similar to: Titelpage pdf-manual, packaging

Hi, I want to create a pdf of my Man-pages from my package. Therefore I run in the terminal Rd2pdf on the package and a pdf of all the pages is created. After the titlepage there is the general package page, which includes "Description" and "Details" etc. Unfortunately after the Subtitle "Details" there is a pagebreak (and 3/4 white page) which I did not set

In re-factoring my optimx package, I'm finding that the pdf output has some lines that are outside the margins (and there are warnings in R CMD check optimx). Clearly I can fix this by editing the tex file that is generated, but the build infrastructure would still get things wrong in automatic processing. So that gives rise to 3 questions: 1) How do I adjust the DESCRIPTION file to avoid too

Hi, I just started with writing functions in R and so some questions popped up. I provide some values as argument to my function such as: function(a,b,c){} Now i want that the function first checks if the arguments are valid for the function. E.g argument "a" has to be a number in the range 0-1. How can that easily done? So far I have: a <- as.numeric(a) if(0 <= a &&

Hello, I want to use a for loop for repeadely calculating a maxent model (package dismo, function maxent()) which creates an object of the class maxent (S4). I want to collect all the resulting object in a list. I tried to simplify my for loop to explain what I want. There are two problems/questions: 1) How can I create the new variables in the loop (using paste) and assign the objects 2) How

Just to inform: I posted that before in R-sig-ecology but as it might be interesting also for other useRs, I post it also to the general r-user list: Hello Alexandre, thank you very much. I also found another way to extract summarizing information from lm results over e.g. 1000 repeated model runs: results2 <- t(as.data.frame(results)) summary(results2) Although some questions popped up in

Hi, I have a dataframe and want to remove columns from it that are populated with a similar value (for the total column) (the variation of that column is 0). Is there an easier way than to calculate the statistics and then remove them by hand? A <- runif(100) B <- rep(1,100) C <- rep(2.42,100) D <- runif(100) df <- data.frame(A,B,C,D) # if want to conditionally remove column B and

This is what I found useful when put samba and CUPS together. diff -ur samba-3.0.1.orig/docs/htmldocs/CUPS-printing.html samba-3.0.1/docs/htmldocs/CUPS-printing.html --- samba-3.0.1.orig/docs/htmldocs/CUPS-printing.html 2004-01-28 10:56:08.000000000 +0800 +++ samba-3.0.1/docs/htmldocs/CUPS-printing.html 2004-01-28 11:23:07.000000000 +0800 @@ -1850,7 +1850,11 @@ parameter (which tries to prepare

Hi, I have a 1-column dataframe with rownames and I want to sort it based on the single column. The typical procedure that is recommended in diverse posts is to use order in the index. But that "destroys" my dataframe structure. Probabaly it is a very simple solution. Here is a short reproducable example: x <- c(1,3,51,2,34,44,12,33,2,8) df <- data.frame(x) rownames(df) <-

Dear list, I am trying to produce a pdf manual using Rtools (version 3.1.0.1936) on Windows 8 (64-bit). I am also aware of the inconsolata issue posted in the forum (https://stat.ethz.ch/pipermail/r-devel/2013-June/066850.html), and then I have installed the patched version of R-3.0.1. However I still have some errors with the following message: R CMD Rd2pdf mypack Hmm ... looks like a package

Hello, just to follow up a question from last week. Here what I've done so far (here an example): library(MCMCpack) Y=c(15,14,23,18,19,9,19,13) X1=c(0.2,0.6,0.45,0.27,0.6,0.14,0.1,0.52) X2a=c(17,22,21,18,19,25,8,19) X2b=c(22,22,29,34,19,26,17,22) X2 <- function()runif(length(X2a), X2a, X2b) model1 <- MCMCregress(Y~X1+X2()) summary(model1) but I am not sure if my X2-function is

Hi, I'd like to know if it is possible to use wildcards * for indexing... E.g. I have a vector of strings. Now I'd like to select all elements which start with A_*? I'd also need to combine that with logical operators: "Select all elements of a vector that start with A (A*) OR that start with B (B*)" Probably that is quite easy. I looked into grep() which I think might

I construct a pdf package manual in Windows 7 using R CMD Rd2dvi --pdf --no-preview [packagename] Page numbers are listed correctly under 'R topics documented' at the front, but incorrectly (offset by -2 pages) in the Index at the back. Following the hyperlinked page numbers in the Index takes you to the wrong page. 2 pages happens to be the length of the package overview man page inserted

Hello, assume we have following dataframe: group <-c(rep("A",5),rep("B",6),rep("C",4)) x <- c(runif(5,1,5),runif(6,1,10),runif(4,2,15)) df <- data.frame(group,x) Now I want to select all cases (rows) for those groups which have more or equal 5 cases (so I want to select all cases of group A and B). How can I use the indexing for such questions? df[??]...

Hi, I would like to plot some extra text in my plot. This should be a two line text including a special character (sigma). I tried so far a to use expression in combination with paste and "\n"... but I can't get the line break... Here what I've done so far: plot(1,type="n", xaxt='n', yaxt='n', ann=FALSE) text(1,1,labels=expression(paste(sigma,"\n

Hello, I am doing a simple regression using lm(Y~X). As my response and my predictor seemed to be skewed and I can't meet the model assumptions. Therefore I need to transform my variables. I wanted to ask what is the preferred way to find out if predictor and/or response needs to be transformed and if yes how (log-transform?). I found a procedure in "A modern approach to Regressoin in

Dear R-users, please consider the following minimal example: \documentclass[a4paper,titlepage,onecolumn,12pt]{article} \usepackage[italian]{babel} \usepackage{amssymb} \usepackage[utf8x]{inputenc} \usepackage[pdftex]{graphicx} \begin{document} <<label=test, echo=FALSE, results=tex>>= df.data1 <- cbind.data.frame(A = rnorm(18), B =factor(rep(LETTERS[1:6],

Hi, I want to split a dataframe based on a grouping variable (in one column). The resulting new dataframes should be stored in a new variable. I tried to split the dataframe using split() and to store it using a FOR loop, but thats not working so far: df <- data.frame(A=c("A1","A1","A2","A2"),B=seq(1:4)) Fsplit <- function(x,y){ ls <-

Hello, probably it is quite easy but I can get it: I have mulitple numeric vectors and a function using all of them to calculate a new value: L <- c(200,400,600) AR <- c(1.5) SO <- c(1,3,5) T <- c(30,365) fun <- function(L,AR,SO,T){ exp(L*AR+sqrt(SO)*log(T)) } How can I get an array or dataframe where all possible combinations of the factors are listed and the new value is

Hello, I'd like to perform a regression using MCMCregress (MCMCpack). One variable therefore should be a function rather than a variable: I want to use X as an input and X should be defined as a random number between to values. Therefore I want to use the function runif like: X <-(1, Xa, Xb) but it seems that runif doesn't allow to use vectors. So I think I've to calculate the new

Hi, I used to use reshape and moved to reshape2 (R 2.15.1). Now I tried some of my older scripts and was surprised that my cast function wasn't working like before. What I did/want to do: 1) Melt a dataframe based on a vector specifying column names as measure.vars. Thats working so far: dfm <- melt(df, measure.vars=n, variable_name = "species", na.rm = FALSE) 2) Recast the