similar to: [Off-Topic] GL Globe

Hi, This is Yan, a graduate student from Temple University. My current work involves drawing 3D plot in R or S-Plus. I have a dataset containing distances between 18 cities in 4 continents. Using classical multi-deminsional scaling in 2 dimensions, I could seperate them successfully and plot with different colors in a 2D figure, which is attacked. Then I do the same in 3 dimensions and use

hi we're a relatively new norwegian company terminating in norway. does anyone know companies that terminate traffic around the globe? we've got decent prices for .eu and .us, but we need cheaper solutions for asia, middle east and africa. regards roy

How do we specify a contrast interaction matrix for an ANOVA model? We have a two-factor, repeated measures design, with Cue Direction (2) x Brain Hemisphere(2) Each of these has 2 levels, 'left' and 'right', so it's a simple 2x2 design matrix. We have 8 subjects in each cell (a balanced design) and we want to specify the interaction contrast so that: CueLeft>CueRght

Hi all, I have a strange problem and rigth now I can't figure out a solution. Trying to calculate an ANOVA with one between subject factor (group) and one within (hemisphere). My dependent variable is source localization (data). My N = 25. My data.frame looks like this: > ML.dist.stack subj group hemisphere data 1 1 tin left 0.7460840 2 2 tin left

Why do I see this error? > library(stats) > require(stats) [1] TRUE > > tHSD <- TukeyHSD(aov) Error in TukeyHSD(aov) : no applicable method for "TukeyHSD" In case it helps: > aov Call: aov(formula = roi ~ (Cue * Hemisphere) + Error(Subject/(Cue * Hemisphere)), data = roiDataframe) Grand Mean: 8.195069 Stratum 1: Subject Terms: Residuals Sum

Dear Experts, I am new to R and unfortunately cannot start with a simply statistical analysis: I manually determined the volume of the right and left hippocampus in a group of meditators and in a group of controls. My data-sheet looks as follows: observation subject group age gender hemisphere volume 1 am04 m 25 f left 3.637 2 am04 m 25 f right 3.713 3 ao08 m 47 m left 3.715 4 ao08 m 47

Hi, we need some help to define planned comparisons. I've based my understanding of the problem on reading Tabachnick and Fidell (2006), ie: http://www.ablongman.com/catalog/academic/product/0,1144,0205459382,00.html I don't understand how to specify planned comparisons in R. I've not found explanations for this in MASS or elsewhere. There is only discussion of the contrast

Dear List, I have a richness data distributing across 20 N to 20 S latitude. (120 E-140 E longitude). I would like to draw the richness in the north hemisphere and a regression line in the plot (x-axis: latitude, y-axis: richness in the north hemisphere). The above demand is done using plot. Then, south hemisphere richness and regression are required to be generated using the same y-axis above

I'm an experimental psychologist and when I run ANOVA analysis in SPSS, I normally ask for a test of non-sphericity (Box's M-test). I also ask for output of the corrections for non-sphericity, such as Greenhouse-Geisser and Huhn-Feldt. These tests and correction factors are commonly used in the journals for experimental and other psychology reports. I have been switching from SPSS to R

Hi I hope this is going to the right place. I am trying to write a program which uses KernSmooth library to estimate mutual information between two time series at various different lags. At the moment it’s producing negative values, which is supposed to be impossible (something is fishy). I am summing across one row of the matrix to get p(value is in bin x) and summing across the columns to get

I'm trying to read in a CSV, with lines looking like: HEADER, Latitude DecDeg, Latitude Hemisphere, Longitude DecDeg, Longitude Hemisphere, Speed knots, Bearing Degrees, fixQualityGga, noOfSatGga, altGga, heightGga, selectionGsa, fixGsa, pdopGsa, hdopGsa, vdopGsa, noOfSatGsv, Time, *checkSum $GPS, 3747.0224, N, 12223.4522, W, 0.36, 348.21, 1, 3, 4.01, 175.5, -25.2, A, 2, 4.14,

With respect to calculating the epsilon index of sphericity for ANOVA, discussed on pp. 45-47 of: http://www.psych.upenn.edu/~baron/rpsych.pdf It notes that epsilon is not required for a repeated measures design with only k=2 levels, as the minimum value of epsilon (e) is given by: e = 1/(k-1) so for k=2, we have e = 1 (ie, no correction of the F test df; see p. 46). These notes apply to a

I am having trouble in Sweave with input line lengths. For example, I may have in my input file the chunk <<>>= BrainSections <- levels(AggData$sctn)[grep( "(^BRAIN)|(^WHOLEBRAIN)|(LEFT HEMISPHERE)| (HALFBRAIN)", levels(AggData$sctn))] @ This is translated in the tex file: \begin{Sinput} > BrainSections <-

> > On 18 May 2017, at 14:58 , Martyn Plummer <plummerM at iarc.fr> wrote: > > > >> On 18 May 2017, at 14:51, peter dalgaard <pdalgd at gmail.com> wrote: > >>> On 18 May 2017, at 13:47 , Joris Meys <jorismeys at gmail.com> wrote: > >>> > >>> Correction: Also dlt uses the default timezone, but POSIXlt is not recalculated

Hello, I'm trying to run shared folders with Dovecot 1.2.12. I'm managing ACLs from SOGo and it seemd that it successfully create dovecot-acl and dovecot-acl-list in user maildir. But I cannot see any of these shared folders. In Thunderbird I could see shared folder in Subscriptions but without option to subscribe. I was reading almost everything that was possible to google but without

I'm trying out a basic plot, but something about the way I subset my data leads to problems with the plot. Here is the first bit of my data set year,date,location,quadrat_juvenile,photo_location,photo_exists,genus,count,divers 2005,2005-04-30, 1 Fringing Reef,1, 1 Fringing Reef Coral Transect Pole 1-2 Quadrat 1,t,Acanthastrea,0,HP+MEM 2005,2005-04-30, 1 Fringing Reef,1, 1 Fringing Reef

As you can see: time is from 1 to 1460, 1 means they the measure Tem for the globe at the first 6 hours , 2=after 12 hours .....; and so on 1460 *6 = 8760 hours which equals 1 year first of all I want to convert all data from kelvin to degree second I want to convert from 6 hourly to daily and make it like this raw data what i want to make time

Hi everyone, I wonder if anyone knows the reason why the outputs of the same reprojection in r and arcgis are different?. The magnitude of the change can be up to 40 km in the poles. Basically, I have a database of points equally separated by one degree over the globe. In ARCGIS, I am projecting the data in GCS-WGS-1984 and then reprojected it to Berhmann to ensure equal area

> On 18 May 2017, at 14:58 , Martyn Plummer <plummerM at iarc.fr> wrote: > > > >> On 18 May 2017, at 14:51, peter dalgaard <pdalgd at gmail.com> wrote: >> >> >>> On 18 May 2017, at 13:47 , Joris Meys <jorismeys at gmail.com> wrote: >>> >>> Correction: Also dlt uses the default timezone, but POSIXlt is not recalculated

Sorry, forgot to switch the header to the R group.... --- Globe Trotter <itsme_410 at yahoo.com> wrote: > Date: Thu, 2 Mar 2006 19:35:21 -0800 (PST) > From: Globe Trotter <itsme_410 at yahoo.com> > Subject: Re: [R] calling R's library using C > To: Dirk Eddelbuettel <edd at debian.org> > > Hi, Dirk: > > Thanks for all the help. I thought I would