similar to: Trouble converting hourly data into daily data

I've just put up (12:00 noon NZ) yet another tmp.zip with the fixes for Peter Dalgaards two bugs. Niels reports that the 3.51 problems are now different but not solved. I'm trying to locate a 3.51 machine and will post another fix. Can I get some feedback on how people want these "patches" delivered? Should I be numbering them and keeping the old patches? I don't want to

Hello R users, I'm a newby to R (and programming software at large) and I would need some help to sum up event data at discreet time and irregular time interval into a hourly frequency. Here is an example of my time series frame (irregular time-serie object - irts in the tseries package): time value 2008-12-19 19:11:03 GMT 1 2008-12-19 19:12:00 GMT 0 2008-12-19

I have a data frame (morgan) of hourly river flow, river levels and wind direction and speed thus: Time hour lev.morgan lev.lock2 lev.lock1 flow direction velocity 1 2009-07-06 15:00:00 15 3.266 3.274 3.240 1710.6 180.282 4.352 2 2009-07-06 16:00:00 16 3.268 3.272 3.240 1441.8 192.338 5.496 3 2009-07-06 17:00:00 17 3.268

Hi, I would appreciate if somebody could help me with this small issue... I have a dataframe like this (originaly has more than 100 000 rows): > subz jul time dtime fix ddawn ddusk day 101608 15006 2011-02-01 19:14:49 19.24694 noon 7.916667 19.88333 1 101609 15006 2011-02-01 19:24:49 19.41361 midnight 7.916667 19.56667 1 101610 15006 2011-02-01

For some reason I cannot fathom, cron.hourly runs twice each hour on one of my two CentOS-5.4 systems, as reported in /var/log/cron: ------------------------- Mar 16 14:01:01 helen crond[27833]: (root) CMD (run-parts /etc/cron.hourly) Mar 16 14:01:01 helen crond[27834]: (root) CMD (run-parts /etc/cron.hourly) ------------------------- On the other it just runs once, as expected.

Hi, I want to sort a data frame by multiple columns and then take the first record in each unique level of the "by" group I used to sort the data frame. Does someone have an example of how to do this? Thanks, Matt -- It is from the wellspring of our despair and the places that we are broken that we come to repair the world. -- Murray Waas

Hello Given the following data for a data set called airquality. To identify the nature of the objects from the data set airquality example "Ozone" would it be best to use the command is. like is.character(airquality$Ozone) ....... I tried attributes(airquality$Ozone) but it came up null. Would there be a better way to identify these objects. Thanking you in advance for your

Hello, I have a challenge! I have a large dataset with three columns, "date","temp", "location". "date" is in the format %m/%d/%y %H:%M, with a "temp" recorded every 10 minutes. These temperatures of surface temperatures and so fluctuate during the day, heating up and then cooling down, so the data is a series of peaks and troughs. I would like

I have data from several sensors that recorded data at hourly intervals during seven months. I want to separate daily variation from the trend, and also be able to zoom in on only one month of data. I have not been able what functions to use, I can not figure out from the help for 'ts' how to use hourly data. I guess this is routine-work for a lot of people so I hope someone can

I would like to use the "row number" information returned from performing a subset command on a dataframe. For example, I would like to automatically delete some rows from a dataframe if they match a criteria. Here is my example below. data(airquality) names(airquality) subset(airquality, airquality$Month == 6) Now how do I delete the row numbers returned automatically? I

Is there a place that shows how to create two plots that are stacked on top of each other where they share a common x-axis scale, but have differnt y-axis scale? Say have the following data: airquality Stack plot(airquality$Day, airquality$Wind) on top of plot(airquality$Day, airquality$Temp). I am interested in stacking the two on top of each other with no seam, or plotting the two lines with

Hello Pete, On Mon, 02 Jul 2018 09:59:17 +0100 Pete Biggs <pete at biggs.org.uk> wrote: > > > > So, service is running but what could happen that makes /etc/cron.* not > > being fired? > > You don't say, but if this is CentOS 7, then cron.daily/weekly/monthly > is run using anacron, not cron. Oops, yes CentOS 7, sorry. For the record: # service anacron

I would like to add a column to the airquality dataset that contains the date 1950-01-01 in each row. This method does not appear to work: > attach(airquality) > data1 <- transform(airquality,Date=as.Date("1950-01-01")) Error in data.frame(list(Ozone = c(41L, 36L, 12L, 18L, NA, 28L, 23L, 19L, : arguments imply differing number of rows: 153, 1 I can't decipher what

> > So, service is running but what could happen that makes /etc/cron.* not > being fired? You don't say, but if this is CentOS 7, then cron.daily/weekly/monthly is run using anacron, not cron. It's configured in /etc/anacrontab and is usually run once a day by the script /etc/cron.hourly/0anacron - cron.hourly is still run by cron. If the script doesn't exist, then

Is there any reason why 'attach' is not generic in R? I notice that it is in another system, for example, and I can see some applications if it were so in R. Bill Venables. Bill Venables, CMIS, CSIRO Laboratories, PO Box 120, Cleveland, Qld. 4163 AUSTRALIA

greetings on a simple CentOS 4 DNS server install i have the below info. crontab -l "shows nothing" pico /etc/crontab shows... SHELL=/bin/bash PATH=/sbin:/bin:/usr/sbin:/usr/bin MAILTO=root HOME=/ # run-parts 01 * * * * root run-parts /etc/cron.hourly 02 4 * * * root run-parts /etc/cron.daily 22 4 * * 0 root run-parts /etc/cron.weekly 42 4 1 * * root run-parts /etc/cron.monthly i

When I have multiple scripts in /etc/cron.hourly/ using noanacron do they all start at same time or sequentially? I would rather they all went at same time in case one takes close to an hour to complete.

My apologies in advance for my thickness but I can't seem to solve the following, seemingly simple, data manipulation problem: I have a data frame that contains multiple factors and multiple continuous response variables, but duplicates of some factor combinations. The duplicates contain bad data, so I would like to eliminate the duplicates. I would like to retain the entire rows

Dear list, I get the following message when I use rcorr in library "Hmisc" ------------------------------------------------------ > rcorr(lskPox0t30, type=c("spearman")) Error in "[<-.data.frame"(*tmp*, is.na(x), value = 1e+30) : matrix subscripts not allowed in replacement ------------------------------------------------------ I do not understand

Dear R list, members of my course have encountered the following error message: > slm <- lm(price ~ engsize, autoframe) Error in get(x, envir, mode, inherits) : variable "FUN" was not found [more context is given in the fuller listing below]. Once the error is encountered it seems to persist; for example early in one session: > summary(blin.fit) Call: lm(formula = Response