similar to: axis tick colors: only one value allowed?

"Not that it really matters, but" Can someone explain how the row numbers get assigned in the following sequence? It looks like something funky happens when rbind() coerces 'bar' into a dataframe. In either sequence of rbind below, once you get past the first two rows, the row numbers count normally. Rgames> (foo<-data.frame(x=5,y=4,r=3)) x y r 1 5 4 3 Rgames>

This question attacked me as I was thinking about matrix value updates. I probably will never need to do this, but wanted to ask if there are efficient methods to perform the for-loop in the following sequence. %xymat<-matrix(rep(0,100) nr=10,nc=10) # empty matrix %x<-1:10 %y<-sample.int(10,10,rep=T) %for (j in 1:10) xymat[x[j],y[j]] <- some_function(x[j],y[j]) #to create either

HI, Sorry Carl, I received your message in my spam folder. Sarah proposed me a good example of code. Thank you Momadou  ________________________________ De : Carl Witthoft [via R] <ml-node+s789695n4188375h96@n4.nabble.com> Envoyé le : Mardi 13 Décembre 2011 3h34 Objet : Re: Polygon Please read the posting guide and provide a (small) reproducible example of your data. The statement

Hi I want to generate 4 random number which sum up to 100 always Please help ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/runif-with-condition-tp4278704p4278704.html Sent from the R help mailing list archive at Nabble.com.

Hi, While playing with quantile-quantile plots, I wrote up some code which plots something strangely different. Here's the pseudocode: testhist <- hist(sample_data) refhist <- hist(rnorm(n, mean=0,sd=1)) # for some large-ish n cumtest <- cumsum(testhist) cumref <- cumsum(refhist) plot(cumref,cumtest) This produces a straight line of slope 1 for a sample with the same

Hi, I would like to produce a plot with a symbol on every nth point in a time series data, like the one in the following: http://www.phon.ucl.ac.uk/home/yi/ProsodyPro/EnglishFocus.png x <- seq(-100,1000,25) plot(x,type="l") Could someone help me out with the above example? Thanks.... [[alternative HTML version deleted]]

Would like to know how much data can R process - number of rows and columns? [[alternative HTML version deleted]]

Hi everybody, I have a matrix with 3 columns (Date, MeanArea and SdArea). I want to draw a figure showing the variable MeanArea in terms of the Date. But instead to use the variable SdArea as bar error, I want to use ?polygon error?. I use this code but the output does not seem good.

Dear all I tried to find some packages (or programs) for image analysis and especially fractal dimension image analysis but so far I had not success. It shall be used for particle surface layer analysis from TEM images. Any suggestions? Best regards Petr

Esteemed colleagues I wonder if there is a package in R that performs the functions of the Excel SOLVER. Thanks in advance for the reply. Best regards, ------------------------- Estimados colegas Me pregunto si hay un paquete en R que funcione como el SOLVER de Excel. De antemano gracias por la respuesta. Saludos, -- Ricardo Bandin Llanos rbandin@udec.cl [c] Magíster Cs. m. Pesquerías

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I followed a couple threads from the archives and from stackoverflow.com, and would like to know: just what is "..." ? What I mean by this is,for example, from the point of view of a user running a function in debug mode, is "..." an object, or does it exist in the current environment as some thingy? Maybe a better question to ask is: if I were to write some function

Dear list, I have been struggling for some time now with this code... I have this vector of unique ID "EID" of length 821 extracted from one of my dataframe (skate). It looks like this: > head(skate$EID) [1] "896-19" "895-8" "899-1" "899-5" "899-8" "895-7" I would like to remove the complete rows in another dataframe

Dear All, I have a bunch of data points as follows: x  100 y  200 z  300 ... where 100, 200, 300 are the values. I would like to know the distribution of my data? how can I fit my data into a distribution? Thanks a lot, Andra [[alternative HTML version deleted]]

Hi there ! I've got 7 Samples that may contain 29 differents kinds of material.... every line below corresponds to a differente kind of material, example: Sample 1, 2,3,5 and 6 has material 1 .... So I want to know how can I do a Venn Diagram with the data below .... ps ( it was generated by a csv, where every line is sep with (";")) Can someone helps me ? thanks csv file :

Everyone, I'm working with scatter plots with different colored symbols (via lattice). I'm currently using these colors for points and lines: col1 <- c(rgb(1, 0, 0), rgb(0, 0, 1), rgb(0, 1, 0), rgb(0.55482458, 0.40350876, 0.04166666), rgb(0, 0, 0)) plot(seq(along = col1), pch = 16, col = col1, cex = 1.5) I'm also using these with transparency (alpha

I want to create a list of functions in a for loop, with the index of the loop appearing explicitly in the function code. After quite a bit of thrashing around I figured out how to do it. Here is a toy example: junk <- vector("list",4) for(i in 1:4) { itmp <- i junk[[i]] <- eval(bquote(function(x){42 + .(itmp)*x})) } So I'm *basically* happy, but there's

> d = data.frame(gender=rep(c('f','m'), 5), pos=rep(c('worker', 'manager', 'speaker', 'sales', 'investor'), 2), lot1=rnorm(10), lot2=rnorm(10)) > d gender pos lot1 lot2 1 f worker 1.1035316 0.8710510 2 m manager -0.4824027 -0.2595865 3 f speaker 0.8933589 -0.5966119 4 m sales

People, I'm researching some Bayesian statistic topics and in the midle of my study i found a very simple problem and i'm trying to find a simple package to solve this type of equations: Lets say that i need to compute beta values for the beta distribution and i now for example: E(teta)=a/(a+b) = 0,5 Var(teta)=ab/((a+b)^2(a+b+1))=0.05 So if i want to solve this to non-linear system to

Hi all, I'd like to plot the Real and Imaginary parts of some f(z) as two different surfaces in wireframe (the row/column axes are the real and imag axes). I know I can do it by, roughly speaking, something like plotz <- expand.grid(x={range of Re(z)}, y={range of Im(z), groups=1:2) plotz$func<-c(Re(f(z),Im(f(z)) wireframe(func~x*y,data=plotz,groups=groups) But that seems like a