similar to: script question

In a context where exceptions are caught, I ran the fragment: cerr << "allocating" << endl; char* arr[100]; for (int jj = 0; jj < 10; ++jj) { cerr << "jj = " << jj << endl; arr[jj] = new char[2000000000]; sleep (30); } sleep (10); for (int jj = 0; jj < 10; ++jj) delete[] arr[jj]; cerr

Hi again everyone I have an arbitrarily dimensional array "a" and a list "jj" of length length(dim(a)). The elements of jj are vectors of indexes. How do I use do.call() to extract a[ jj[[1]], jj[[2]], jj[[3]], ...] ? Toy example follows: a <- matrix(1:30,5,6) jj <- list(5:1,6:1) I want the following a[ jj[[1]],jj[[2]] ] How do I do this? OBAttempts:

Hello, I am trying to vectorize the following loop but the vectorizer says: "Found a possible write-write reorder" and does not vectorize. Why? for (j=0; j < 8; j++) { jj = j << 3; m2[j][0] = diff[jj ] + diff[jj+4]; m2[j][1] = diff[jj+1] + diff[jj+5]; m2[j][2] = diff[jj+2] + diff[jj+6]; m2[j][3] = diff[jj+3] + diff[jj+7]; m2[j][4] = diff[jj ] -

Regardless of which version -- 1.1.1 or 1.2.0 (2000-11-27) -- with a fresh "directory" (i.e. no .RData), I am getting an extremely weird result. R : Copyright 2000, The R Development Core Team Version 1.2.0 Under development (unstable) (2000-11-27) > jj _ seq(0.05,0.95,by=0.002) > sum(jj==0.75) ## WRONG ANSWER [1] 0 > 0.05 + 350*.002 ## Double check that 0.75 is in jj [1]

Hi there, I am trying to understand how AliasAnalysis works out in LLVM. I used the following simple test-case (test4.c): -- void test() { int *jj, *kk; int aa = 100; jj = &aa; *jj = 300; } int main() { test(); return 0; } -- Then I did "llvm-gcc -emit-llvm -c -o test4.bc test4.c" to get bc. I tried the following 2 ways to get what I expect to get as

Hi I have a factor 'f' and a named list 'jj'. I want names(jj) to match up with levels(f). How do I use levels(f) to access elements of jj? > f <- factor(c("pigs","pigs","slugs")) > f [1] pigs pigs slugs Levels: pigs slugs > > jj <- list(pigs=1:10,slugs=1:3) My attempts to produce jj$pigs all give errors: >

Hi how do I extract those components of a list that satisfy a certain requirement? If jj <- list(list(a=1,b=4:7),list(a=5,b=3:6),list(a=10,b=4:5)) I want just the components of jj that have b[1] ==4 which in this case would be the first and third of jj, viz list (jj[[1]],jj[[3]]). How to do this efficiently? My only idea was to loop through jj, and set unwanted components to NULL,

I have a small home network with server and 5 clients all on an internal LAN with private IPs. Samba, Version 4.7.6-Ubuntu, file sharing is not working on the server for any of the 5 clients. I have tried both mount.cifs and smbclient. The same errors are thrown in the server's samba logs for all connection attempts, regardless of how the client tries to connect: getpwuid(1000) failed,

Hello everybody I'm using contour() to draw streamlines of potential flow, eg jj <- seq(from= -4, to=4,len=20) jj <- outer(jj,jj,function(x,y){x})+1i*outer(jj,jj,function(x,y){y}) f <- function(x){x^2} contour(Im(f(jj)), nlevels=44 , labels="") How best to put arrows on the contour lines to show the direction of flow? (ie I want contour lines looking like

On 07/01/15 10:51, Jason Long wrote: > Thank you. > I changed my "krb5.conf" as below : > > > [logging] > default = FILE:/var/log/krb5libs.log > kdc = FILE:/var/log/krb5kdc.log > admin_server = FILE:/var/log/kadmind.log > > [libdefaults] > default_realm = JASONDOMAIN.JJ > dns_lookup_realm = false > dns_lookup_kdc = true > ticket_lifetime = 24h

On 06/01/15 06:17, Jason Long wrote: > Thanks. > My domain name is "jasondomain.jj" and backend is "jasondomaini". No, your realm name is "jasondomain.jj" and it would seem that your domain name is "jasondomaini", the domain name can also be known as the 'workgroup' name. Set smb.conf to match this: [global] workgroup =

Hi Eli, thanks for the answers helping out. I tried to understand further - got another example: void test() { int *jj, *kk; int aa = 100; jj = &aa; *jj = 300; kk = jj; *kk = 400; } int main() { test(); return 0; } bc looks like the following (only test() part) define void @test() nounwind { entry: %aa = alloca i32 ; <i32*> [#uses=2] %kk =

Hello everyone I am trying to get one of my packages through R's QC. The package is clean for me under R-2.4.1, R-2.5.0, and R-devel, but Kurt gets > > * checking R code for possible problems ... WARNING > hypercube: no visible binding for global variable ?f? Function hypercube() [cut-&-pasted below] is intended to return an adjacency matrix for an n-dimensional

On 05/01/15 11:09, Jason Long wrote: > > > Thank you. > > My Windows is Windows server 2008 R2. > About realm name, My domain name is "JASONDOMAIN.JJ". > My Windows not have any Workgroup Name. It is Domain. > > > Thanks > > > > > On Monday, January 5, 2015 1:05 AM, Rowland Penny <rowlandpenny at googlemail.com> wrote: > On 05/01/15

On 05/01/15 07:02, Jason Long wrote: > Thanks a lot. > I changed the below lines to correct domain name : > > idmap config JASONDOMAIN : range = 10000-999999 > idmap config JASONDOMAIN : schema_mode = rfc2307 > > and after join, the command "net rpc testjoin" show same error : > > Unable to find a suitable server for domain JASONDOMAINI > Join to domain

Hi I am having difficulty with apply(). I want apply() to return a matrix, but sometimes a vector is returned. Toy example follows. Function jj() takes a couple of matrices m1 and m2 as arguments and returns a matrix with r rows and c columns where r=nrow(m2) and c=nrow(m1). jj <- function(m1,m2,f,...){ apply(m1, 1, function(y) { apply(m2, 1, function(x) { f(x, y, ...)

On 09/01/15 08:40, Jason Long wrote: > Thanks. > I'm confused. Can I paste "set" command on windows for you? > "jason" account is administrator and can join and dis-join any computer. > > Cheers. > > > > On Wednesday, January 7, 2015 2:59 AM, Rowland Penny <rowlandpenny at googlemail.com> wrote: > On 07/01/15 10:51, Jason Long wrote:

Dear All, I try not to bump too much, but I just tried Ubuntu 18.04, and it is not in repo and I still do not see any PPA available. If it would help, I can spend the time to explain why I believe it helpful to install using a command rather than webbrowser, but I think this is already understood why helpful, but it seems there is just a technical tricky problem to solve to implementation. Thank

Buen día a todos, Agradezco su ayuda con lo siguiente: Tengo 100.000 registros con nombres de personas con su respectivo número de documento, quiero identificar casos que tengan un porcentaje de igualdad alto, no del 100% porque ya esos los tengo identificados, sino casos como por ejemplo: Nombre: Juan Pérez Documento: 123456789 Nombre: Juan Pérez Documento: 1234056789 Este caso sería una

dear all, I'm building new dataframes from bigger one's using e.g. columns F76, F83, F90: JJ<-data.frame( c( as.character(rep( gender,3))) , c( F76,6- F83, F90) ) Looking into JJ one has: c.as.character.rep.gender..8... c.6...F73..F78..F79..F82..6...F84..F94..F106..F109 1 w 2 2 w