similar to: help wrapping findInterval into a function

HI, I am using Windows XP and R version 2.9.2. I have a data frame written by R similar to the following: Lab_ID Analysis_Soil Results -4MAD -2.5MAD +2.5MAD +4MAD 55003 Calcium-2008-116 900 961 1121.5 1656.5 1817 55003 Calcium-2008-117 3321 2175 2380.5 3065.5 3271 55003

What should findInterval(x,vec,all.inside=TRUE) return when length(vec)<=1, so there are no inside intervals? R-3.3.0 gives a decreasing map of x->output when length(vec)==1 and -1's when length(vec)==0. Would '0' in all those cases be better? > findInterval(x=c(10, 11, 12), vec=11, all.inside=TRUE, rightmost.closed=FALSE, left.open=FALSE) [1] 1 0 0 >

Hello Wise Ones... I need a clever way around a problem with findInterval. Consider: vec1 <- 1:10 vec2 <- seq(1, 10, by = 0.1) x1 <- c(2:3) a1 <- findInterval(x1, vec1); a1 # example 1 a2 <- findInterval(x1, vec2); a2 # example 2 In the problem I'm working on, vec* may be either integer or numeric, like vec1 and vec2. I need to remove one or more sections of this vector;

Dear R users, the help for findInterval(x,vec) suggests a logarithmic dependence on N (=length(vec)), which would imply a binary search type algorithm. However, when I "test" this hypothesis, in the following manner: set.seed(-3645); l <- vector(); N.seq <- c(5000, 500000, 1000000, 10000000, 50000000);k <- 1 for (N in N.seq){ tmp <- sort(round(stats::rt(N, df=2), 2));

I've found over time that R documentation that comes off as terse at first blush is usually revealed to be precise, concise, and complete on close reading.? I'm sure this is also true of `?findInterval`, but for whatever reason my brain simply refuses to extract meaning from it. Part of the problem may be that we interact with the function via a compressed form of the bounds of the

I have a batch of data in each line of data contains three values, calcium score, age, and sex. I would like to predict calcium scores as a function of age and sex, i.e. calcium=f(age,sex). Unfortunately the calcium scorers have a very "ugly distribution". There are multiple zeros, and multiple values between 300 and 600. There are no values between zero and 300. Needless to say, the

Hi all, I am writing some C code where I want to use the findInterval function documented in "Writing R extensions/Utility functions". i.e. the C-version not the R version. It all compiles but the shared library is causing seg-faults and I'm obviously stuffing something up. Has anyone got any examples of calling this function they'd be will to share? I've searched through

Deepayan: Sorry for the additional email, but I'm concerned that I wasn't being clear. In the end, I would like a graphic that portrays my y-values on a log scale in their native data range. That is to say, I would prefer to see the axis labels as 1000 rather than 3 (log10 of 1000). Thank you for your kind assistance, Hobie Perry St. Paul, MN Hobie Perry <hobie_perry@yahoo.com>

I am submitting the command: calcium<-read.table("calcium.txt",header=TRUE) and with Rw0630 and Bdr0631 I get an application error and R crashes. But the command works fine with rjune. I am running under NT4.0 Anyone have a similar problem? Jeff jmorris at ocdus.jnj.com -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

>>>>> brodie gaslam via R-devel >>>>> on Thu, 5 Mar 2020 22:18:33 +0000 (UTC) writes: > I've found over time that R documentation that comes off as terse at > first blush is usually revealed to be precise, concise, and complete > on close reading.? I'm sure this is also true of `?findInterval`, but > for whatever reason my

Dear Colleagues, I am attempting to develop an optimization routine for a river suspended sediment mixing model. I have Calcium and Magnesium concentrations (%) for sediments from 4 potential source areas (Topsoil, Channel Banks, Roads, Drains) and I want to work out, based on the suspended sediment calcium and magnesium concentrations, what are the optimal contributions from each source area to

Tengo 2 grandes inquietudes: Necesito aplicar la función findInterval a una lista donde su componentes son matrices(32x32), cuyos intervalos se conformaron de la siguiente manera: 1er paso. # a todas las matrices se las dividió en matrices superiores e inferiores d_sup <- lapply(Matriz,function(x){data.matrix(upper.tri(x)*x)}) d_inf <-

Is there a generic binary search routine in a standard library which a) works for character vectors b) runs in O(log(N)) time? I'm aware of findInterval(x,vec), but it is restricted to numeric vectors. I'm also aware of various hashing solutions (e.g. new.env(hash=TRUE) and fastmatch), but I need the greatest-lower-bound match in my application. findInterval is also slow for

> On Apr 19, 2018, at 1:22 PM, David Winsemius <dwinsemius at comcast.net> wrote: > > >> On Apr 19, 2018, at 11:20 AM, Ding, Yuan Chun <ycding at coh.org> wrote: >> >> Hi All, >> >> I want to create a categorical variable, cat.pfoa, in the file of pfas.pheno (a data frame) based on log2pfoa values. I can do it using the following code.

> On Apr 19, 2018, at 11:20 AM, Ding, Yuan Chun <ycding at coh.org> wrote: > > Hi All, > > I want to create a categorical variable, cat.pfoa, in the file of pfas.pheno (a data frame) based on log2pfoa values. I can do it using the following code. > > pfas.pheno <-within(pfas.pheno, {cat.pfoa<-NA > cat.pfoa[pfas.pheno$log2pfoa

Hi, I am trying to label the x-axis of some histograms with the units of measurement. However, when I use, for example: > truehist(Ca, prob=FALSE, col="gray", xlab=expression(paste("Calcium (", mu, eq^-1, ")"))) I get the following message: Error in eval(expr, envir, enclos) : Object "mu" not found Could someone let me know what I'm doing wrong?

In findInterval's help page, it says 'v[i[j]] <= x[j] < v[i[j] + 1]'. I'm wondering if there is a variant of it such that 'v[i[j]] < x[j] <= v[i[j] + 1]'.

I don't find how to do what I need to do in Dalgaard or 'R Cookbook', so I'm asking here. I have a data frame with water chemistry data and I want to start exploring these data. There are three factors (site, date, chemical) associated with each measurement. The data frame looks like this: > summary(chemdata) site_id.sample_date.param.quant

I am attempting to emulate the VLOOKUP function from Excel in R. I want to compare one column (coll.minus.release) with another (release.days) to get the number of parasitoid released at that time (TotalParasitoids). for example: coll.minus.release release.days ParasitoidTotal -12 -266 1700 8 -259 1000 8

On Thu, Apr 14, 2011 at 7:02 PM, <rcpp-devel-request at r-forge.wu-wien.ac.at> wrote: > I was able to write a very short C++ function using the Rcpp package > that provided about a 1000-fold increase in speed relative to the best > I could do in R. ?I don't have the script on this computer so I will > post it tomorrow when I am back on the computer at the office. > >