Displaying 5 results from an estimated 5 matches similar to: "Help! I couldn't put multiple qplot on the same page..."
2007 May 23
0
Changing sequential regression code to call systemfit
I use code ( actually its code from vars package and its directly below
) to do a sequence of lm calls and the data I use from the matrix
depends on restrictions.
for(i in 1:K){
datares <- datasub[, which(x$restrictions[i, ] == 1),drop=FALSE]
y <- yendog[, i]
lmres <- lm(y ~ -1 + ., data=datares)
# x$varresult[[i]] <- lmres
# x$resid[, i] <-
2011 May 02
2
Lasso with Categorical Variables
Hi! This is my first time posting. I've read the general rules and
guidelines, but please bear with me if I make some fatal error in
posting. Anyway, I have a continuous response and 29 predictors made
up of continuous variables and nominal and ordinal categorical
variables. I'd like to do lasso on these, but I get an error. The way
I am using "lars" doesn't allow for the
2009 Oct 31
3
Plots with k-means
Hi,
I'm doing a k-means cluster with 6 clusters and 15 variables. Any
suggestions on how to plot the results?
I've tried the standard xy plot, but couldn't get much of it.
Thansk in advance,
Iuri.
2011 Jun 24
2
counting columns that fulfill specific criteria
Hi,
I have a matrix (pwdiff in the example below) with ~480000 rows and 780
columns.
For each row, I want to get the percentage of columns that have an absolute
value above a certain threshold "t". I then want to allocate that percentage
to matrix 'perc' in the corresponding row. Below is my attempt at doing
this, but it does not work: I get 'replacement has length
2004 Feb 08
2
substitute, eval, quote and functions
Hi,
i am working with large data frames with many dependend variables. I
want to write some functions that will allow me to quickly select
variables from the frame and plot them in various colors depending on
factor columns, possibly selecting rows according to factor conditions.
In order to do this in a nice function, i need to understand how to work
with a column name in the body of a