similar to: Kickstart - URL command

Should I be concerned? [root@fs1 ~]# cobbler import --name=F18 --path=rsync://mirrors.kernel.org/fedora/releases/18/Fedora/x86_64/os --arch=x86_64 task started: 2013-01-18_062009_import task started (id=Media import, time=Fri Jan 18 06:20:09 2013) Found a redhat compatible signature: Packages adding distros creating new distro: F18-x86_64 creating new profile: F18-x86_64 associating repos

I''m using puppet-0.24.8-4.el5 on CentOS 5.4. My problem is yumrepo isn''t writing the "name=" field to the repository files which causes yum to complain with the error: Repository ''local-CentOS-5.4-x86_64'' is missing name in configuration, using id I get this behavior on all of my yumrepo definitions. One of them looks like this: yumrepo {

Your config looks ok, as far i can tell. This : "cifs/kvm7246-vm022.maas.local at TC84.LOCAL" As it should spn/hostname.fqdn at REALM nothing wrong with that. But if i understand it right. Your server : kvm7246-vm022.maas.local is in REALM : TC83.LOCAL ( NTDOM:TC83 ) But you get TC84 back?. On the problem server run the following: dig a kvm7246-vm022.maas.local @IP_of_AD-DC

I've tried installing wine using synaptic on ubuntu, also compiling form source and a couple of other ways but never get a ./wine/config file ? Any idea what I'm doing wrong? Thanks Jim -- Dr. Jim Maas james.maas@nottingham.ac.uk This message has been checked for viruses but the contents of an attachment may still contain software viruses, which could damage your computer system:

Here's the keytab info: ubuntu at kvm7246-vm022:~/samba$ sudo klist -ek /etc/krb5.keytab Keytab name: FILE:/etc/krb5.keytab KVNO Principal ---- -------------------------------------------------------------------------- 12 host/kvm7246-vm022.tc83.local at TC83.LOCAL (etype 1) 12 host/KVM7246-VM022 at TC83.LOCAL (etype 1) 12 host/kvm7246-vm022.tc83.local at TC83.LOCAL (etype 3) 12

Hi all. I?m trying to understand a weird authentication failure: I have two domains (TC83.LOCAL and TC84.LOCAL), each in a diferent forest, with a bidirectional forest trust. The samba server kvm7246-vm022.maas.local is a domain member of TC83 and is running a recent build from git master (f38077ea5ee). When I test authentication of users in each domain by running ntlm_auth on the samba server,

I'm having what appears at first glance to be a kickstart+anaconda issue on CentOS 7.4. As near as I can tell in the program.log in the anaconda environment, the partitioning instructions downloaded with the kickstart from cobbler appear to simply not be applied. Then /mnt/sysimage is not mounted, the logs are not copied to /mnt/sysimage/root and the installation stalls due to the anamon

I'd like to save some calculation outputs as a pdf, to incorporate with others in a document. I've tried pdf("filename") name_of_object_to_output dev.off() but it doesn't seem to work, appears that this pdf function is for graphics? Is there a way to output numerical objects to pdf? Thanks J Dr. Jim Maas University of East Anglia

I'm attempting to install and run a program called ACSL (advanced continuous simulation language) on wine. So far the closest I've got is by installing Wine 20050725 on my Ubuntu (Debian) Linux by using the latest wine-config-sidenet-1.8.6 which appears to install ok and then installs the software ok. However when I try to run it using wine acslX which should start it I get lots of code

I can not understand why this fails > > faicoutput2 <- list(stuff21 = as.numeric(faicout$coefficients[2]), + stuff31=as.numeric(faicout$coefficients[3]), + stuff41=as.numeric(faicout$coefficients[4]), + stuff32=(stuff21-stuff31), + stuff42=(stuff21-stuff41), +

Simple one, have read and googled, still no luck! I want to create several empty vectors all of the same length. I would like multiple empty vectors (vec1, vec2, vec3) and want to create them all in one line. I've tried vec1,vec2,vec3 <- vector(length=5) and c(vec1,vec2,vec3) <- vector(length=5) and several other attempts but nothing seems to work ... suggestions? Thanks Jim

Is there a way to convince R to create a character vector without using the quotes? This works ex1 <- c("first","second") but when I try this it doesn't ext <- as.character(c(first,second)) it complains. I have many variables to put into character vectors so dispensing with the quotes would be useful. Thanks Jim =============================== Dr. Jim Maas

I'm trying to work out the simplest way to remove the upper and lower quantiles, in this case upper and lower 25% from an array. I can do it in two steps but when I try it in one, it fails. Is there something simple missing from my syntax or are there other simple elegant way to accomplish this? Thanks J > i <-1:20 > i2 <- i[i<quantile(i,.75)] > i3 <-

If possible I would like to combine two different character arrays in combinations Array1 <- c("height","weight","age","sex") Array2 <- c("trt0","trt1","trt2") I would like to combine these two character vectors to end up with such ... Array3 "height.trt0.trt1" "height.trt0.trt2"

I'm using the range command to get the minimum and maximum values of an array as in x <- range(array_y) which gives me two values such as [1] -2 9 I need to be able to test if this range of values includes a third value. For example I'd like to query 1) does the range of -2 to 9 include 3, answer TRUE 2) does the range of -2 to 9 include -6, answer FALSE? All values could be

I found a form of the if statement that works but it is very long. I'm attempting to check the value of of two different variables to see if they evaluate to either of two different values, which will result in a division by 0 in the final equation. This first if statement works for me _______ if ((x0.trial01 == 0.0)||(x0.trial01 == npt01)||(x1.trial01 == 0.0)||(x1.trial01 == npt01))

I get a list object from an iterative function. I'm trying to figure out the most efficient way to calculate the mean of one element, across all components of the overall list. I've tried output <- mean (listobject[[1:5]]$element) to get the mean of "element" in the first five components? It doesn't like the $. I'm suspect one of the "apply" functions

I have a data.frame "e" and would like to extract the 23rd column, remove any NA's and then remove any values >= 30. I can do it in steps such as this but have failed to figure out how to do it in a single line .... any suggestions? first <- e[,23] second <- first[!is.na(first)] third <- second[second<=30] thanks a bunch J -- Dr. Jim Maas University of East

Could anyone give me some clues as to the best way to debug this error message? I think it is from the passing of variables back to R from the jags function which does Bayesian fitting. The curious part for me is that the error messages seem random, yet the input data are always the same. Any suggestions most welcome. Thanks J Compiling model graph Resolving undeclared variables

Is it possible to send data from an executing R script, to external R script files, on linux in this case, get that external R script to execute, and pass results back to the central script? If so what commands should I be looking at? I've googled for R and external, stuff like that but no luck. The reason for the question is that I need to generate simulation data, then perform several