group only. > But if I don't know that group in this case "B", how

subset( DM, "B" != x ) This is covered in the Introduction to R document that comes with R. -- Sent from my phone. Please excuse my brevity. On December 6, 2017 3:21:12 PM PST, David Winsemius <dwinsemius at comcast.net> wrote: > >> On Dec 6, 2017, at 3:15 PM, Ashta <sewashm at gmail.com> wrote: >> >> Hi all, >> In a data set I have group(GR)

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> On Dec 6, 2017, at 4:27 PM, Ashta <sewashm at gmail.com> wrote: > > Thank you Ista! Worked fine. Here's another (possibly more direct in its logic?): DM[ !ave(DM$x, DM$GR, FUN= function(x) {!length(unique(x))==1}), ] GR x y 5 B 25 321 6 B 25 512 7 B 25 123 8 B 25 451 -- David > On Wed, Dec 6, 2017 at 5:59 PM, Ista Zahn <istazahn at gmail.com> wrote:

Hi David, Ista and all, I have one related question Within one group I want to keep records conditionally. example within group A I want keep rows that have " x" values ranged between 15 and 30. group B I want keep rows that have " x" values ranged between 40 and 50. group C I want keep rows that have " x" values ranged between 60 and 75. DM <-

Hi all, In a data set I have group(GR) and two variables x and y. I want to remove a group that have the same record for the x variable in each row. DM <- read.table( text='GR x y A 25 125 A 23 135 A 14 145 A 12 230 B 25 321 B 25 512 B 25 123 B 25 451 C 11 521 C 14 235 C 15 258 C 10 654',header = TRUE, stringsAsFactors = FALSE) In this example the output should contain group A and

Leon Fauster wrote: > Am 03.12.2015 um 15:40 schrieb m.roth at 5-cent.us: >> Valeri Galtsev wrote: >>> >>> On Thu, December 3, 2015 4:28 am, Leon Fauster wrote: >>>> Am 03.12.2015 um 11:08 schrieb Greg Lindahl <lindahl at pbm.com>: >>>> >>>> CentOS 7.1511 (aka '7.2') not yet released ... >>> >>> aka 7.2,

Thank you Ista! Worked fine. On Wed, Dec 6, 2017 at 5:59 PM, Ista Zahn <istazahn at gmail.com> wrote: > Hi Ashta, > > There are many ways to do it. Here is one: > > vars <- sapply(split(DM$x, DM$GR), var) > DM[DM$GR %in% names(vars[vars > 0]), ] > > Best > Ista > > On Wed, Dec 6, 2017 at 6:58 PM, Ashta <sewashm at gmail.com> wrote: >> Thank

> On Dec 8, 2017, at 4:48 PM, Ashta <sewashm at gmail.com> wrote: > > Hi David, Ista and all, > > I have one related question Within one group I want to keep records > conditionally. > example within > group A I want keep rows that have " x" values ranged between 15 and 30. > group B I want keep rows that have " x" values ranged

> On Dec 6, 2017, at 3:15 PM, Ashta <sewashm at gmail.com> wrote: > > Hi all, > In a data set I have group(GR) and two variables x and y. I want to > remove a group that have the same record for the x variable in each > row. > > DM <- read.table( text='GR x y > A 25 125 > A 23 135 > A 14 145 > A 12 230 > B 25 321 > B 25 512 > B 25 123

library(dplyr) DM <- read.table( text='GR x y A 25 125 A 23 135 . . . ) DM %>% filter((GR == "A" & (x >= 15) & (x <= 30)) | (GR == "B" & (x >= 40) & (x <= 50)) | (GR == "C" & (x >= 60) & (x <= 75))) On Fri, Dec 8, 2017 at 4:48 PM, Ashta <sewashm at gmail.com>

Thank you Jeff, subset( DM, "B" != x ), this works if I know the group only. But if I don't know that group in this case "B", how do I identify group(s) that all elements of x have the same value? On Wed, Dec 6, 2017 at 5:48 PM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > subset( DM, "B" != x ) > > This is covered in the Introduction to

All, In case you aren't tracking it, the Developers' Meeting is shaping up nicely. Thanks to everyone who has volunteered to make this a great meeting. http://llvm.org/DevMtgMay2007.html Lots has changed since the last update: Attendance: now 30+ Location: now in the Cupertino Inn (very close to Apple) Speakers: 7 Discussion Topics: 7 And, the big news: T-Shirts. If you want one,

Hello, Try the following. keep <- list(A = c(15, 30), B = c(40, 50), C = c(60, 75)) sp <- split(DM$x, DM$GR) inx <- unlist(lapply(seq_along(sp), function(i) keep[[i]][1] <= sp[[i]] & sp[[i]] <= keep[[i]][2])) DM[inx, ] # GR x y #1 A 25 125 #2 A 23 135 #5 B 45 321 #6 B 47 512 #9 C 61 521 #10 C 68 235 Hope this helps, Rui Barradas On 12/9/2017 12:48 AM, Ashta

> On Dec 8, 2017, at 6:16 PM, David Winsemius <dwinsemius at comcast.net> wrote: > > >> On Dec 8, 2017, at 4:48 PM, Ashta <sewashm at gmail.com> wrote: >> >> Hi David, Ista and all, >> >> I have one related question Within one group I want to keep records >> conditionally. >> example within >> group A I want keep rows that

You could make numeric vectors, named by the group identifier, of the contraints and subscript it by group name: > DM <- read.table( text='GR x y + A 25 125 + A 23 135 + A 14 145 + A 35 230 + B 45 321 + B 47 512 + B 53 123 + B 55 451 + C 61 521 + C 68 235 + C 85 258 + C 80 654',header = TRUE, stringsAsFactors = FALSE) > > GRmin <- c(A=15, B=40, C=60) > GRmax <-

Dear Sir, I am a new user of R and I am doing a tast, which is: find the maximum likelihood estimate of the parameter of Gaussian distribution for generated 100 numbers by using >x=rnorm(100, mean=3, sd=1). I tried to use following Maximum Likelihood function >fn<-function(x) (-50*log((sd(x))^2))-50*log(sqrt(2*pi))-(1/2*((mean(x))^2))*(sum((x-(mean(x))^2)), but it did not work. I am