similar to: how to get inflection point in binomial glm

Displaying 20 results from an estimated 1000 matches similar to: "how to get inflection point in binomial glm"

2010 Apr 26
3
Identifying breakpoints/inflection points?
Hello! I have a dataset with the following two vectors: year<-c(1967,1968,1969,1970,1971,1972,1973,1974,1975,1976,1977,1978,1979,1980,1981,1982,1983,1984,1985,1986,1987,1988,1989,1990,1991,1992,1993,1994,1995,1996,1997,1998,1999,2000,2001,2002,2003,2004,2005,2006,2007,2008,2009)
2004 Jul 01
2
Inflection Points
Hi! Some weeks ago I discovered R. Now, I have a somewhat complicated task and am not sure whether R is the right tool to solve it. I got data of several series or measurements where I have to find the two inflection points. I did a linear regression (with ^2 and ^3 arguments), the problem there was that I had to look only at a very narrow band of measurement in order to get the
2009 Mar 28
1
Find inflection points using smooth.spline
Is there any way to identify or infer the inflection points in a smooth spline object? I am doing a comparison of various methods of time-series analysis (polynomial regression, spline smoothing, recursive partitioning) and I am specifically interested in obtaining the julian dates associated with the inflection points inferred by the various models. Tyler e.g.
2003 Apr 30
1
How to calculate the x to assymptotic value and curve inflection .
Hi, I have this non-linear function: y=115.251 - 118.69 * exp(-0.123517*x) I try to discovery the x value for the assyntoptic value of y and the x value where the behavior of curve change, the inflection point. How to make this? Is poss?ble to make this on R? Thanks Ronaldo -- O Flamengo e o Bangu terminaram o jogo em 0 x 0. Quem fez o gol? A Volkswagen -- | // | \\
2006 Apr 10
5
Inflections.rb in spanish
Hi: I have a problem with the plural of fracancia, I got fragancium but in spanish is fragancia. I modified inflections in environment.rb Inflector.inflections do |i| i.irregular ''fragancia'', ''fragancias'' end but is ignored. The solution that I found was comment this inflection on inflections.rb #inflect.singular(/([ti])a$/i,
2012 Jul 19
20
Rails' inflections are messy
Yesterday, I opened a GitHub Issue<https://github.com/rails/rails/pull/7071> about moving Rails inflections to an initializer. The idea wasn''t received well, understandably, as generating a large initializer with new Rails apps is pretty unappealing. However, the core members seemed open to the discussion of alternatives continuing here. For those of you not in the know,
2011 Mar 01
11
Did rails or shoulda go insane on the inflection of 'taxes'?
I have a model ''xp_jurisdiction_taxes'' which rails (3) created correctly. Another model ''xp_jurisdiction_states'' has many :xp_jurisdiction_taxes. In my spec I am using a shoulda helper to test the association but get the following error. BTW, greped the whole project just in case and the string ''taxi'' exists nowhere. 1)
2006 Aug 21
1
Fwd: Re: Finney's fiducial confidence intervals of LD50
thanks a lot Renaud. but i was interested in Finney's fiducial confidence intervals of LD50 so to obtain comparable results with SPSS. But your reply leads me to the next question: does anybody know what is the best method (asymptotic, bootstrap etc.) for calculating confidence intervals of LD50? i could "get rid" of Finney's fiducial confidence intervals but
2005 Dec 01
2
Minimizing a Function with three Parameters
Hi, I'm trying to get maximum likelihood estimates of \alpha, \beta_0 and \beta_1, this can be achieved by solving the following three equations: n / \alpha + \sum\limits_{i=1}^{n} ln(\psihat(i)) - \sum\limits_{i=1}^{n} ( ln(x_i + \psihat(i)) ) = 0 \alpha \sum\limits_{i=1}^{n} 1/(psihat(i)) - (\alpha+1) \sum\limits_{i=1}^{n} ( 1 / (x_i + \psihat(i)) ) = 0 \alpha \sum\limits_{i=1}^{n} (
2006 Aug 21
2
Finney's fiducial confidence intervals of LD50
I am working with Probit regression (I cannot switch to logit) can anybody help me in finding out how to obtain with R Finney's fiducial confidence intervals for the levels of the predictor (Dose) needed to produce a proportion of 50% of responses(LD50, ED50 etc.)? If the Pearson chi-square goodness-of-fit test is significant (by default), a heterogeneity factor should be used to calculate
2010 Nov 22
0
Rails 3 - Custom Inflection Not Working?
I''m using Rails (3.0.3) and have the following code in initializers/inflections.rb ActiveSupport::Inflector.inflections do |inflect| inflect.irregular(''nursery'', ''nurseries'') end From the console I''m getting: "nursery".pluralize => "nurseries" "nurseries".singularize => "nurseries" I should be
2007 Dec 26
1
#10615 : inflection bug that affects classify method
Have a look: http://dev.rubyonrails.org/ticket/10615 This is actually a singularize method bug: >> "Business".singularize => "Busines" seems that classify uses singularize internally. Rick resolved it as invalid but I cannot understand why. Rick, could you shed some light on your decision? MK --~--~---------~--~----~------------~-------~--~----~ You received
2015 Jun 10
2
Duda glmer
Hola, Tengo una base de datos con estructura jerárquica en la que quiero clasificar observaciones en distintas categorías. En el caso más simple, tengo una variable con dos categorías (variable Y1) y dentro de cada una de ellas hay otras dos categorías (variable Y2). Además tengo una variable explicativa cuantitativa discreta X. El banco de datos sería de este tipo: X Y1 Y2 5 0 1 9 0 0 2
2002 Dec 04
1
use of offset - clarification
Hi Listers, seems I have forgotten some basics re offset in glm: data: counts (y) from locations off different size (area), explanatory variable: x Model: y ~ x+offset(area) Predictions (pred) using Poisson errors plot(x,y) and points(x,pred) gives neat "line" of estimated values. However, for ease of understanding graphs are better using plot(x,y/area). Question: How to display
2004 Oct 08
1
nlme vs gls
Dear List: My question is more statistical than R oriented (although it originates from my work with nlme). I know statistical questions are occasionally posted, so I hope my question is relevant to the list as I cannot turn up a solution anywhere else. I will frame it in the context of an R related issue. To illustrate the problem, consider student achievement test score data with multiple
2005 Nov 24
1
residuals in logistic regression model
In the logistic regression model, there is no residual log (pi/(1-pi)) = beta_0 + beta_1*X_1 + ..... But glm model will return residuals What is that? How to understand this? Can we put some residual in the logistic regression model by replacing pi with pi' (the estimated pi)? log (pi'/(1-pi')) = beta_0 + beta_1*X_1 + .....+ ei Thanks! [[alternative HTML version deleted]]
2013 Jul 22
2
Set ringtone by dialed number
Would it be possible to set the ringtone based on the number that was dialed? Example of what the goal is: Dial Denver number Incoming calls ring with ringtone 1 Dial main number Incoming calls ring with ringtone 2 We are currently using Digium D40, D50, D70 phones. -------------- next part -------------- An HTML attachment was scrubbed... URL:
2018 Sep 14
1
Possible bug with chromatic adaptation in grDevices::convertColor
It appears that the chromatic adaptation feature of `grDevices::convertColor`is broken, and likely has been for many years.? While a little surprising, it is an obscure enough feature that there is some possibility this is actually broken, as opposed to user error on my part.? If it turns out to the latter, I apologize in advance for spamming this list. Consider: ??? rgb.in <-
2011 Apr 05
4
Rails 3.0.5 gives SQLite3::SQLException for the same code that works on 3.0.3
Hello, I recently updated Rails to 3.0.5. The very same code that worked on 3.0.3 now gives error. The code is: def kategorialista Kategoria.where(:elfogadva => TRUE).order("nev").collect {|s| [s.nev, s.sefuri]} end It is in application_controller.rb with helper_method :kategorialista The error it gives on 3.0.5: SQLite3::SQLException: no such table: kategoria: SELECT
2010 Jan 25
3
binary
Hi all Assume I have a data set xx; Group: 1=group1 ?, 2=group2 IQ: ?1= High, 0 =low fit <- glm(IQ ~group, data = xx, family = binomial()) summary(fit) Results ?????? ????????????Estimate Std. Error z value Pr(>|z|) (Intercept) -2.55456??? 0.210 -12.273? < 5e-16 *** group????????? 0.36180 ?????0.076?? 3.952 ????5.24e-05 *** the odd ratio = exp(0.36180 )= 1.435912 My question