similar to: Nomogram with stratified cph in Design package-- failure probability

Displaying 20 results from an estimated 400 matches similar to: "Nomogram with stratified cph in Design package-- failure probability"

2011 Nov 30
1
Nomogram with stratified cph in rms package, how to get failure probability
Hello, I am using Dr. Harrell's rms package to make a nomogram. I was able to make a beautiful one. However, I want to change 5-year survival probability to 5-year failure probability. I couldn?t get hazard rate from Hazard(f1) because I used cph for the model. Here is my code: library(rms) f1 <- cph(Surv(retime,dfs) ~ age+her2+t_stage+n_stage+er+grade+cytcyt+Cyt_PCDK2 , data=data11,
2011 Nov 30
0
formula for calculating the survival probability for nomogram
Hi, I used Dr. Harrell's rms package to make a nomogram. Below is my code for nomogram and calculate total points and probability *in original data set* used for building the nomogram. *My question is how I get the formula for calculating the survival probability for this nomogram. Then I can use this formula to do validation by using other data set. * f1 <- cph(Surv(retime,dfs) ~
2017 Oct 26
1
nomogram function error
Hi R-help, ? I have fit a cox ph model to my data, but have beenreceiving an error when trying to fit a model to the nomogram. Here is the codeand corresponding error: ? ? >nomogramCF = nomogram(cph_age6_40avp4, +????????????????????lp.at= seq(-10,10,by =0.5),lp = TRUE, +?????????????????????? +??????????????????????funlabel="5year survival",
2009 Apr 25
3
Nomogram with stratified cph in Design package
Hello, I am using Dr. Harrell's design package to make a nomogram. I was able to make a beautiful one without stratifying, however, I will need to stratify to meet PH assumptions. This is where I go wrong, but I'm not sure where. Non-Stratified Nomogram:
2005 Jul 11
1
validation, calibration and Design
Hi R experts, I am trying to do a prognostic model validation study, using cancer survival data. There are 2 data sets - 1500 cases used to develop a nomogram, and another of 800 cases used as an independent validation cohort. I have validated the nomogram in the original data (easy with the Design tools), and then want to show that it also has good results with the independent data using 60
2010 Oct 04
1
I have aproblem about nomogram--thank you for your help
dear professor: I have a problem about the nomogram.I have got the result through analysing the dataset "exp2.sav" through multinominal logistic regression by SPSS 17.0. and I want to deveop the nomogram through R-Projject,just like this : > n<-100 > set.seed(10) > T.Grade<-factor(0:3,labels=c("G0", "G1", "G2","G3")) >
2011 Oct 21
1
cph/nomogram Design/RMS package hazard ratio: interquartile vs per unit
Hello, I am constructing a nomogram using cph and nomogram commands in Dr. Harrell's Design/RMS package. The HR that I obtain for dichotomous and categorical variables are identical to those that I obtain using STATA stcox. However, the inter-quartile HR I obtain for continuous variables is obviously different, since STATA gives me HR for each unit (year, centimeter, etc) like coxph would
2010 Jul 31
3
I have a problem
dear£º in the example£¨nomogram£©£¬I don't understand the meanings of the program which have been marked by red line.And how to compile the program(L <- .4*(sex=='male') + .045*(age-50) + (log(cholesterol - 10)-5.2)*(-2*(sex=='female') + 2*(sex=='male'))). n <- 1000 # define sample size set.seed(17) # so can reproduce the results age <- rnorm(n, 50, 10)
2010 Oct 04
2
i have aproblem --thank you
dear professor: thank you for your help,witn your help i develop the nomogram successfully. after that i want to do the internal validation to the model.i ues the bootpred to do it,and then i encounter problem again,just like that.(´íÎóÓÚerror to :complete.cases(x, y, wt) : ²»ÊÇËùÓеIJÎÊý¶¼Ò»Ñù³¤(the length of the augment was different)) i hope you tell me where is the mistake,and maybe i have
2010 Aug 25
1
modify a nomogram
Hi, I would like to emphasize ("zoom") the zone of a nomogram where the probability are > 0.01 (nomogram built with nomogram, Design). As a consequence, I don't need to draw the part of the "Total points" axis with score < 60 equivalent in my case to a linear predictor < 4.5 - As far as I know, this is not possible with the arguments of the function. - Changing
2013 Feb 14
1
Nomogram after Cox Random Effect (frailty) model
Dear R-users, I am a novice R-user with some experience in using the RMS package for taking nomograms after various survival models. This time, I am trying to plot a nomogram after a Random Effects Cox, implemented by the "coxme" package. My questions are: 1. Is it possible to take a nomogram directly after the coxme survival function? 2. If not is there a way to take the linear
2010 May 19
1
Nomogram with multiple interactions (package rms)
Dear list, I'm facing the following problem : A cox model with my sex variable interacting with several continuous variables : cph(S~sex*(x1+x2+x3)) And I'd like to make a nomogram. I know it's a bit tricky and one mights argue that nomogram is not a good a choice... I could use the parameter interact=list(sex=("male","female"),x1=c(a,b,c))... but with rcs or pol
2011 Jun 24
1
Competing-risks nomogram
Hi R users, I'd like to draw a nomogram using a competing-risks regression (crr function in R), rather than a cox regression. However, the nomogram function provided in the Design package is not good for this purpose. Do you have any suggestion. I really appreciate your help Many thanks F.Abdollah, MD San-Raffele hospital Milan, Italy -- View this message in context:
2013 Jun 24
2
Nomogram (rms) for model with shrunk coefficients
Dear R-users, I have used the nomogram function from the rms package for a logistic regresison model made with lrm(). Everything works perfectly (r version 2.15.1 on a mac). My question is this: if my final model is not the one created by lrm, but I internally validated the model and 'shrunk' the regression coefficients and computed a new intercept, how can I build a nomogram using that
2010 Oct 03
2
A problem about nomogram--thank you for you help
dear professor: I am a doctor of urinary,and I am developing a nomogram of bladder tumor.Now I have a problem about this. I have got the result like this through analysing the dataset "exp11.sav" through multinominal logistic regression by SPSS 17.0.(the Sig. is high,that is good ,it is just aexperimental data ) Parameter Estimates Ya B Std. Error Wald df Sig. Exp(B) 95%
2013 Mar 21
1
Re-order variables listed in nomogram?
Hi, I am using the function "nomogram" in the rms package for survival analysis. How is the order in which variables determined and how can I change it? I use it with a cph() model. Many Thanks Eleni Rapsomaniki Clinical Epidemiology Group Department of Epidemiology and Public Health University College London
2003 Nov 04
2
help with nomogram function
I have fitted a logistic regression model > failed.lr2$call lrm(formula = failed ~ Age + task2 + Age:task2, data = time.long, na.action = na.omit) using the Design package functions and would like to generate a nomogram from this model. the datadist information is generated and stored in > ddist time.long$Age time.long$task2 Low:effect 45
2007 Oct 03
1
Nomogram
Hi R users. I have a model of cox that already it is estimated (I have only the model estimated, I haven't data), how can I determine a nomogram with R? Is it posible to do nomograms in Design package? I think that's only when the model (Cox Regression in this case) is before estimated in R. Thanks
2006 Nov 06
1
Competing risk nomogram
Dear R Users, Do you have a sample code for developing a nomogram with competing-risks? Any help is appreciated. Kind regards, ND Nguyen
2011 May 05
7
Draw a nomogram after glm
Hi all R users I did a logistic regression with my binary variable Y (0/1) and 2 explanatory variables. Now I try to draw my nomogram with predictive value. I visited the help of R but I have problem to understand well the example. When I use glm fonction, I have a problem, thus I use lrm. My code is: modele<-lrm(Y~L+P,data=donnee) fun<- function(x) plogis(x-modele$coef[1]+modele$coef[2])