similar to: how to call a function for each row

Hi I want to generate 4 random number which sum up to 100 always Please help ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/runif-with-condition-tp4278704p4278704.html Sent from the R help mailing list archive at Nabble.com.

Hi I have column name as given below If the variable is in log(X1 + 1) pattern it should be removed and i need only X1 Input log(x1 + 1) x2 log(X3 +1) Expected Output X1 X2 X3 Please help me -- View this message in context: http://r.789695.n4.nabble.com/help-in-removal-of-fixed-pattern-tp4152524p4152524.html Sent from the R help mailing list archive at Nabble.com.

Hi how do we get intercepts standard error. I'm using the package pls. i got the coefficient but not able to get the stabdard error -- View this message in context: http://r.789695.n4.nabble.com/How-to-get-intecerpt-standard-error-in-PLS-tp3932104p3932104.html Sent from the R help mailing list archive at Nabble.com.

Hi I have set of records seperated by a separator say "$$$" i want to get the values in a dataframe. eq qwer$$12$$qwre ewrtr$7789$ewwe I want the output as\ V1 V2 V3 qwer 12 qwre ewrtr 7789 ewwwe Please help me ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Help-in-splitting-the-records-tp4650827.html Sent from

Hi I'm getting the intercepts of the Random effects as 0. Please help me to understand why this is coming Zero This is my R code Data<- read.csv("C:/FE and RE.csv") Formula="Y~X2+X3+X4 + (1|State) + (0+X5|State)" fit=lmer(formula=Formula,data=Data) ranef(fit). My sample Data State Year Y X2 X3 X4 X5 X6 S2 1960 27.8 397.5 42.2 50.7 78.3 65.8 S1 1960 29.9 413.3 38.1

Hi, I want to remove the entire row from the dataset if any of the row contains blank or NA my dataset look like State Year Y X2 X3 X4 X5 X6 State1 1960 27.8 397.5 42.2 50.7 78.3 65.8 State2 1960 29.9 413.3 38.1 52 79.2 66.9 State1 1961 29.8 439.2 40.3 54 79.2 67.8 State2 1961 30.8 459.7 39.5 79.2 69.6 State1 1962 31.2 492.9 37.3 54.7 77.4 68.7 State2 1962 528.6 38.1 80.2 73.6 State1 1963

How to use the segments in the PLS fit1 <- mvr(formula=Y~X1+X2+X3+X4+x5+....+x27, data=Dataset, comp=5,segment =7 ) here when i use segments,the error was like this rror in mvrCv(X, Y, ncomp, method = method, scale = sdscale, ...) : argument 7 matches multiple formal arguments Please help -- View this message in context:

Hi How to get p-value and the standard error in PLS I have used the following function to calculate PLS fit1 <- mvr(formula=Y~X1+X2+X3+X4, data=Dataset, comp=4) Please help me -- View this message in context: http://r.789695.n4.nabble.com/getting-p-value-and-standard-error-in-PLS-tp3914760p3914760.html Sent from the R help mailing list archive at Nabble.com.

Hi i have few clarification regarding the output from the fitted(object). I'm creating a object using the following formula dataset <- read.csv("~/data.csv") obj = lm (formula="log(y+1)~log(x1+1)+(log(x2+1)+log(x3+1)", data=dataset) fitted(obj) here the output of the fitted(obj) considers the log(x1+1) or just log(x1). -- View this message in context:

Hi My data looks like this startDate="2008-06-01" dateRange =c( "2008-10-01","2008-12-01") Is there any method to find the week number from the startDate range ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Week-number-from-a-date-tp4410223p4410223.html Sent from the R help mailing list archive at Nabble.com.

Hi all, I have the following code: set.seed(1) x1 <- matrix(sample(1:12), ncol=3) x2 <- matrix(sample(1:12), ncol=3) x3 <- matrix(sample(1:12), ncol=3) X <- list(x1,x2,x3) tt <- matrix(round(runif(5*4),2), ncol=4) Is there a way I can construct a new list where newlist[[i]] = tt[i,] %*% X[[i]] without using a for loop? Each element of newlist will be 3 x 1 vector. Thanks -- Tina

Hi I have a variable str = " X", "Y" and values ("0","12") i want to set value for X =0 and Y =12 and use inside the program. how to do this Please anybody help me. -- View this message in context: http://r.789695.n4.nabble.com/Setting-the-Values-tp3823388p3823388.html Sent from the R help mailing list archive at Nabble.com.

Hi I have a data class wise. I want to create a histogram class wise without using for loop as it takes a long time my data looks like this x class 27 1 93 3 65 5 1 2 69 5 2 1 92 4 49 5 55 4 46 1 51 3 100 4 ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Histogram-classwise-tp4528624p4528624.html Sent from the R help mailing list archive

Hi I 've a data a=c(10,20,30) b=c(100,200,300) c=c(50,60,70) I want to compare a[1]<=c[1]<b[1],...... How to compare for all the records ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/comparing-three-vectors-tp4636728.html Sent from the R help mailing list archive at Nabble.com.

I have a long string. i want to sepearate a 10 digit phone no from it. eg "my no is 9876543210 is personal no and my official no is 123-456-8907. you can use any of these" i want to seperate the 9876543210 and 123-456-8907 from this. therev may be many phone nos in the string. how to do it ----- Thanks in Advance Arun -- View this message in context:

Hi I have four sets of datas x1, x2, x3,y I want to sactter plot between (x1,y) and line chart between (x2 ,y) and (x3,y) all these should come in a single graph Can anyone help ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/plotting-multiple-plot-in-same-graph-tp4545624p4545624.html Sent from the R help mailing list archive at

Hi I have records like like this X1 X2 State 34 72 state1 9 63 state1 49 31 state1 60 34 state1 80 73 state1 60 20 state2 59 87 state2 88 20 state2 71 66 state2 65 56 state2 59 16 state1 60 100 state2 I want to get the summarize value like mean median histogram for X1 and X2 based on state. I'm using FOR loop for this. Is there any method to remove for loop and use apply or any

Hi I'm not getting any results in R console when i run commands. I reinstalled R but the results are same ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Results-not-dispalying-in-R-console-tp4647271.html Sent from the R help mailing list archive at Nabble.com.

Hi, You could try: A<- matrix(unlist(read.table(text=" 1 2 3 4 5 6 7 8 9 9 8 7 6 5 4 3 2 1 ",sep="",header=FALSE)),ncol=3,byrow=FALSE,dimnames=NULL) library(matrixStats) ?res1<-t(sapply(split(as.data.frame(A),as.numeric(gl(nrow(A),2,6))),colProds)) ?res1 #? [,1] [,2] [,3] #1??? 4?? 10?? 18 #2?? 63?? 64?? 63 #3?? 18?? 10??? 4

Using the Cement hardening data in Anderson (2008) Model Based Inference in the Life Sciences. A Primer on Evidence, and working with the best model which is lm ( y ~ x1 + x2, data = cement ) the AIC value from R is model <- lm ( formula = y ~ x1 + x2 , data = cement ) AIC ( model ) 64.312 which can be converted to AICc by adding the bias