similar to: Centos Project : STEM

Hi, R people. Consider the following small R session: ======================================================================> > a <- c(8.48, 9.58, 9.96) > stem(a) The decimal point is at the | 8 | 8 | 5 9 | 9 | 6 10 | 0 > stem(round(a,1)) The decimal point is at the | 8 | 5 9 | 9 | 6 10 | 0

I would like to do some fairly basic stem-and-leaf displays in R. I am aware (I might even say painfully aware) of stem(base) and have tried it. That's why I'm hoping someone has a usable stem- and-leaf display for R so that I don't have to write my own. r-project.org > Search > R Site Search > "stem and leaf display" finds nothing. I also tried the mail archive

I must apologize in advance for asking a simple question. I am sure that a clue will be sufficient to get this show on the road. I am trying to graph tide prediction data in various ways. I haven't been able to answer this question after pouring over TFM. I read the datafile theight <- read.table("tides",header=TRUE) I do get a summary() or fivenum()

Hi, I would like to make a stem and leaf plot and I want to edit the category-names. So, by doing this: > x <- c(1,2,2,3,3,3,3,2,2,1) > stem(x) I get: 1 | 00 1 | 2 | 0000 2 | 3 | 0000 First Question: Why do I get gaps between the categories? (like in line 2 and line 4) And second: How can I edit the categories so that I can create something like that:

Hi I do not know why does it happen but you can control the behaviour by setting scale to 0.5. Cheers Petr > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Leif Ruckman > Sent: Friday, February 16, 2018 9:18 AM > To: r-help at r-project.org > Subject: [R] stem - strange leaves > > > x > [1] 8.0 7.9 7.5 7.0 8.0 7.3 8.0

Hi R is open source so you could dig into the code. However the actual stem function is probably written in C, so it is beyond my expertise. If you replied to the list there could be experts who are able to provide explanation. > stem function (x, scale = 1, width = 80, atom = 1e-08) { if (!is.numeric(x)) stop("'x' must be numeric") x <- x[is.finite(x)]

Is the following a bug with stem() or is there something else that I am missing? I ran stem() on the vector x below and got stem(x-10) instead of stem(x). If I subtract 1 from x, I get a correct answer. If I add 1 to x, I still get a wrong answer. If I add 10 to x, I get a correct answer. I'm not sure what to make of this, other than to think it is a bug. Can anyone tell me if this is a bug?

Full_Name: Myung Geun Kim Version: 2.4.0 OS: Window XP Submission from: (NULL) (210.110.8.105) For the data c1 of size 14, stem provides the following result. ************************************************************** >c1 [1] 14 39 70 11 38 20 37 15 41 74 74 34 48 51 ZZangi>stem(c1) The decimal point is 1 digit(s) to the right of the | 0 | 145 2 | 04789 4 | 181 6 | 044

Referring to "Using R for Data Analysis and Graphics" by J H Maindonald, and available from the R site, I found the example on p.30 non-working: > stem(qqnorm(possum$hdlngth)) Error in stem(qqnorm(possum$hdlngth)) : 'x' must be numeric Since qqnorm(possum$hdlngth) plots, and > class(possum$hdlngth) [1] "numeric" , the problem must be here: >

Full_Name: Liming Liang Version: 1.8.1 OS: windows2000 professional Submission from: (NULL) (67.172.81.139) I was looking at the variable 'mpg' of the data file 'mtcars' and make a stem plot, the following is the commend I entered. The stem plot shows the largest observation is 32.9 but actually in the data the largest observation is 33.9, here might be a problem. >

Hi All I came across a problem below when doing stemming and stem completion with package tm in R. Word "mining" was stemmed to "mine" with stemDocument(), and then completed to "miners"with stemCompletion(). However, I prefer to keep "mining" intact. For stemCompletion(), the default type of completion is "prevalent", which takes the most

> x [1] 8.0 7.9 7.5 7.0 8.0 7.3 8.0 7.2 7.4 7.3 7.8 8.0 7.7 8.3 7.8 7.8 7.1 7.7 6.9 7.5 7.5 7.3 7.2 7.5 7.2 > stem(x) The decimal point is at the | 6 | 9 7 | 012223334 7 | 5555778889 8 | 00003 > y <- c(x, 8) > stem(y) The decimal point is 1 digit(s) to the left of the | 68 | 0 70 | 00 72 | 000000 74 | 00000 76 | 00 78 | 0000 80 | 00000 82 | 0 The

Hi there, I am trying to find a way to accomplish parallel stem-and-leaf displays in R, yet there seems to be no specific command nor info in the archive that I can depend on. Specifically, there are two batches of data that I want to put together in parallel stem-and-leaf displays. Would anyone help me figure out how to do this in R? Thank you sooooooooooooo much! Jin [[alternative HTML

hi, i am newbie to xapian and am trying to get started with it in python. there is no stemmer.stem_word method in the latest python library. how do i stem words before doing doc.add_posting? is there any sample hello world code in python that i can use? thanks a lot! >>> stemmer = xapian.Stem('english') >>> stemmer. stemmer.__call__

Full_Name: Yutaka Hamaoka Version: 1.8.1(Raqua) OS: OSX 10.3 Submission from: (NULL) (218.140.186.74) Hi, I've found "stem()" falls into infinit loop when x has no variance. Let's try x<-matrix(1,nrow=100,ncol=1) stem(x) Then you will get infinit flow. The decimal point is 9 digit(s) to the left of the | -214748360 | -214748358 | -214748356 | -214748354 |

A discussion on r-help led me to look at stem.c at https://github.com/wch/r-source/blob/trunk/src/library/graphics/src/stem.c Lines 76-77 appear superfluous. They sit inside a condition, and set mu, as follows: if (k*(k-4)*(k-8) == 0) mu = 5; if ((k-1)*(k-5)*(k-6) == 0) mu = 20; But mu is set unconditionally to 10 on line 84, and that is followed by conditional assignments (on line 85-6)

hello, you can use the persp() function. The shade=0.7 option is very nice. With matlab, it is possible to change of colors automaticalli with the value to be plotted. Does someone know to do that ? Gr?gory f0z6305 at labs.tamu.edu@stat.math.ethz.ch on 06/02/2003 07:05:04 Envoy? par : r-help-admin at stat.math.ethz.ch Pour : r-help at stat.math.ethz.ch cc : Objet : [R] About

Hi all, I am trying to implement a search that will use the Stem Analyzer. I added the Stem Anaylzer from the examples shown in another post http://ruby-forum.com/topic/80178#147014 module Ferret::Analysis class StemmingAnalyzer def token_stream(field, text) StemFilter.new(StandardTokenizer.new(text)) end end end The problem with the Stem analyzer is that when I search for a

Hi, I need to modify the stemming for a couple of words (a blacklist) and for all the other to use the usual snowball stemmer. The "natural" way of doing it would be to derive from Stem and override operator ()... but I am using *python-bindings*. Would this be possible? If not I have two other solutions in mind: - add a custom stemmer to Xapian - write custom index & search

I''m not on AAF. Can someone else help Raymond with an example? On 12/6/06, Raymond O''connor <nappin713 at yahoo.com> wrote: > > Matt Schnitz wrote: > > You also need to stem-analyze the incoming query. > > > > I had this same problem. :^> > > > > > > Schnitz > > Do you have an example of how to do this? I''m using