similar to: Data alignment

Hello Hello I have a data frame, x, holding 5 persons answering the question which cars they have used: # the data frame x <- as.data.frame( matrix( c('BMW', '', '', 'Mercedes', 'VW', '', 'Skoda', 'VW', 'BMW', '', '', '', 'VW', 'Skoda',

Hello! If I have a vector vec <- c(FALSE, FALSE, TRUE, FALSE, TRUE, TRUE, FALSE FALSE) I can I create the following order of numbers based on vector vec: 1, 2, 2, 3, 3, 3, 4, 5 Whenever there is a FALSE I increase the number (starting with 1). Whenever there is a TRUE I set the same number as the previous FALSE has been assigned to. I would be happy for any input Cheers, Syrvn -- View

Hello, consider the following data.frame df and vector v df <- data.frame(group = c("A","B","C","D"), value = c(1,2,3,4)) v <- c(2,3) How can I return a sub data.frame which has only the rows left where value matches v df: group value B 2 C 3 Cheers -- View this message in context:

Hi, let's assume I have the following vector a: 1 5 23 How can I use R to duplicate the elements so that my new vector looks like: 1 1 5 5 23 23 Many thanks, Syrvn -- View this message in context: http://r.789695.n4.nabble.com/Duplicate-elements-of-a-vector-tp3879561p3879561.html Sent from the R help mailing list archive at Nabble.com.

Hello, can anybody tell me how to produce a plot like the one in http://cran.r-project.org/web/packages/lme4/vignettes/Implementation.pdf on page 13, Figure 6? The data is stored in: library(nlme) data(Oats) Cheers -- View this message in context: http://r.789695.n4.nabble.com/Help-needed-in-reproducing-a-plot-tp4119603p4119603.html Sent from the R help mailing list archive at

Hello! with the R system command I would like to call a perl script which needs an input directory and an output directory in form of a path. When I put in the path directly it works. The script line looks as follows: system("perl '../path1' '../path2' '../path3'") If I store the path in a variable/object and call the perl script again it does not run and I

Hello, with Sys.time() you get the following string: "2011-11-15 16:25:55 GMT" How can I extract the following substrings: year <- 2011 month <- 11 day_time <- 15_16_25_55 Cheers, Syrvn -- View this message in context: http://r.789695.n4.nabble.com/Extract-pattern-from-string-tp4073432p4073432.html Sent from the R help mailing list archive at Nabble.com.

Hi, the R code: a <- matrix(c(1,5,4,3,7,10,34,4,3,8,6,5,12,17,45,3,2,45,46,47,3,4,22,12,21), nrow=5) rownames(a) <- c("a","b","c","d","e") a a[which(a[,3] < 8), ] a[which(a[,3] < 6), ] produces the following output: > a [,1] [,2] [,3] [,4] [,5] a 1 10 6 3 3 b 5 34 5 2 4 c 4 4 12 45 22 d

Hello, I am working on a big R project using Eclipse/StatET/Texlipse. I'd like to write a Latex document within that project but DO NOT want to Sweave it. It's pure Latex. Via the external tools configurations I set up 2 different versions to ensure that my latex document is processed correctly. Version 1 (System Call): library(tools) setwd("${container_loc}") file =

Hello, I am running Windows 7 and R-2.13 in StatET. When I try to create a directory it does not print any errors but if I check outside eclipse if it exists or do a refresh in Eclipse the directory is not been created. The strange thing is that it happens only to some sub-folders... On the other hand when I use the normal windows explorer in one of these sub-folders and create a folder it

Hello, since 3 days now I try to get pgfSweave running using Eclipse + StatET. I created a super simple .Rnw file which can be viewed here: http://www.text-upload.com/read.php?id=147992&c=6441045 test.Rnw When I use sweave it works perfectly fine but when I use pgfSweave I get an error. The R output can be viewed here: http://www.text-upload.com/read.php?id=147995&c=3804886 R output

Hi, imagine the following matrix/data.frame Letter Number a 1 a 1 b 1 b 0 c 0 c 1 d 0 d 0 If the numbers for two identical letters are also identical then I want to remove either the first or the second row of that letter. If for a letter the numbers are 1 and 0 I want to remove the row with the 0. That means if the code works I would and up with the following matrix/data.frame Letter

Hello, when I use list.files with recursive = TRUE and all.files = TRUE, R returns a list of strings/paths. >From all those strings I want to keep only the ones starting with a . I tried using grep to achieve that. However, the problem is that because of the recursive list.files parameter, for some files beginning with a . there is a path attached. I think it is not as simple as it looks

Hello, I am stuck with the following problem. Consider the vector: vec <- c(2,4,6,9,10) I now want to use R to manipulate the vector as follows: [1] 2, 4, 2, 6, 2, 9, 2, 10 In words, the first element of the vector should be placed in front of each following number. Which R commands do I need to achieve that? Cheers -- View this message in context:

Greetings all. Any help with the following would be appreciated. I want to create a data frame for each file in a directory. The following code does not work but it may show what I am trying to do: carmakes <- c('BMW','Chrysler','Citroen','Fiat','Ford','Holden','Honda',

Hello, I have a simple question but I don't know which method is best to use for my problem. I have the following strings: str1 <- "My_name_is_peter" str2 <- "what_is_your_surname_peter" I would like to apply predefined abbreviations for peter=p and name=n to both strings so that the new strings look like the followings: str1: "My_n_is_p" str2:

Dear group, I am working on a rather big project where the output data frames have dimensions of 3000 x 15 or greater. We are using xlsx and xlsx2 to write the data.frames to Excel sheets. Since recently we get the following error, when trying to write the data frames to the excel sheets: Error in ls(envir = envir, all.names = private) : invalid 'envir' argument We figured out that

Hi, Is there a simple way of doing the following in R? a <- data.frame(name = c(rep("A", 3), rep("B", 5), rep("C", 10))) > a name 1 A 2 A 3 A 4 B 5 B 6 B 7 B 8 B 9 C 10 C 11 C 12 C 13 C 14 C 15 C 16 C 17 C 18 C Do some fancy R code here: > a name val 1 A 1 2 A 2 3 A 3 4

Hello, I think I am right in saying that a 2 sample wilcox.test is equal to a 2 sample kruskal.test and a 2 sample t.test is equal to a 2 sample anova. This is also stated in the ?kruskal.test man page: The Wilcoxon rank sum test (wilcox.test) as the special case for two samples; lm together with anova for performing one-way location analysis under normality assumptions; with Student's t

Hi list, I tried to convert a data.frame into a matrix using data.matrix. Unfortunately my matrix contains missing values (NA) wherefore all columns including NA's were changed into factors. I thought that many people stumbled across that problem already wherefore there must be a simple solution. But it seems there isn't. I tried lapply, replace and other things in combination but still