similar to: "error in rsync protocol data stream (code 12) at io.c(150)" revisited

Environment: - CentOS 5.1, - Apache 2.2.3 - php 5.1.6 - phpMyAdmin 2.11.6 - MySQL 5.0.22 Brand new system, brand new installation of all the above products. All looks well, but when I try to connect to phpMyAdmin, I get an error: "Forbidden: You don't have permission to access /phpMyAdmin/ on this server". I'll forgo all the paths I followed trying to get this to work and cut

We run a third party application that creates an inordinate amount of subdirectories in a single directory. To speed up I/O, I wanted to set the T attribute on the directory that will hold the subdirectories. The "chattr +T /usr/local/lepus-bb/a-0607" command returns status 0, but when I verify the setting, the attribute isn't there: # lsattr -d /usr/local/lepus-bb/a-0607

Given that the default journaling mode of ext3 (i.e. ordered), does not guarantee write ordering after a crash, is this journaling mode safe enough to use for a database such as Oracle? If so, how are out of sync writes delt with? Kind regards, Herta Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm

I'm trying to install CentOS 5.2 on a Dell PE 1850 via the DRAC 4 card, with CentOS-5.2-i386-bin-1of6.iso mounted as virtual media. At the boot prompt, I hit <Enter>, which should start the graphical installation, but it starts off with a text installation. I am asked - whether I want to test the media, which I skip - what language I want to use - I select English - what keyboard I

Environment: Samba server: ?Solaris 10 5/08 ?Samba version 3.0.24 Windows client: ?Windows Server 2003 Service Pack 2 extract from smb.conf: [global] ? ? ? ?workgroup = BBB.CCC ? ? ? ?wins server = xxx.xxx.xxx.xxx ? ? ? ?smb ports = 139 [WINDCHILL] ? ? ? ?path = /ptc/eaiXMLFiles ? ? ? ?force group = plm ? ? ? ?read only = No ? ? ? ?force create mode = 0775 Up till May 12, you could create a

Hello, I have a situation where I have numerous files with numerous hard links to each of them on an ext3 RHEL4.2 system. Some of these files are duplicates of the others. I would like to re-link all of the duplicates to point to a single inode. For instance if file1 has hardlinks link1 and link2, and file2 has hardlinks link3 and link4, I need to change it so that link1, link2 (these

On Fri, 10 Mar 2006, Herta Van den Eynde wrote: > I'm trying to install Red Hat Advanced Server AS 4 on a HP Proliant DL380G4. > Unlike e.g. the DL360, the DL380 does not have the option to set the OS in the > BIOS. > As soon as the installation starts, i.e. even before you get to the point > where you can enter "boot" and whatever boot options you want to use, the

Hello Folks Can anyone help with why I can use ssh like so: [root@morgansoldmachine ~]# ssh -t rsync@192.168.1.40 sudo ssh -i /home/rsync/.ssh/id_dsa root@192.168.1.100 Last login: Tue Mar 24 21:32:51 2009 from morgansmachine.lan [root@morgansoldmachine ~]# logout Connection to 192.168.1.100 closed. Connection to 192.168.1.40 closed. [root@morgansoldmachine ~]# But, when I use the same

Dear Wiza[R]ds, I have a data.frame header that looks like this: v2FfaPre15 v2FfaPre10 v2FfaPre5 v2Ffa2 v2Ffa3 v2Ffa4 I need it to look like this, 15 10 5 2 3 4 i.e., with v2FfaPre and v2Ffa stripped off Any suggestions, Thanks in advance! -- Oscar Oscar A. Linares, MD Translational Medicine Unit LaPlaisance Bay, Bolles Harbor Monroe, Michigan 48161

Dear all, I am trying to avoid a for loop here and wonder if the following is possible: I have a data.frame with 6 columns and i want to get a cross-correlogram (by using ccf) . Obivously ccf only accepts two columns at once and then returms a list. In fact, with a for loop i?d do the following for (i in 1:6) { x[[i]]=ccf(mydf[,i],mydf[,6]) } Is there any chance to the same with

hello, i have been using ccf() to look at the correlation between lightning and electrogamnetic data. for the most part it has worked exactly as expected. however, i have come across something that puzzles me a bit: > x <- c(1, 0, 1, 0, 1, 0) > y <- c(0, 0, 0, 0, 0, 0) > ccf(x, x, plot = FALSE) Autocorrelations of series 'X', by lag -4 -3 -2 -1 0

The question is how to use a URL in place of a file= argument for read.*.functions that do not support this internally. e.g., utils::read.table() and her family all support a file= argument that can take a URL equally well as a local file. So, if I have a file on the web, I can equally well do > langren <- read.csv("langrens.csv", header=TRUE) > langren <-

I´ve several packages for latent class analysis, but I was wondering if there is a package for continuos variables, which allows latent prfile analysis. Thanks for your help in advance, J Toledo _________________________________________________________________ cial-network-basics.aspx?ocid=PID23461::T:WLMTAGL:ON:WL:en-xm:SI_SB_1:092 [[alternative HTML version deleted]]

I am new to R and new to time series modeling. I have a set of variables (var1, var2, var3, var4, var5) for which I have historical yearly data. I am trying to use this data to produce a prediction of var1, 3 years into the future. I have a few basic questions: 1) I am able to read in my data, and convert it to a time series format using 'ts.' data_ts <- ts(data, start = 1988, end =

Dear R-users, I have been using R and its core-packages with great satisfaction now for many years, and have recently started using the "ccf" function (part of the "stats" package version 2.16.0), about which I have a question. The "ccf"-algorithm for calculating the cross-correlation between two time series always calculates the mean and standard deviation per time

Dear All, I am studying some process measurement time series in R and trying to identify time delays using cross-correlation function ccf. The results have however been bit confusing. I found a couple of years old message about this issue but unfortunately wasn't able to find it again for a reference. For example, an obvious time shift is observed between the measurements y1 and y2 when the

Hi. It's my understanding that a cross-correlation function of vectors x and y at lag zero is equivalent to their correlation (or covariance, depending on how the ccf is defined). If this is true, could somebody please explain why I get an inconsistent result between cov() and ccf(type = "covariance"), but a consistent result between cor() and ccf(type = "correlation")? Or

Dear R gurus, I would like to use the ccf function on two matrices that are each 196000 x 12. Ideally, I want to be able to go row by row for the two matrices using apply for the ccf function and get one 196000 X 1 array output. The apply function though wants only one array, no? Basically, is there a way to use apply when there are two arrays in order to do something like correlation on a row

Hi, I have missing values in my time series. "na.action = na.pass" works for acf and pacf. Why do I get the following error for the ccf? > ts(matrix(c(dev$u[1:10],dev$q[1:10]),ncol=2),start=1,freq=1) Time Series: Start = 1 End = 10 Frequency = 1 Series 1 Series 2 1 68.00000 138.4615 2 70.00000 355.5556 3 68.76000 304.3200 4 68.00000 231.4286 5 69.74194 357.4963 6

Hi, I have been running the ccf() function to find cross-correlations of time series across various lags. When I give the option of plot=TRUE, I get a plot that gives me 95% confidence interval cut-offs (based on sample covariances) for my cross-correlations at each lag. This gives me a sense of whether my cross-correlations are statistically significant or not. However, I am unable to get R to